Coupling constant | Spectroscopy | Organic chemistry | Khan Academy

[@TeodoraMateeva]

Dude, your explanations have saved my life so many times. Bless you!

[@sharonwangurra8621]

Lmn lama I 8jdjdkkfit

[@mickeyminou]

thank you , I'm at 0:20 and you just said exactly what I wanted to hear :D Now I can go on lol

[@BruinChang]

I searched little bit for magnetic equivalence and chemical equivalence. Magnetic equivalence has a more strict symmetry demand than chemical equivalence. I quotes from libretext: "The first important point to note is that magnetically equivalent nuclei do in fact couple to each other, however no splitting is observed in the spectrum. The second point is that chemically equivalent, but magnetically non-equivalent, nuclei couple to each other, and this coupling is observable in the NMR spectrum."

[@Ethan-pm3ig]

Thank you so much this was so helpful 🤍

[@amhraenidheasmhunaigh9005]

in the first example how would you identify which one is more deshielded by OSiMe3 if they are both seperated by one double bonded carbon

[@twilightselena4eva]

Hi how did you know that the coupling constant was 1.4 hz? (At 2.26)

[@hkharis07]

twilightselena4eva I am stuck with this calculation also though I used to do this but now I forget how to calculate J value

[@h33day]

delta/(spectrometer machine's MHz)=J. He didn't mention what the machine's MHz was so we can't exactly calculate, but that is the general formula.

[@suniladiyodi]

the difference between two peaks in ppm, multiplied by instrument frequency in MHz.

[@seras.9187]

Thanks

[@adaratemizler7344]

where is the 7 Hz coming from?

[@Hirschbergs]

In the second example each proton in Blue has not 3, but 4 neighbours - 3 vicinal protons from - CH3 group and one geminal proton from the -CH2, so 4+1 equals 5, it means in this case you will see a multiplet (not a pentet, though).. Same applies to the protons in -CH3 group. Each one of them has 2 geminal neighbours and 2 vicinal neighbours, which means 4+1=5. So it be either dt or m....

[@codchemistryclub4358]

They are 3 bonds away so I believe they are too far to split at that point, barring using a specialized technique.

[@marco_gorelli]

Kaggle CHAMPS competition brought me here

[@emil.krumov]

FUCK! :D :D :D