CSIR NET 2024 Chemistry | Inorganic Spectra CSIR NET | Inorganic Chemistry Questions | Nadeem Sir

Accelerate your CSIR NET Chemistry preparation with our specialized sessions! Join our Inorganic Chemistry One Shot for a comprehensive review and our Inorganic Spectra Revision for focused insights. These targeted sessions are designed to strengthen your knowledge and boost your confidence for the CSIR NET exam. Don't miss out on mastering key concepts effectively #csirnet #inorganicspectra #chemicalsciences #inorganicchemistry #csirnetchemicalsciences #csirnettestbook
👉Fill out the Google Form Now to Join🔥 Booster Crash Course to Achieve JRF in JUNE 2024: forms.gle/BnTb...
👉Get Additional Discount Fill the Form Now- forms.gle/LRoy...
➡️🔥Click here to Get The Offer Use Code: NADEEM - testbook.com/g...
****************************************************************************************************************
Start Your CSIR NET | SET and GATE Exam Preparation with our FREE Content (Limited Offer)
➡️Join Nadeem Sir Free Masterclass on Testbook App - link.testbook....
➡️📲 Download Testbook Exam Preparation app to attend all classes: link.testbook....
➡️🌍Visit our website : testbook.com/c...
➡️Testbook Pass Pro Click Here- link.testbook....
****************************************************************************************************************
Playlist:-
➡️CSIR NET | SET and GATE Chemical Science | Inorganic Chemistry by Nadeem Sir : • CSIR NET | SET and GAT...
****************************************************************************************************************
➡️ Join Nadeem Sir Chemical ScienceTestbook Telegram Channel- t.me/NadeemSir...
➡️ Join SuperCoaching for CSIR NET | GATE Chemical Science by Testbook TG Channel- t.me/CSIRNETCh...
➡️👨🏻‍🎓 Student Support & Course Inquiry feel free to 📞Call on 011 4084 8077 or email us at [e-mail]
Joint CSIR UGC NET is a test being conducted to determine the eligibility of Indian nationals for Junior Research Fellowship (JRF) and for Lectureship (LS) /Assistant Professor in Indian universities and colleges subject to fulfilling the eligibility criteria laid down by UGC.
The National Testing Agency (NTA) has been entrusted by the Council of Scientific and Industrial Research (CSIR), with the task of conducting the Joint CSIR-UGC NET Examination in Computer Based Test (CBT) mode.
________________________________________________________________________________________
#csirnet2024 #setexam #gateexam #csirnetjune2024 #csirnetchemistry #chemistrybynadeemsir #inorganicchemistry #chemistry #chemicalsciences #csirnetexam #csirnetsyllabus

[@Amit4UU2]

Hw ans ) correct✅ option( 1) 8 and 8 1) H- NMR --- 3H decouple with B11(4 line) and p31 (2 line) =2×4--8line B11 NMR - B11 decouple with 3 H (4 line) and 1 P31 (2 lines) =2×4 ----8 lines

[@npaski]

Tnx for bringing simplified version of tough and scary topic

[@sumaylasumayla1599]

Hw option 1 correct 1Hnmr give 8 lines and 11B also give 8 lines thank you so much sir

[@pradhumansinghchouhan9237]

Homework answer -- Option A

[@harishsamanpelly3606]

Tq so much sir for the wonderful session ❤

[@biswajitbjm]

Ans-A

[@manishamishra3993]

Homework Ans:- Correct option -> (a) 8 and 8 Explanation:- 1H & 11B NMR spectrum of PPh3.BH3 molecule : 1H NMR spectra -> quartet and doublet (4×2=8 lines) 11B NMR spectra -> quartet and doublet (4×2=8 lines) Thank you so much sir 🙏

[@Amit4UU2]

Hi manisha..... Ap booster batch me enroll kia ho?

[@manishamishra3993]

@@Amit4UU2 Nhi. Aapne join Kiya h?

[@Amit4UU2]

@@manishamishra3993 nhi.... Bs notes bnakr pdh rha. And test series

[@npaski]

Won't it be doublet of quaderate ??? How to decide whether signals will be in which order ? I m new to this topic can u pls help me guiding

[@manishamishra3993]

@@npaski The coupling constant value (J value) will be mentioned in the examination. Which has higher J value that will be splitted first. For this question PPh3BH3 , while calculating 11B NMR spectra we get doublet when B decoupled with P and we get quartet when B decoupled with H. Let's consider, if J value of P > H then for this example we can say that "doublet of quartet" . Hope you will understand what I'm trying to say.

[@harishsamanpelly3606]

Correct answer :- A

[@monayadav614]

Correct answer is option a

[@PayalSharma-c9v]

H.w 8 and 8 lines

[@premaarya9340]

option no .1

[@adeshmaurya399]

Correct answer aaaa

[@janhviyadav486]

8 and 8

[@Sohitrao234]

A

[@aabidhussain428]

8 n 8

[@paraggore-jt8gh]

opp A

[@preetikaler1323]

A