one of the most beautiful mathematics lectures I have ever seen in my life...my heart is jumping with joy
@Flopsaurus9 жыл бұрын
To clear something up to others who might have been confused, at 17:13, where he states slope = ux, that x is actually a subscript. He is not multiplying. That's the partial derivative of u with respect to x.
@MizuHakuryu7 жыл бұрын
Jesusdragon737 thanks!
@PurusharthSaxena4 жыл бұрын
Thanks. Got confused there for a second
@mohammedouallal23 жыл бұрын
Slope is derivative
@Elianath12 жыл бұрын
Your approach to teaching this material really helps me understand and accept the assumptions being made to derive the equations. I am having a rough time in my PDE class right now because there is so much math (I am an engineering student) that I just can't symbolically follow everything - let alone remember many of the theorems that I learned way back in Calc 3. Thanks for posting these videos...I hope you will continue to do so!
@LeavingCertMaths12 жыл бұрын
I have watched the derivation on the mechanics course by MIT. The reason given for constant tension there is that a tiny mass element could be given high acceleration if the 2 tension forces acting on it are unequal. You brought up a few points not mentioned there, so I found your approach helpful.
@SM_Price5 жыл бұрын
I went through five different videos before finding this one. Your video made the derivation intuitive and simple.
@vasanthrajaram12417 жыл бұрын
this video was just beautiful.I have many of wave equation derivation video,but none of them gave an intuition to wave equation like this
@chewie787674 жыл бұрын
holy moly the textbook did not make sense at all but your video got me to understand it . THanks
@taojiang10949 жыл бұрын
marvelous understanding of PDE, really useful to rookies like me, thanks so much!!!!!
@LeavingCertMaths12 жыл бұрын
There is a derivation here at 50:00, youtube lec 7 vibrations and waves. He says that the tension is the same (to a very good approximation) if the amplitude is small, which I do not understand. I think he mentions the constant string tension idea that I mentioned earlier in another video on masses on pulleys. However, I fully understand your explanation.
@johnholme7834 жыл бұрын
Thank you for taking the time to produce this video, I now understand my textbook derivation. Simple no nonsense explanation explanation!
@1aMattes11 жыл бұрын
i had no pdes yet (bachelor thesis) but still i do need them as a part of electromagn. wave theory, you help me a lot!!
@ParvaChhantyal11 жыл бұрын
Hi @16:16, can you explain me how you got second line equation after putting lim h=0 please? bit confused in that one. Thanks
@kaustubhsinha5057 жыл бұрын
In differential Calculus, the derivative/ change in a function F(x) to F(x+h) over a given period of time T, is given by the following relation: limit of h tending to 0 d/ dT of F(x) (or rate of change of F(x)) = ( F(x+h) - F(x) )/ h Note that I wrote of as putting brackets would be wrong notation as I cannot represent it in text here. commutant has done the same with the function T here, reducing it to a differential form from a limit change form.
@HotPepperLala7 жыл бұрын
f'(x) = lim_h->0 [f(x+h)-f(x)]/h. Let f(x) = g(x)h(x).
@daohung11127 жыл бұрын
+rinwhr hi
@daohung11127 жыл бұрын
+Hung Dao you have any physics maths boong?
@michellejingdong Жыл бұрын
Thank you so much for the video! It explains so clearly! All the assumptions here had been emphasized!
@sova-vlog5 жыл бұрын
I thought that the external force that you include in the equation of motion should be the weight of the string, mg. However, when h tends to 0, mg tends to 0 either. Thanks for this great lecture prof
@ArvindSastry9 жыл бұрын
Thank you very much! you really explained the wave equation (and the assumptions) very well!
@fredericmoresmau43038 жыл бұрын
Why can one always assume that the theta-angle is always small ? Can't there be bigger vibrations happening ? What happens then ?
@daohung11127 жыл бұрын
t iu very short, h iu very small, theta iu very small
@mohammedouallal23 жыл бұрын
Taylor expansion
@mohammedouallal23 жыл бұрын
Sine of theta is approximated to theta (by Taylor expansion) due to very small vibrations. As he approximate cosine of theta to 1. Then, simple trigonometry, theta is equal to u_x
@Pro-dq9ey3 жыл бұрын
The 3rd assumption saying it is small vibration, i.e. amplitude of vibration is small, i.e. theta is small angle, in which case sin(theta)≈tan(theta)
@mohammedouallal23 жыл бұрын
Impressive video! I have one remark. I take it you considered the area of string equals to 1....
@jolez_48694 жыл бұрын
At around 8:30 you say that because the vibrations are small the length of the curve is approximately the same to that of the interwall. However, isn't it true for all vibrations due to assumption 1? It being that all motion is only vertical.
@LeavingCertMaths12 жыл бұрын
Perhaps you could expand a bit on the idea of constant tension in a string.
@kaustubhsinha5057 жыл бұрын
Halo, at 22:20 just to keep the facts right, one cannot have a completely elastic string which also has a constant mass density (ie. constant T and rho), it is not possible in the physical universe.
@MrSakriwedg11 жыл бұрын
Where I can find the derivation with the x displacement taken into account?
@wargreymon2024 Жыл бұрын
It's the best one on the topic so far, but I must say I cannot understand the assumption on small vibration, the whole purpose of wave equation is to understand the vibration, the wave equation should explain large vibration, not neglecting it.
@roomking-petch81688 жыл бұрын
Thanks a lot. Your videos are so great and help clarify many many points.
@SraigiusLT12 жыл бұрын
loved it, explained very good. i'm inspired by You,. (Lithuania loves you)
@LawrenceUdeigwe9 жыл бұрын
Great lecture !!! One quick question though: If you assumed that theta is close to zero (around 18:40), why would your assumption affect only cos(theta) and not sin(thata). In other words, one could also have assumed that since theta is going to zero, sin(theta) is approximately equal to zero, which will not be good. please help.
@Flopsaurus9 жыл бұрын
+Lorens Chuno Approximating a small number with zero is quite different from approximating a number close to 1 with 1. Typically, when theta gets small, sin(theta) is approximated as theta, and cos(theta) is approximated as 1. You can multiply a number by 1 and generally get something close to multiplying it by cos(tiny theta). However, if you multiply a number by 0, you will always get zero, so you will not generally get something close to multiplying it by sin(tiny theta).
@alokrajawat76199 жыл бұрын
Thank you very much! you explained the wave equation very well!
@Elianath12 жыл бұрын
Also, can you recommend any textbooks or materials that presents information the way you do? I have gotten Farlow and Strauss and our class book is Zauderer. I find Zauderer's book to be useless for me. My professor teaches with Strauss basically and that is even hard for me to follow. Farlow is okay sometimes... Thanks again
@lukestuemke544511 жыл бұрын
When summing the forces in the y (or u) direction, I'm confused why the string's weight was not taken into account. Should we not also be adding -rho(x)hg to the left-hand side? T(x+h,t)sin[theta(x+h, t)] - T(x, t)sin[theta(x,t)] - rho(x)hg = rho(x)hu_tt
@Michallote2 жыл бұрын
Yes those are external forces. What would happen is that you would do the limit as usual as dividing by h cancels out for the weight term, and it also doesn't affect the definition of derivative. Meaning you would end up with T u_xx - rho g = rho utt To what u_xx = c^2 utt + c^2 g
@Triple9MX4 жыл бұрын
How do I add damping to this derivation?
@cmdrblahdee11 жыл бұрын
Lol, not used to this notation... was wondering why the slope was U times X for several minutes before I realized you meant the derivative /w respect to X
@Filip67543 жыл бұрын
Doesn anybody know a good source where this derivation is used? I'd like to use it in my thesis, but the teachers aren't quite ready to accept a youtube video as a valid reference.
@tallblondephysicist11 жыл бұрын
Fantastic video, thanks a lot.
@sunaba297110 жыл бұрын
Please can I get a project topic on PDE from you for my Msc project
@mrmaaza12311 жыл бұрын
Great video ! Keep up the good work !
@Chausies712 жыл бұрын
Thank you so much Rob!! I love these (and you to a degree...
@HotPepperLala7 жыл бұрын
So the wave equation is just one big assumption..
@davidsonjoseph89916 жыл бұрын
Camel with SunGlasses but it works! 😎
@amalguptan67165 жыл бұрын
Reasonable assumptions
@rodrigobispo9 жыл бұрын
Thank you! You explained this very well
@luisirisarri10854 жыл бұрын
But c has not dimensions of velocity ? Thank u very much
@cristophorbutuc-mayer66498 жыл бұрын
Hi! quick question.. what's the point of taking c^2 why not just leave it as c?
@ahmedImam8 жыл бұрын
see the previos video . PDE 7
@ericgilkey35497 жыл бұрын
From a strictly mathematical perspective, c^2 is technically just some coefficient "a". However, if we want to interpret "a" as a velocity, we need to square it to make the units work out (m^2/s^2). Thus, u_tt (m/s^2) has the same units as c^2*u_xx (m^2/s^2*m/m^2 = m/s^2).
@diwakarsaran39784 жыл бұрын
Thank you very much Sir!!
@OfficialEnman11 жыл бұрын
Thank you for making these videos!
@lcfaskys67119 жыл бұрын
Fantastic video, thanks a lot!
@muhaha71411 жыл бұрын
I just dont get the bit where mass is the density times the length. Isnt density the mass per unit volume? Love the videos btw :D
@rutger500010 жыл бұрын
Yes, but volume isn't necessarily length*width*hight. Volume is depending on your space. In 1 D volume is the same as length, in 2 D volume is the same as surface, in 3 D (real space) volume is what you know it to be. There's volume in all D, but it won't be intuitive anymore. In any case it's very normal to talk about line density (mass per length) or surface density (mass per area)
@alexleviyev11 жыл бұрын
You are amazing...
@daohung11127 жыл бұрын
good video. thanks
@laneellisor71133 жыл бұрын
Thank you!
@LeavingCertMaths12 жыл бұрын
Thanks.
@davidkwon18724 жыл бұрын
Thank you!!!
@skrafi429210 жыл бұрын
good thankyou sir
@jieunboy3 жыл бұрын
Thx
@michaelsun79683 жыл бұрын
my mind is blown
@veronicapaul67684 жыл бұрын
good
@crystalc1ear7 жыл бұрын
are you canadian
@davidtan89039 жыл бұрын
I wish I watched this video when I was a sophomore
@panazilian11 жыл бұрын
thankyou!!
@biohoo2211 жыл бұрын
has anyone ever been so far as decided what to do more like?
@angiefan24814 жыл бұрын
Do physicists just get to add assumptions every time the math gets ugly?
@ankurc6 жыл бұрын
let us assume a spherical cow lol assumptions assumptions and assumptions...but still beautiful.....dont have enough words to thank you
@Postermaestro6 жыл бұрын
o boi
@Pervertlegenge10 жыл бұрын
hahaha....this is clever...thanx
@DelphianSociety11 жыл бұрын
you don't clear by this video? lmao
@scholar197211 жыл бұрын
Sir, You tends to be too many assumptions.
@balaportejean70155 жыл бұрын
thx bro Jesus loves you Believe in him and repent bro