Connected Particles on a rough inclined plane : ExamSolutions

[@reddress2200]

Thank you for your clear explanation. I am really struggling with the mechanics. It's immensely helpful to have your videos to refer to.

[@prochchhannomahmad8298]

Thank You very much. M1 has been the toughest for me in my A Levels. Your videos give me a lot of confidence.

[@ExamSolutions_Maths]

That's good - thanks.

[@kellywhybrow167]

i did really well at maths at GCSE but when it came to Alevel i felt useless. I got a U on mechanics 1 twice (dont ask how) and thought third time lucky, i think everyone lost faith, but finding these videos has helped so so much. Just recently got a B on my resit mock. so happy, going to keep practicing and watching these videos til I get that A! So thank you so so much, what you're doing is really great!

[@tabithasinclair6821]

how did you do?

[@sandras4805]

Thanks a lot!!!! I usually refer to your video's when it comes to revision. Clearly explained!

[@Kaineq1]

Mechanics today! Thanks for the videos, best revision at home ever. Good luck everyone

[@ALekz43]

great video, thanks a lot, only thing is, how would you go about working out the answers if the string was extensible and/or the pulley was rough? you would have more than 2 unknowns..?

[@votevimto]

You are the clearest teacher of Mathis

[@ExamSolutions_Maths]

Well done. Keep at it and I am sure you will get there.

[@alexc9476]

good video!

[@fusioncore9986]

thank you so much this helped me a lot i have my mechanics AS exam tomorrow wish me good luck

[@maggiej2590]

Thank you Sir, M1 seem much easier after watching ur videos!!

[@ExamSolutions_Maths]

Best wishes.

[@vinimani1047]

Watching from Kenya for my Architecture physics class.

[@kashoot4782]

How would you be able to tell which particle would move up or down for this? Is it just the masses?

[@arvin390]

It doesn't really matter which direction you pick, if you picked the wrong direction, you'd still get the same value for acceleration, just negative.

[@nonamekitty5]

why we didn't consider the normal reaction on the pully if it is inclined?

[@ExamSolutions_Maths]

That's good. No worries.

[@ExamSolutions_Maths]

@imdaark Thank you very much

[@JackMitchinson]

In OCR M1 would we ever be asked a question with a rough pulley or an extensible string?

[@votevimto]

*maths would you ever consider incorporating the ccea syllabus? It's very similar although there irate different moments questions. There's not much online for ccea and it would be fantastic if there was something like what you do, just a thought

[@theteacake]

many thanks for the video!

[@nurmustaqqim256]

What if the question asked find the friction if the system in statics equilibrium

[@youknow1858]

Thank u soo much

[@ExamSolutions_Maths]

You're welcome Kevin, glad you like it! Best wishes

[@westerlywind1035]

You cleared this up for me, thanks. I would donate, but I have no income.

[@ExamSolutions_Maths]

I would really appreciate that if you do. Thanks.

[@imdaark]

Amazing as always stuart

[@ALekz43]

ah ok that's good, these videos have helped so much, when I get the chance I will donate (Y)

[@adyansiraj8522]

I do not understand what u were on about when u said with sine you exclude the angle and with co sine you do not?

[@ExamSolutions_Maths]

Check this out www.examsolutions.net/tutorials/resolving-forces/?level=A-Level&board=Edexcel&module=Mechanics%20A-Level&topic=1632 I hope it answers your question

[@zahid4902]

thanks mate

[@sumithansuthaharan497]

how comes particle A uses the equilibrium method but for particle B you used f=ma ???

[@ExamSolutions_Maths]

Simply put, the sum of forces that are perpendicular to the motion of the particle is equal to zero.

[@ExamSolutions_Maths]

That's ok.

[@ExamSolutions_Maths]

Too difficult to go into here. You would not get a question like that at this level.

[@ExamSolutions_Maths]

It accelerated from rest.

[@ahmedswagb24]

I'm a little confused to where I might have went wrong. I got T-6.79+2gSin30+2a Then I got T= 6.79+2gSin30+2a Substituting that into 4g - T = 4a got me 4g - 6.79+2gSin30+2a=4a Taking away 2a from both sides give me 4g-6.79+2gSin30=2a which is then 39.2 - 16.59 = 2a 22.61 = 2a a = 22.61/2 i got a as 11.305 Help me out please although Im going to redo the question and If anything changes Ill remove this comment or post another one

[@SkillSasaBoy123]

idiot

[@nadirberrachedi4347]

@@SkillSasaBoy123 no need for that

[@Ella-cg2vz]

why is tension up

[@ExamSolutions_Maths]

No

[@nurmustaqqim256]

And the surface is given frictionless at first

[@thomasparisot6713]

how can A be at rest and have an acceleration? :S

[@herp_derpingson]

You use calculator for this? O_o okay :(

[@votevimto]

*are not irate lol