Control Bootcamp: Example Frequency Response (Bode Plot) for Spring-Mass-Damper

[@testxy5555]

I've never understood the significance of the bode plot and the significance of synchrony. Now it makes so much more sense after seeing your experiment!

[@pedrodeazeredonogueira9661]

After taking "Dynamic Systems 1", "Dynamic Systems 2" and "Control 1", I finally understood the frequency response. All it took was a telephone and a good teacher.

[@mrzombiesbo]

The phone on the cord is an awesome visual aid. Great video

[@ireallyamrumi]

I am blown away at the quality and coherence of these lectures. Inspired to improve my own teaching ability. Keep up the incredible work

[@YohanSutjandra]

Boy! I wish you were my control professor back when I was in college. Thanks for sharing great contents Professor Brunton!

[@mustafayildiz2756]

only one word; AMAZING

[@Daniboy370]

You outdid yourself as usual

[@RobFrohne]

It is really hard to see the phase is -90 degrees. As you say, it looks like the phone bounces down (-180 degrees out of phase with your hand) when your hand goes up at resonance, but it is just plain hard to measure with your eyes, as it happens pretty fast. And as you indicate, the expected angle is -90 degrees. Nice illustration.

[@arintiwari]

u can only increase the damping factor in the eqn till 1.4 or else damping constant becomes greater than 0.7 and there is no resonant peak so we see a steady fall of the bode magnitude plot

[@outofthebots3122]

Thank you for this video. It made the penny drop

[@junuhunuproductions]

Super helpful, thank you!

[@mohamedelaminenehar333]

Thank you 😊

[@Eigensteve]

You're welcome 😊

[@tijmeng8550]

I still have a question, from the transferfunction I can calculate that the Phase for high frequencies is 180 degrees. But what does that mean pysically? Beacause I can imagine that at some point the phase will change again?

[@VTdarkangel]

Assuming you don't have any time delays in your system, your maximum phase is 90 * (number of poles - number of zeroes). What that means is, in a linear model, higher frequencies get really delayed relative to incoming signal speed or frequency. If it changes again at really high frequencies, you have a high speed pole(s) or zero(s) that you haven't accounted for in your TF model. In a physical sense, what phase angle means is how much delay there is between an input signal at that frequency and its response. So if I have a -180 degree phase at a frequency of 100hz, it means that the high speed portions of my output signal are going to significantly lag behind the input above 100hz or its equivalent.

[@arintiwari]

@@VTdarkangel yes and even more lag for non minimum phase systems

[@FGSRL]

super easy understanding :)

[@fhz3062]

Finally I know I'm not the only -- weird -- one to bounce a (cell)phone to explain how the magnitude increases with the frequency.

[@blackcat-mp7kh]

are you writing in reverse direction?