Complex Analysis L06: Analytic Functions and Cauchy-Riemann Conditions

  Рет қаралды 51,140

Steve Brunton

Steve Brunton

Күн бұрын

This video explores analytic complex functions, where it is possible to do calculus. We introduce the Cauchy-Riemann conditions to test for analyticity.
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This video was produced at the University of Washington

Пікірлер: 36
@yigitrefikguzelses291
@yigitrefikguzelses291 Жыл бұрын
You are great at these videos, you are really helping me improve my calculus. And i am at highschool its really hard to find stuffs that i can understand with my limited knowledge... so i wanted thank you ❤
@annanor9009
@annanor9009 Жыл бұрын
Thank you so much for this great lecture and for including your own mistakes along the way. I struggled in math in high school and so gave up on math/science as soon as I was able to, and only decided to try again in my late twenties; after a few years of playing catch-up, I just started a degree in engineering. I spent so long thinking I was just "not a math person" that even having accrued plenty of evidence that I can in fact learn math if I try, it's still easy to assume everyone fundamentally has it together except for me and I'm the only one falling into "stupid" holes all the time. 21:15: would love a primer on the concept of "measure" some time-- I first encountered it when I ended up teaching the lab for the precalculus catch-up class not too long after taking it myself, and found myself saying something similar about an example without thinking about it-- "if I randomly chose a function, it probably wouldn't be the right one... wait, huh... can I say that? what does 'probably' even mean in this context?"
@danielhoven570
@danielhoven570 Жыл бұрын
Fantastic series! needed to brush up on this for a mechanics book I'm working through.
@treenabalds
@treenabalds Жыл бұрын
These videos have been awesome, so far. Your approach to the topic is a little different from previous classes I've taken, and this is actually perfect because it's helping me understand the ideas in more nuanced ways than I had before. Thanks so much!
@milakshashaey2957
@milakshashaey2957 6 ай бұрын
You gives your best in teaching, awesome.. thank you sir!
@samvelsafaryan4698
@samvelsafaryan4698 Жыл бұрын
Thank you very much. It's very simple tutorial but very hard branch of math.
@individuoenigmatico1990
@individuoenigmatico1990 8 ай бұрын
1) The principal logarithm function is discontinuous on the entire negative real axis, not just on z=0 hence it is not analytic there. But it is analytic everywhere else. 2) A complex function is analytic if and only if it is R²-differentiable and its partial derivatives verify the Cauchy-Riemann equations.
@curtpiazza1688
@curtpiazza1688 6 ай бұрын
Wow! This is GREAT! This is a whole new world for me! 😂 ❤
@valentinkadushkin324
@valentinkadushkin324 Жыл бұрын
wow! this is a gem of a video
@Hank-ry9bz
@Hank-ry9bz 5 ай бұрын
25:00 why expand in a first order taylor series? Wouldn't that ignore higher terms that could affect the result?
@gabrielluiz1768
@gabrielluiz1768 2 ай бұрын
great lecture
@fzmlnre
@fzmlnre 19 күн бұрын
7:45 how it can delta z bar
@lazaredurand6675
@lazaredurand6675 5 ай бұрын
At 25:35 When you say "you ca pause and this is what you get..." This is really really not evident for me. What mean to expand something out in a first order serie?
@shashwatmangulkar1107
@shashwatmangulkar1107 5 ай бұрын
how does z/2 have two solutions. isn't it a one-one function
@shashwatmangulkar1107
@shashwatmangulkar1107 5 ай бұрын
ohh you meant z^1/2 .. then it's True.. Excuse Me
@krzysztofciuba271
@krzysztofciuba271 Жыл бұрын
A question/suggestion: why do U treat e^z analytic but z^n (only for n=1,2,..) analytic without 0? A practical question in order to reveal some Global Idiocy in physics just by using a complex plain and contour integral as INDEPENDENT from the "path" in such a "perfect/divine" plane - there are just other just real number analytic and geometric solutions but this one is best simple (for the path in Minkowskian space-time)
@ucas5301
@ucas5301 Жыл бұрын
Thanks
@broor
@broor Жыл бұрын
19:40 z conjugate is not cuspy at all? it is equivalent to f(x,y) = x - yi which has real part x and imaginary part -y which is not at all cuspy. what do you mean?
@starsun7455
@starsun7455 11 ай бұрын
I bet prof.Brunton lefthanded.
@edwardhuff4727
@edwardhuff4727 11 ай бұрын
It's not the principle of the thing, it's who your pals are. And Riemmann is not your friend, he's some American who got his name mangled at Riker's Island.
@younique9710
@younique9710 5 ай бұрын
how is Z^2 a single valued? although Z^2 can be from +Z or -Z?
@hoseinzahedifar1562
@hoseinzahedifar1562 Жыл бұрын
16:29: 2(1/2), it is like platform 9(3/4)...😅😍, it is as like as this sentence: "your teaching style is like magic".
@amittksingh
@amittksingh 8 ай бұрын
Thanks for providing the necessary context. For Showing us non analytic functions also and putting a meaning around how rare analytic functions are.
@marc-andredesrosiers523
@marc-andredesrosiers523 Жыл бұрын
I don't recall ever seeing it in 25 years. It'd be nice to see the complex derivatives derived from the polar form. Express the Cauchy-Riemann conditions in polar form, or find an alternative set of necessary conditions that are more easy to express in said form. And, then come back to monomials.With the hope that infinite differentiability of analytic functions is easier to intuit in that form.
@ggrsvvrd2683
@ggrsvvrd2683 10 ай бұрын
He finds the Cauchy Riemann conditions in polar in the next lecture
@JAYasankarPillai7
@JAYasankarPillai7 Жыл бұрын
Couldn't find L04, and L05.....it would be great if they are uploaded. Anyways, thanks a lottttttttttttttttttttttttttttttttttt.
@erikgottlieb9362
@erikgottlieb9362 Жыл бұрын
Thank you. (Additional thanks for including example at end of presentation.)
@amrithmadhu1523
@amrithmadhu1523 2 ай бұрын
can someone explain why z^2 is single valued @2:52
@KhalidAlshumayri
@KhalidAlshumayri Ай бұрын
He said z^(1/2) not z^2.
@TheBonaparteReport
@TheBonaparteReport 4 ай бұрын
Fantastic! My interest in complex analysis was piqued by Roger Penrose’s road to reality, but unfortunately his writing is just too impenetrable for me. You present it in a far more easy to understand way.
@georgegoldmanonyidikachijo3784
@georgegoldmanonyidikachijo3784 8 ай бұрын
from my own evaluation of the cauchy reimann equatoin i got [u(∆x, ∆y) - iv(∆x, ∆y) ]/ (∆x + i∆y) is this the same with what you got?
@naturallyinterested7569
@naturallyinterested7569 Жыл бұрын
I thought the complex logarithm wasn't analytic on the negative real numbers? It's at least not continuous there. So shouldn't we need to remove (-inf, 0] from C?
@LeylaAbdulkadir-mq2xq
@LeylaAbdulkadir-mq2xq 8 ай бұрын
amazing video thankyou : lol it was stupid mistake
@rudypieplenbosch6752
@rudypieplenbosch6752 Ай бұрын
Great presentation thank for teaching us.
@Hank-ry9bz
@Hank-ry9bz 5 ай бұрын
i'm guessing D must be open?
@CraigMukwananzi-z2o
@CraigMukwananzi-z2o 13 күн бұрын
We want to learn to solve things not here you talk the whole video
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