Single Replacement Reaction Practice Problems & Examples

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Conquer Chemistry

Conquer Chemistry

Күн бұрын

Пікірлер: 26
@ArlenGriswold
@ArlenGriswold Жыл бұрын
Great job best explanation I’ve found
@sophierobertson222
@sophierobertson222 8 ай бұрын
You are great at explaining! I actually understand now!🎉
@yaboibablu
@yaboibablu 5 жыл бұрын
This is so great thanks so much!
@biaastar_
@biaastar_ 2 жыл бұрын
TYY MAN UR SOO HELPFULL
@abdulrahmanalmadani7168
@abdulrahmanalmadani7168 5 жыл бұрын
thank you it helped me a lot in my exam
@jesssssssss7466
@jesssssssss7466 3 жыл бұрын
Wouldn't the sodium oxide from the first example be aqueous according to solubility rules? I thought oxides were insoluble unless the compound contains a Group 1 metal or ammonium...
@mariaherrera2896
@mariaherrera2896 4 жыл бұрын
thank you!!
@Moonflower6
@Moonflower6 3 жыл бұрын
thank you! this was great
@goldentrio7547
@goldentrio7547 2 жыл бұрын
Thank You
@kelli5966
@kelli5966 5 жыл бұрын
thank you this helped a lot
@hughjassole7600
@hughjassole7600 5 жыл бұрын
Why did the i in the 2nd problem automatically become i2 is that just a rule ?
@kelli5966
@kelli5966 5 жыл бұрын
i was just wondering the same thing. i guess iodine and hydrogen always get a 2? idk
@yaboibablu
@yaboibablu 5 жыл бұрын
ik this is very late, but its because they are diatomic elements. They are naturally always found in pairs, so we have to have H2 or I2
@brianaalexandra
@brianaalexandra 4 жыл бұрын
hugh Jassole You probably forgot about this comment but all halogens and gases are diatomic when they are by themselves. Hydrogen, nitrogen, oxygen, fluorine, chlorine, bromine, and iodine are all diatomic so they always have the subscript of 2 when by themselves (:
@theashologist
@theashologist 4 жыл бұрын
​All Halogens in column VIIA are diatomic elements mostly in the form of gases (because they are gases. The other two elements that are diatomic but not considered halogens are Nitrogen and Oxygen
@theashologist
@theashologist 4 жыл бұрын
Be wary about Oxygen. Peroxide is O with a subscript of 2 and a superscript of -2 (O2^-2). But its oxidation state is of a -1 charge. This is the same with Mercury. Their is Mercury H2+ and Mercury (I) H2^+2 BUT its oxidation state has a +1 charge because its a variable metal.
@edmarfuentes8512
@edmarfuentes8512 2 жыл бұрын
i didn't understand your explanation
@killedacatuskilledacatus6355
@killedacatuskilledacatus6355 6 жыл бұрын
Fairly garbage
@BabyBossOb
@BabyBossOb 4 жыл бұрын
Stfu
@killedacatuskilledacatus6355
@killedacatuskilledacatus6355 4 жыл бұрын
@@BabyBossOb ay bro not cool
@BabyBossOb
@BabyBossOb 4 жыл бұрын
@@killedacatuskilledacatus6355 wow ur active
@killedacatuskilledacatus6355
@killedacatuskilledacatus6355 4 жыл бұрын
@@BabyBossOb yea and
@BabyBossOb
@BabyBossOb 4 жыл бұрын
@@killedacatuskilledacatus6355 just didn’t think u would this was 2 years ago thought u passed or something
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