Consider the charges q, q, and -q placed at the vertices of an equilateral triangle, as shown in fig

Example 1.7, chapter 1, electric charges and fields, physics, class 12, ncert

[@harshgupta4932]

Abhi tak maine jitni book padhi hai 1 to 9 tak usme ncert hi aisi ek book hai jo doubt clear karne ki jagah doubt badhati hai

[@reefayesmin395]

Agree 💯

[@arpitaawasthi8397]

Sir plzz upload more video they are really helpful for us in our journey of neet / jee 😊😊 Thank you sir....❤❤❤

[@shravanasharma5968]

My godddd!!...u explained that so well sir!!...thank u so much sir!!🙏🏻🙏🏻😊😊🙌✨

[@PhysicswithGaurav]

Thanks dear student for appreciating my work 🤗

[@rakeshtyagi9968]

I must say you have a good experience

[@PhysicswithGaurav]

Thanks for appreciating my work 🙏

[@diksha5686]

Thankuuu veryy muchh sirr 🙏❤️ In my book the question is not clear like thiss but Now I'm able to solve it by myself ☺️ Thnkuuu very much 🙏

[@PhysicswithGaurav]

Welcome 🤗

[@manvirautela8980]

Thankyou sir .. very nice explanation sir

[@ujjwaldahiya8725]

Thank you soo much sir for this explanation😃

[@PhysicswithGaurav]

Thanks dear student🙏

[@AyeshaSyed-yo5vs]

Thanku so much....i was not able to understand anything from NCERT but u made is super easy thank you so much

[@PhysicswithGaurav]

Glad to hear that

[@snehachauhan237]

Splendid Really it is excellent explanation... Thanks sir

[@PhysicswithGaurav]

🙏☺️

[@droidly_]

I used ( F^2 + F^2 - 2F^2 Cos 60 )^1/2 instead of ( F^2 + F^2 + 2F^2 Cos 120 )^1/2 because Cos(180 - Q) = - CosQ

[@10ektasisodia10]

Thanq so much sir 🙏❤️🙏

[@PhysicswithGaurav]

Welcome 🤗

[@GaganNepram]

Keep it uuup sirrrrrrr

[@pranalikursunge7847]

Very well explained

[@PhysicswithGaurav]

Thanks dear student

[@user-zh1sq3ni2m]

Thanks a lot sir for best explanation 😊😊

[@PhysicswithGaurav]

Welcome

[@aiyoo_aronayy]

Thanks a lot sir 😇😇😇

[@PhysicswithGaurav]

Thanks dear student🙏

[@anandu5820]

What did you do at the end How did they become equal?

[@harshitmalhan8751]

Thank you so much sir

[@PhysicswithGaurav]

😇

[@velocxty2477]

Great explanation sir!👍

[@PhysicswithGaurav]

Glad you liked it

[@r.cfacts2733]

Thank q sir 🤗

[@PhysicswithGaurav]

Thanks 😊

[@alveeranadeemanjum4375]

Sir, will please show the proof of the same question that says Coulomb's law is consistent with Newton's third law which is left as an exercise in NCERT for students? I'll be highly obliged, sir...

[@harshbhai2079]

Thanks sir 🤘

[@PhysicswithGaurav]

😊

[@sillysiblings7317]

Sir agar isme direction bhi btani hui to i mean direction kaise find out karenge along F1,F2 and F3 ?

[@deepanshudas4108]

Sir this video is proven to be so helpful😊😊🤗🤗🤗

[@PhysicswithGaurav]

Thanks

[@GiveawayWallah]

Sir please describe how F1+F2+F3 = 0 in the this question , please please please please please please please please please please please please please please 🙏🙏🙏

[@PhysicswithGaurav]

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[@sofiyakhan2300]

😮​@@PhysicswithGaurav

[@satyamchaitu]

Milgayaa bhai.! Kab se baal keech raha tha.!! Thank you sir.!!

[@PhysicswithGaurav]

Thanks

[@Mystudyspacembbs]

But sir why is the sum of the three forces zero?

[@PhysicswithGaurav]

Dear student, by the vector law of addition

[@reshmakabra7184]

Thanks sir

[@PhysicswithGaurav]

Thanks 😊

[@dibyashankarpradhan1696]

Thnx 4 this helpful vdo sir...😌👏🖤

[@PhysicswithGaurav]

Thanks and welcome dear student🤗

[@suhanisahoo5461]

Thank u sir

[@PhysicswithGaurav]

🙏😇

[@adityasingh-iy2fq]

Helpful

[@PhysicswithGaurav]

Thanks

[@bhurvi5761]

thank u

[@anonymous-xv5gh]

Thanku

[@abdulraheemtt6674]

😍

[@PhysicswithGaurav]

🤗

[@vijayalakshmim1457]

Then, how can we say that sum of the three forces will be zero (as it is given in book)

[@PhysicswithGaurav]

Yes, the resultant of forces be zero, I will explain it in exercise problems.

[@vijayalakshmim1457]

@@PhysicswithGaurav Ok sir, thank you

[@GiveawayWallah]

@@vijayalakshmim1457 can you please explain how ? Request 🙏

[@kajalyadav4531]

Thank 😂 Sir

[@vishalpandit8558]

Sar aap kha sa hooo🙏🙏🙏

[@jagrititiwari2665]

Aap bht acha explain karte h 12ke sare chapter ki video bna deejiye

[@PhysicswithGaurav]

Thanks dear student.😇

[@BRAHMAN_7879]

Sir isme hum woh wala method kyo nahe use kr rahe Root√F2 + F2 + 2FF Cos120degree ?

[@PhysicswithGaurav]

Dear student we use it, check at 8.10 time on video

[@BRAHMAN_7879]

@@PhysicswithGaurav I didn't saw that sorry sir And also thanku sir Sir u teaches to well why don't u start a one shot series of ncert exercise and also important topics?

[@PhysicswithGaurav]

@@BRAHMAN_7879 thanks, I’ll start soon

[@BRAHMAN_7879]

@@PhysicswithGaurav 😇😇😇😇

[@panchamvaid1651]

Sir q3 pr -q charge h ...pr jb magnitude of force on charge q3 nikala toh..... answer F kyu aaya 😶😶.. - F kyu nhi 😵😵

[@PhysicswithGaurav]

Dear students, Magnitude means only numerical value, ( we don’t consider signs)

[@panchamvaid1651]

@@PhysicswithGaurav thanks sir

[@dreamworld9880]

Outstanding..

[@PhysicswithGaurav]

Thanks

[@dreamworld9880]

@@PhysicswithGaurav My pleasure sir..

[@jaatboy_786]

SIR AAPNE DONO KE MAGNITUDE KO EQUAL KYON RAKHA HAI 🤔🤔🤔🤔🤔🤔🤔🤔🤔🤔🤔???????

[@PhysicswithGaurav]

Magnitude does not depend upon signs of charges

[@Xavier-oo3ij]

Sir mere book mein direction bhi diya h..

[@PhysicswithGaurav]

Because this is solved example, aap ko exam mein directions nahi given ho ge

[@snehachauhan237]

But how the magnitude of two forces can be equal

[@PhysicswithGaurav]

Charges have same value ( magnitude) and the distance between all the charges same, thats why.

[@PhysicswithGaurav]

Watch it again after half an hour

[@banibhatia3965]

in book F1 + F2+ F3 IS EQUAL TO 0 HOW???

[@PhysicswithGaurav]

Watch it again after half an hour

[@itsmearia978]

why do we take it as COS 120 why not sin

[@PhysicswithGaurav]

It’s derived formula, you can check it in your book

[@jaatboy_786]

SIR JI RAAM RAAM 👍👍🤘

[@shit_sgoing_on8285]

💣💥💣💥💣💥💣💥

[@PhysicswithGaurav]

😇

[@codingwallah4612]

Wrong answer One of the force is √3F

[@officialmuskanclothhause]

Sir samaz me nhi aaya

[@SAGNIKDA_]

Kala ha kya tu hyaaa !!

[@Bhavna_42006]

Thank you Sir