CSEC Chemistry - The Mole Concept 2

[@Dxspair.]

got a few weeks before my exam. These videos help me a lot, thanks sir🙏

[@shaniquacolebrooke680]

Watching your videos to prepare me for the exam in may/June. Your videos are very straight to the point and easy to understand...:)

[@csecchemistry]

Thanks. Good luck in your exams.

[@zygon8685]

thanks for doing these videos , they were really helpful .

[@csecchemistry]

Thanks

[@aneiliachandersingh8264]

OMG!!!I Tried it and I figured it out...feeling proud...tanx sir..for making education entertaining

[@jasminwilkinson1345]

thank u very much...my teacher taught moles and I was confused ...now u explained and taught me it a different way I understand...once again thank u...imam promote ur channel

[@csecchemistry]

Excellent

[@shennelllambie7052]

You are so easy to understand. Phew...tryna help my classmates & stay woke at the same time

[@leonardobanks2140]

TOMORROW 😁😁😁😁😁😁😁😁😁😁🙌🙌🙌🙌🙌🙌🙌

[@jashalawrencin6795]

shouldn't it be 0.944 and not 0.943 because there's a 7 at the back of the three.

[@that_gurlshay_17]

Your right

[@jerronmohd9652]

Your videos helped me alot! Thank you and keep up the great work!

[@coreecegrant9292]

Thank you so much.

[@shennelllambie7052]

Sir i see another error. RMM for CaCl2 isnt 111g instead of 110g?

[@csecchemistry]

And how did you get that....40 + (35.5 x 2) = 111 g

[@shennelllambie7052]

@@csecchemistry yes Sir

[@angeliesingh9716]

No Moles came this year:(:(...But your videos really prepared me for that!

[@csecchemistry]

Wow...that's odd, usually it comes is some form and they always complain that students don't understand the mole concept. I'm glad to hear the videos helped. Hope you do well when results come out.

[@azourisuarez4040]

Tenq sm sir ❤❤

[@jeffventures2430]

I'm confused with a few things in the video and was wondering if you could explain, for the limiting reagent question why did you multiply 0.02 by 2 instead of 0.08 and also why did you use 2 instead of 20 for part B of the same question

[@csecchemistry]

I'm just checking it and I realize I made an error. In the question it should be 2 grams of calcium carbonate. So the calculation is correct....its just that I typed 20g instead of 2 g.

[@shennelllambie7052]

I was wondering if my head tough cuz I saw this too. Que, Sir: Why is it that the RMM was calculated for CaCo3 but not HCl? Is it because the molar concentration was given? I love your videos btw❤

[@shennelllambie7052]

So Sir you could find out the no of moles for CaCo3 another way by simply using the equation: 1mole CaCo3 reacts with 2 mole HCl. Since we know the no of moles in HCl 0.08moles we can find the moles for CaCo3 which is 0.08mole ×1/2=0.04moles CaCo3. But, I see they only used 0.02mole CaCO3 so this means 2 (0.02) HCl used.This also can double check our answers for question B rt?

[@alleyne-palmer95]

sir should we round up the moles after calculating or is not needed?

[@sashoyajohnson705]

Thanks 😊

[@moviesandchips3936]

Thanks so much

[@tramaneclarke]

Help!!!! 25 cm3 of a dibasic acid solution containing 4.9g dm3 reacted exactly with 25 cm3 of a solution of a base of concentration 0.50 mol dm3. What is the relative molecular mass of the acid?

[@shennelllambie7052]

Well I attempted. Rmm of 1 mole? I'd need to see the elements involved. However, I wrote: 1000cm3=4.9g. Then 25cm3=4.9÷1000×25 =0.1225g was used in the experiment. Sir,please look

[@Erenilda.]

❤❤❤❤

[@grace-anncampbell7632]

If it is 20g it should have been 0.2 moles of calcium carbonate

[@csecchemistry]

I believe I used 2g of calcium carbonate in my calculation and not 20g. Give me the time in the video and I will check for you.

[@grace-anncampbell7632]

+CSEC Chemistry oh ok Otherwise from that i understood everything from your video. Your a great teacher , thumbs up!!!! thank you.

[@csecchemistry]

Thanks for the thumbs up. Moles can be easy once you understand what is being asked.

[@pot__roast1976]

Tree.Tree tree tree 🤣

[@notfunny7876]

I dont fucking understand it