Cosine solution to Simple Harmonic Motion

[@jingyiwang5113]

You have offerred a crystal-clear explanation about the cosine solution to the simple harmonic motion. I am really grateful for your help! Thanks!

[@cutawayuniverse6396]

What's k in the equation

[@remowspread]

Thank you Dr. Anderson!

[@yoprofmatt]

You're welcome. Thanks for watching. Cheers, Dr. A

[@umarzanginamuazu7876]

I really like ur turtoruals

[@mickl3176]

Hi professor Anderson, Is there any way possible I can receive a set of full lecture for physics 3(optics)253? Please let me know.

[@aku7598]

Wish all videos related to "waves and oscillation" in single video.

[@RicardoHernandez-nd5pp]

Thanks!

[@yoprofmatt]

Ricardo Hernandez, You're very welcome. Glad you're enjoying the videos. You might also like my new site: www.universityphysics.education Cheers, Dr. A

[@matthew_bang]

Wow great professor. Makes my UC physics professor an absolute joke

[@yoprofmatt]

Matthew, Dang, that's cold. But thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A

[@grantking4032]

The -k/m(x) comes from the fact that the d^2x/dt^2 is equal to acceleration (a). Acceleration is equal to Force over Mass. a=F/m from the equation F=ma. Force is also equal to Negative spring constant multiplied by the distance. Now the a=F/m will look like a=-kx/m. because the k and x are multiplied together you can pull the x out and be left with -k/m(x). It took me a little bit to find where -k/m(x) came from. I am sure there is a paid version of this video somewhere that actually covers it, but if like me, you need to understand where formulas came from, you were probably lost and felt like you were missing out on some crucial information. Thanks, Grant

[@yoprofmatt]

Thanks Grant, I'm always looking to improve these lessons, so I appreciate your feedback. Cheers, Dr. A

[@grantking4032]

@@yoprofmatt i didnt expect a reply, holy cow. I appreciate you taking the time to read replies and respond. I am not sure if I was subbed before but I will check right after this. Thanks!!!

[@the_eternal_student]

Why does nothing happen to Amplitude in the derivatives?; constants are supposed to drop in differentiation.

[@cutawayuniverse6396]

What's k in the equation

[@kohilnoureddine9772]

Thanks a lot

[@yoprofmatt]

Most welcome. Cheers, Dr. A

[@tvd5002]

Dao động điều hoà Tổng hợp dao động Sóng Điện xoay chiều Mạch dao động

[@dennisrayrosas3175]

Now i know why i am confuse where did the formula came from hehe, i need to study calculus

[@TheKingDavid7]

Professor, what type of marker do you use? I want one lol

[@yoprofmatt]

Expo Neon. Cheers, Dr. A

[@saptarshimukherjeebmch2884]

sir,is timetravel possible through blackhole.....please explain me..

[@valkyrie9349]

May i know whether u r writing straight or opposite from ur side?

[@samanthas9742]

i think he writes straight and then flips the video maybe

[@royalgaming3469]

Why we take natural omega outside at 2:38 please explain anyone

[@JOE-sy6gy]

In A cos(wt+¢) first we differentiat it totally so we get -A sin(wt+¢) then we differentiat wt+¢. Since ¢ is constant and wt will become w×1 which is w , we can make it -Aw sin(wt+¢)

[@bhaswatimedhi6673]

@@JOE-sy6gy why is t = 1 ???

[@JOE-sy6gy]

@@bhaswatimedhi6673 its because of differentiation. The equation of differentiation of X^n =n×X^n-1 X is a variable Here x is t. w is a constant. Power of t is 1 (t^1 = t) 1×t^1-1=t^0=1(here t becomes 1) Add w after that cause it is a constant If it was t^2 then t will become 2t^2-1=2t

[@saptarshimukherjeebmch2884]

sir,plese make video on blackhole...everything about it..please sir,i want to know more about it......

[@mahesan2881]

Hold on!!! How are you writing like that????

[@_inky_]

He's prob writing on a mirror or some sort or reflective surface

[@SalhStudios]

@@_inky_ he is writing in regular direction may be he has flipped the video

[@saptarshimukherjeebmch2884]

what is -zone of no return->>>?

[@Tridebeshs]

Zone of no return is the event horizon where the gravity becomes so strong that you can't come back from that point

[@carultch]

In this context, that means yielding. When you deform a ductile material to exceed a limit called its yield point, it will permanently deform. It will still support the load, but when you remove the load, it will not return to its original size/shape. It is only in the elastic zone of loading, between zero and the yield point, that a ductile material will return to its original size/shape, after you remove the mechanical load. A brittle material by contrast will not have a yield point. Instead, it ruptures immediately at the end of its limit of reversible loading.

[@amazingman8842]

Sala chutiya youtube, kal exam hai aur mera net slow lekin video quality 1080p pe set hogaya aur video load hi nai hora. Aur sath me bas 100mb bacha hai.

[@yoprofmatt]

Good luck on your exam. Cheers, Dr. A