CSIR NET June 2023 Mathematics | Real Analysis Solution | Q.Id 704064 | December 2023 by Sudip Sir

  Рет қаралды 3,162

Pure Mathematical Academy

Pure Mathematical Academy

Күн бұрын

Пікірлер: 18
@prerakpatel5808
@prerakpatel5808 5 ай бұрын
Nice sir kash pahelese aese teacher mile hote to koi doubt hu na raheta
@rintumondal5658
@rintumondal5658 5 ай бұрын
H.W: it's false as one one fail karega
@Satvik_negi
@Satvik_negi 7 ай бұрын
H.w. - false counter example - f: R-->N. g.i.f Restriction of f = N
@_AniketSamurai
@_AniketSamurai 5 ай бұрын
Sir in a option d) Since all points are isolated points so can we say that restriction function will be continuous on this isolated points?.
@SRajagopalrajagopal
@SRajagopalrajagopal 6 ай бұрын
consider f : Z to Z^+ such that f (x)=x^2 g is a restriction function such that g : w to Z^+ defined as g(x)=x^2 g is 1-1 but f is not 1-1
@avsbrothers
@avsbrothers Жыл бұрын
2023 ka paper kis जगह पर मिलेगे sir
@Mandeepkumar-lu8iy
@Mandeepkumar-lu8iy Жыл бұрын
1/n means domain is not connected how discuss continuity left and right limit please reply
@varun08sinha16
@varun08sinha16 8 ай бұрын
Bro sequential criteria use kro
@uvaish576
@uvaish576 Жыл бұрын
Sir we can discard option a by ivp Let restriction function is continuous, then continuous function map compact set into compact set, but image of compact set is not compact then we can say option a is false?
@Nainagour-l1h
@Nainagour-l1h Жыл бұрын
Home work sir ( lemma= let f:A tend to B be a bijection and c contain A then the restriction f|c: c tend to f(c) is also bijection
@dollysingh7072
@dollysingh7072 Жыл бұрын
False hoga ....onto possible hai agr periodic ho to
@samranaaz8988
@samranaaz8988 10 ай бұрын
home work- false
@jaggul3249
@jaggul3249 Жыл бұрын
HW True
@mukeshkumarkaziana2989
@mukeshkumarkaziana2989 Жыл бұрын
H.W. true
@zahidgeelani44
@zahidgeelani44 Жыл бұрын
False
@Nainagour-l1h
@Nainagour-l1h Жыл бұрын
Sir ye true hoga
@puremathcsir2021
@puremathcsir2021 Жыл бұрын
Home Work !?
@Nainagour-l1h
@Nainagour-l1h Жыл бұрын
Sir ( we may define g:f(c) tend to c such that g( f(c))=c this is well defined due to bijection of f there fore gof|c=idc and f|cog=idf(c)
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