Complex impedance, Low- and high-pass filters, Bode plots

  Рет қаралды 23,436

James van Howe

James van Howe

Күн бұрын

Пікірлер: 20
@Lexyvil
@Lexyvil 5 ай бұрын
Amazing explanation! Thanks. The Gain vs frequency graph makes a lot of sense now! It's just the connection I needed.
@qingdasoon9226
@qingdasoon9226 7 жыл бұрын
This analysis method is genius and simple to understand.
@olivierp8049
@olivierp8049 Жыл бұрын
At 27:50 shouldn't the complex conjugate be identical on numerator and denominator?
@sebastianrayonnixon7879
@sebastianrayonnixon7879 8 жыл бұрын
Clear Explanation. Thanks :)
@furgplay8698
@furgplay8698 4 жыл бұрын
Hello, what would be the impedance value if I will connect in series an 8ohms tweeter and the 1uF/400v capacitor to the amplifier. Can we use those theories that you are using? Thank you.
@Chachi0400
@Chachi0400 6 жыл бұрын
Fantastic! Thank you
@SnoozeDog
@SnoozeDog 5 жыл бұрын
at 27:09 to find magnitude, why arent gain terms squared?
@SnoozeDog
@SnoozeDog 5 жыл бұрын
also what happened to the j term in y value at 29:49
@astrogecko1650
@astrogecko1650 7 жыл бұрын
Awesome vid! But how do you actually know what the Bode plot looks like?
@jamesvanhowe1718
@jamesvanhowe1718 7 жыл бұрын
Sorry for delay in my replies. In one of my classes this term we are make Bode plots using a function generator, the circuit under test, and an oscilloscope. You can simply input sine wave of fixed voltage to the circuit and look at the voltage of the sine wave out, as well as its relative position in time compared to the input (phase). Keep the input voltage fixed and then take vout's and output phases for different frequencies. Voila! This is the long way to do it. There are analyzers that can do this for you. If you have a function generator that sweeps, you can use labview or an arduino board to make your own Bode plotter. You can also get an idea of what it looks like on the scope if you have a sweeping function generator with the scope on xy mode.
@ziedmekki6631
@ziedmekki6631 7 жыл бұрын
thanks a lot
@MrChannel221
@MrChannel221 6 жыл бұрын
Thanks!
@jiungchoi4213
@jiungchoi4213 7 жыл бұрын
at 24:28 why don't you just get the magnitude right away, 1/sqrt(1+(wRC)^2) using lZl=sqrt(x^2+y^2)
@jamesvanhowe1718
@jamesvanhowe1718 7 жыл бұрын
At this point in the video, we are not in the format (real part) + j*(Im part). Rigorously, we must be in this format in order to take the magnitude correctly. Certainly there are shortcuts you may be able to see/take that can work. However, for more complicated expressions, this shortcut can't be applied. It's very easy to apply the wrong shortcut to a more general complex algebraic expression and make a mistake.
@mthatshelwa
@mthatshelwa 7 жыл бұрын
incredible
@LunaMarlowe327
@LunaMarlowe327 7 жыл бұрын
Awesome
@LunaMarlowe327
@LunaMarlowe327 7 жыл бұрын
The most detailed one I have seen
@justedms53
@justedms53 6 жыл бұрын
But practically there is such thing as ESR , ESL etc
@yanalishkova1873
@yanalishkova1873 8 жыл бұрын
Thank you! ][=
@jamesvanhowe1718
@jamesvanhowe1718 8 жыл бұрын
Glad it could be of help!
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