CSIR NET DEC 2023 MEMORY BASED QUESTIONS DISCUSSION

[@mathematicalPathshala]

Question 19 I solved wrongly, as unit rational circle is not complete, hence it can not be compact, sorry for the wrong argument 😢

[@harshbaranwal7544]

Hello sir,in last question,a/c to you for cardinality of such group matrix there exist matrix [(3,1)t,(3,7)t] which is singular=>cardinality is wrong b/c you include zero divisors. Please reply if I say correct 🙏🙏

[@mathematicalPathshala]

You seem correct, i will think the correct explanation

[@Attitude.184]

Sir lpp wale me (4,8) corner point nhi bnega

[@mathematicalPathshala]

Yeah, later I solved completely

[@amananand7970]

Sir offline class kaha krwate ho plz reply

[@mathematicalPathshala]

Agra Centre

[@qsmaths2784]

Sir, since x^TAx>0 for all x in C for complex positive definite matrix A . Again every real positive definite matrix can be treated as complex positive definite matrix . So option( c ) is not correct in my opinion .

[@mathematicalPathshala]

I don’t think so.

[@qsmaths2784]

(1,i,-i),x^TAx=-i/2

[@suru8183]

​@@qsmaths2784if we can take vector 1,w,w^2 in c for complex?

[@suru8183]

​@@qsmaths2784Then this option is true na

[@RanjithKumar-ep1uz]

1h.10 min that question lemda zero both convergent

[@ykmathsguru1196]

Bahut Sandar Explain karte ho Aap Sir

[@mathematicalPathshala]

Shukriya

[@Guddu_pahadi1995]

Question 10.. 12 bhul gye..

[@aradhanakatankar2631]

EC

[@Dearbhanusir]

3-4 questions hi sahi krke aaya tha ..vo bhi sir ki video dekhkr glt ho gye😢

[@reshavbhatarai7413]

Same here

[@Krantiveer-y7u]

Same here ☺️