Coefficient of restitution for an elastic collision in 1 dimension

[@andrewciricillo9726]

Thank you for showing the manipulations starting from final energy=initial energy, using conservation of momentum equation to eliminate the masses, and then the difference of two squares yielding the final equation for e. Everywhere likes to show off e and the final equation, was pretty tough to find someone showing the manipulation for 2 bodies resulting in the final equation.

[@DrBenYelverton]

Glad it was helpful! I agree, knowing that e = 1 for an elastic collision is a useful trick but it's important to know the derivation too.

[@hilmikhoirulloh9389]

Terima kasih pak ben anda telah membantu saya dalam menjawab soal dari dosen mekanika klasik. Semoga hari mu bahagia selalu pak

[@FelpSbtw]

nice!

[@Tatateye]

THANK YOU

[@lilith9556]

Can you solve that 1- For the elastic collision, write the following a- The energy balance equation b- The momentum balance equation c- The value of energy loss factor Q d- The value of coefficient of restitution €

[@peterpoli2839]

my DOS told me off using this in 1A natsci lmao

[@DrBenYelverton]

Fair enough, it's a useful result but I would also advise students not to use it without a derivation for exam purposes (since it's not fundamental in the same way as conservation of momentum and energy)!

[@peterpoli2839]

@@DrBenYelverton you’re better off doing zero momentum frames, you skip simultaneous equations

[@DrBenYelverton]

@Peter poli I don't think we can ever fully avoid simultaneous equations but the ZMF can at least remove a degree of freedom by letting us consider momentum in just a single direction even for 2D collisions.

[@peterpoli2839]

@@DrBenYelverton at least the simultaneous equation that we always do is simpler