Colligative Properties Explained

[@ChemAcademy]

At 15:10 I meant to say and write -0.9 degrees celsius and not 0.9 degrees celsius.

[@ChemAcademy]

Thanks for pointing that out Donald.

[@jeromecolico3536]

Chem Academy , i thought so , thats why i looked in the comment section

[@iantharaka4149]

The best video I've come across on KZbin. Thank you so much. You are a much better teacher than my professor in college. Excellent explanation

[@victoriaolukayode6194]

I love love love the way you explain and I totally totally understand it all. I am soooo happy. God bless you and thank you.

[@Mayowa1994]

Definitely better than Khan academy's explanation

[@ChemAcademy]

Thank you!

[@firecollection]

It's hard to figure out and understand __ Thank you, Mr Chem, now i know how to solve this problem for my next exam :)

[@ChemAcademy]

glad it helped

[@rodthegreat5083]

Thank you sooo much. I couldn't understand this in class and now totally get it. TRULY AMAZING!

[@cristinachin9584]

You have such a gift for explaining otherwise confusing concepts. I value your videos soo much!!

[@donaldmorris8817]

it's -0.9 for the first freezing point depression calculation example

[@alexgalcoro6787]

Me ayudo mucho, muchas gracias, muy practico y rápido, toda una clase en un video, saludos de México

[@judyracheku]

Thanks for this video now I clearly understand colligative properties I was struggling 🤘❤

[@ratgermss]

This is very lit. Stay lit and keep these vids going.

[@camilorubio388]

Muchas gracias. excelente explicación.

[@riogrl324]

Finally someone who can explain this in a way that is understandable 😂🤣😂

[@MZ-lm5ei]

very helpful! thank you very much for this simple explanation :)

[@vgtoasty]

Good video, helped with a chem lab.

[@campbeja001]

More correct: Colligative properties depend on concentration of solute but don't depend on identity of solute not "type" as you wrote since ionic compounds ionize (i > 1) and covalent compounds do not (i=1)

[@noura9929]

thank you so much < this helped me a lot

[@cold-dreamer5736]

Dude it was awesome helped me a lot, thanks

[@natalierivas6285]

Much appreciated @1am!

[@lucasramirezvideos]

This helped a ton. Thank you

[@ayshasiddika5988]

thank you. this was really helpful

[@shamohabibi]

Thank you so much it really help me

[@ChemAcademy]

Shamila Habibi I am glad it helped you out! Stay tuned...more vids coming.

[@iqraurooj6516]

on start of this lecture; You said that THEY DONT DEPEND ON THE TYPES OF CHEMICAL SPECIES PRESENT. and then you explained that lowering of v.p would be greater in case of sugar, if 1 mole each of sugar NaCl and K2S.

[@TheSharingarMaster]

They depend on the molar CONCENTRATION of the chemical species present not the the type or the nature of the solute. Let me explain: 1 mole of C12H22O11(Sugar) dissolves in water to give 1 mole of dissolved sugar. (it does not dissociate or seperate) .1 mole of NaCl give you 1 mole of Na and 1 mole of Cl in solution to a total of 2 moles of ions. 1 mole of K2S dissolves in water to give 2 moles of K ions and 1 mole of Sulfur to a total of 3 moles of ions. 3>2>1 so K2S provides a greater depression(lowering) in freezing point and a greater elevation in Boiling point. Balanced equation of dissociation of K2S: K2S ---h20---> 2K (aq) + S (aq) مفهوم انشالله :D

[@sarahward5974]

Very helpful, thank you :)

[@sanegirl2]

I wish you were my teacher

[@jeanatienza1247]

Thank you so much, Sir!

[@jerlyndenoya907]

Why is 0 deg C minus 0.9 deg C equal to 0.9? Is it not negative 0.9?

[@nourhaydar8848]

If the freezing point decreases doesnt that mean that there is more energy released?

[@opus3415]

9:00 why are finding Boiling point using the formula of elevation in boiling point?

[@diegoandradex12]

Thank you so much!!!

[@sakinilla5760]

How can you express enthalpy change for chemical reaction?

[@sakinilla5760]

What happen to the boiling point of water when sucrose is added?

[@greyakatsukiz]

thank you soo much.

[@xxTrumpetBoyxx]

Great thank you

[@sudiXP]

Thank you.

[@leon_oby]

15:12 0-0.9 is -0.9

[@greentellus5458]

Good

[@bhavanisri191]

thank you sir

[@saibutanitoluwa3306]

I think the last answer is meant to be -0.9°©

[@topten7106]

where I downloade your ppt.

[@andreenriquez4817]

thanksz

[@calebarulandu3068]

The 1st freezing point problem should be -0.9 C and not 0.9 degrees.

[@mmoose3673]

Alright, but this doesn't explain why the boiling point would change, only that it does and that it depends on moles of dissolved particles

[@mmoose3673]

I did a bit of research. Turns out that, on the surface of the water, the more room taken up by the solute, the less room for the water to enter the gas phase. So at each temperature less vapor is coming off the liquid and the vapor pressure is lower. It then requires a higher temperature to bring the vapor pressure up to match the atmospheric pressure.

[@susalulu6578]

thak you

[@dedioraemiliano4649]

Why do you pronounce water like WARIC

[@benjaminswrld]

Z

[@venkataramanapolireddy8284]

Sir please pronounce some what clearly please