Complex Analysis 26 | Keyhole contour

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The Bright Side of Mathematics

The Bright Side of Mathematics

Күн бұрын

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This is my video series about Complex Analysis. I hope that it will help everyone who wants to learn about complex derivatives, curve integrals, and the residue theorem. Complex Analysis has a lof applications in other parts of mathematics and in physics. In particular, we can solve real integrals by going to the complex realm.
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Пікірлер: 23
@idk-vj8tz
@idk-vj8tz Жыл бұрын
Great work! This helps one see beyond textbooks.
@brightsideofmaths
@brightsideofmaths Жыл бұрын
Glad you think so! :) And thank you for your support!
@Ghetto_Bird
@Ghetto_Bird 8 ай бұрын
Man you are such a legend, as crystal clear as always!
@brightsideofmaths
@brightsideofmaths 8 ай бұрын
Thanks! I appreciate that! :) And thanks for the support!
@synaestheziac
@synaestheziac 2 жыл бұрын
Can’t wait for Cauchy’s formula!
@souravdutta8630
@souravdutta8630 Жыл бұрын
Superb understanding sir
@youteubakount4449
@youteubakount4449 2 жыл бұрын
Amazing series, thank you!
@brightsideofmaths
@brightsideofmaths 2 жыл бұрын
Glad you enjoy it!
@Ren-wi1gf
@Ren-wi1gf 2 жыл бұрын
Thank you so much for having these series m(__)m I wouldn't otherwise have such a good master explain these concepts while trying to self study
@individuoenigmatico1990
@individuoenigmatico1990 29 күн бұрын
The proof works exactly the same if g is holomorphic in a disk D-{z0} where z0 is not necessarily the center of the disk, am I right?
@skillick
@skillick Жыл бұрын
Why are we justified in taking the limit delta --> 0? I understand the result flows nicely when we do, but are we indebted to the limit we took somehow? Thanks for your videos!
@brightsideofmaths
@brightsideofmaths Жыл бұрын
What do you mean by "justified" here? The limit exists and we can do the calculations. Do you prefer not taking the limit but doing it another way?
@skillick
@skillick Жыл бұрын
@@brightsideofmaths I mean in the sense of why is it useful to see what happens to this shape in the limit if we are trying to say something about the shape itself? I appreciate your response, I think I have a deeper misunderstanding I need to address before moving on!
@brightsideofmaths
@brightsideofmaths Жыл бұрын
@@skillick The delta was a helping variable from the beginning. So we want to get rid of it in the end.
@skillick
@skillick Жыл бұрын
@@brightsideofmaths Thank you!! That caused the penny to drop for me!
@kayebennett7867
@kayebennett7867 2 жыл бұрын
Why do we have to consider some non-zero delta and take the limit? Is not possible to choose directly delta equal to zero at the beginning?
@brightsideofmaths
@brightsideofmaths 2 жыл бұрын
With a zero delta, we cannot apply Cauchy's theorem as we have learnt in the former videos. I wanted to show a straightforward proof of this important fact :)
@kayebennett7867
@kayebennett7867 2 жыл бұрын
@@brightsideofmaths But why exactly we cannot use the version of the previous part? If delta is zero, we are still able to construct the polygon paths, right?
@brightsideofmaths
@brightsideofmaths 2 жыл бұрын
@@kayebennett7867 Yeah but the region is not the correct one then.
@paul_tee
@paul_tee 2 жыл бұрын
Whoa is this a face reveal
@brightsideofmaths
@brightsideofmaths 2 жыл бұрын
It's a least my face :D
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