CSIR NET Mathematics||Dec 2013|| complex analysis video lectures

[@laldinpuiarenthlei7615]

Eventhough i dont understand hindi, but i understand your explanation.....thank you for making video for us, thank you sir

[@rajeshlahare3487]

Superb explanation sir.. Thank you so much

[@jivishajain7487]

If we take e^z then first option is discard...then how to solve?

[@ShivamKumar-tg3vp]

Sir , I have still a doubt in omission of option 2. Why can't we omit using Liouville's Theorem???? Sir, is it because , we are given fxn. to be holomorphic in disc only and not on entire complex plane.

[@shikshasaini3840]

option (b) is f is bounded and its given in the question that f is entire thus by liouvellie's theorem f is constant, which again is contradiction as given that f is non- constant. Can we think like this?

[@manishakaninwal9685]

Sir,aap ek video me bol rhe thhe ki theorm ki statement ...or uske counter example yaad rkho....... Ye smjh nhi aaya sir...counter example kase krne h

[@mohdaadil6692]

Sir your method to solve the problem is very good

[@tejashreesaravate1351]

hello sir june 2013 ka set b se question no 36 ka solution dijiye it is from linear algebra

[@ShaktiSingh-zp6jw]

Very nice sir

[@poojachaudhary8510]

Very nice

[@devashish890]

Hello sir , when iam solving this question by myself ( today i saw your video) then i take counter examples -(for B) - exp(z/2) , (My thought process) - Since exp(z) is a periodic function with period 2pi *iota so , exp(z/2) is a periodic function with period pi* iota and on a unit disk (Imaginary Axis this length will be convered easily ) so f(z) is unbounded also it's Range will be entire complex plane expect 0 , for last option i consider - f(z)= z-1 . (f(0)=1 )

[@rajvinderbatth2839]

Sir can we take z+1 for b option?

[@harikripal2489]

board work is awesome .

[@RahulMapariBasicMaths]

Thank you

[@Matchless_gift]

Very helpful..like the way of teaching

[@aamiryousuf3149]

New videos plz

[@arunnagargoje1439]

It's great help sir... Thank you so much

[@SanjoyMondal-yj9nu]

Thank you sir.

[@roniadhikari2724]

2018 June and 2017 Dec ar cov solution send koriya plz

[@arindampaul1812]

sir can u solve the problem of complx analysis of csir net December 2014 ... part c k three questions...

[@RahulMapariBasicMaths]

Ok

[@debopriyopalchowdhury6045]

Sir, please upload the solutions of - 1) NET DEC 2011( Q. 30, 40 COMPLEX) 2) NET DEC 2013( Q. 82 COMPLEX) If you please solve the sums, it will be very helpful for me. Thanks for your great efforts.

[@mdsaquib8083]

Sir how e^iz is unbounded??

[@mdsaquib8083]

Sorry how e^iz is bounded that u say in the solution.

[@RahulMapariBasicMaths]

For particular domain

[@purabisaud3626]

If this question makes inbC part is f is bounded correct or not

[@RahulMapariBasicMaths]

Not correct

[@arindampaul1812]

plz sir it's urgent because I m appearing June 18 net exam... 1. f(z+ia)=f(z-ia) Jo option bale problem Hai o... 2.S={RE(f(z)+IM(f(z))} is an open set in R 3.f(z) be an entire function and r be a positive real no.then...

[@RahulMapariBasicMaths]

What is question?

[@ankurtaneja7026]

in first option if we take e^z then option discard...then explain the option

[@RahulMapariBasicMaths]

??? I didn't get u properly.

[@jivishajain7487]

Ist option if we take e^z then |e^z| =1 for only z=o not for infinitely many points in unit disc

[@RahulMapariBasicMaths]

No, for this function we infinite points again. See u take zero right. But if take x=0 and y nonzero from unit disc u will get again infinitly many points in unit disc. Y axis upto positive one.

[@deepthipolakonda5311]

Thank you so much sir...

[@adityachouhan3855]

Integral equation ka syllabus

[@sandeepjaiswal7505]

very nice sir thanks for help us, sir please upload more vedio on complex

[@RahulMapariBasicMaths]

Ok. I will try to cover all Questions.

[@sandeepjaiswal7505]

Rahul Mapari thank you so much sir

[@SanjoyMondal-yj9nu]

Sir, why you take y=0? Can i take y any non zero?

[@RahulMapariBasicMaths]

I m not taking only y=0 ,this is for checking points at mod f =1

[@nehaaggarwal2587]

Sir discuss more ques. Than one in one video....

[@sanjitsingh3154]

Sir i guess e di power iz is not holomorphic function

[@RahulMapariBasicMaths]

It's holomorphic. See iz is holomorphic so e di power iz also holomorphic. Dont confuse in a simple things.

[@damanhunjan8215]

Thanku so much sir ... Sir plz upload videos on linear algebra also...

[@RahulMapariBasicMaths]

Ok

[@mdsaquib8083]

Sir here f map C to D{|z|

[@mdsaquib8083]

No I think I m wrong

[@tanutyagi3848]

Sir i had used open mapping thm in this question and get same answer even i didn't know that it is from b part or c part. I used that thm and get same answer and discard other options

[@SanjoyMondal-yj9nu]

If i take y any non zero then |f (z)| never not equal to 1.

[@RahulMapariBasicMaths]

That's why I take y=0 . See we have just verify is their any points where mod f =1 , and we get infinite. That's all

[@Mathshubham]

Sir please upload videos on some important topics of complex

[@RahulMapariBasicMaths]

I have already uploaded, link- kzbin.info/www/bejne/laPOiZ-Cft58n8k

[@RahulMapariBasicMaths]

Or U will get video on end of this question.

[@soundharyadevik9694]

I dont know hindi sir....will u please teach in english ..sir

[@Mathshubham]

Sir can we take f(z)=z+1

[@RahulMapariBasicMaths]

For which option u want to take f=z+1

[@Srinivasa-no-eqn-without-god]

then mod of f is not 1

[@RahulMapariBasicMaths]

It is equal to one for z=0

[@DkSaini_Maths]

e^iz is unbounded on C , i think

[@RahulMapariBasicMaths]

Yes, actually every non constant entire function is unbdd

[@rajnibansal3587]

Sir question is very nicely solved but i have a question in my mind that by taking example we can discard any option but can't be mark correct

[@RahulMapariBasicMaths]

Yes. Counter example is more useful for Descarte the option.

[@rajnibansal3587]

Thanks sir

[@jivishajain7487]

If we take e^z then ist option is discard

[@veenarani9601]

please prove in general. not by taking example for option first

[@RahulMapariBasicMaths]

Ok. When I will take theory lectures I will prove the result. Thanks for suggestion. But this is question of CSIR NET, so within a time we have to solve question.

[@veenarani9601]

Rahul Mapari examples are taken to verify the result not to prove them. may be result fail for another example. so prove in general. for example is not a proof

[@RahulMapariBasicMaths]

But my friend, we can not prove every result in 3 Hours. We hv to use counter example. And I told u when I take theory lectures then I will prove.

[@cavendis3423]

nice sir

[@lakhanmahto9405]

sir real pe vedio bnyea plzz

[@RahulMapariBasicMaths]

Ok

[@yazhiniyazhu7685]

Please, explain in English sir

[@shossain8995]

Dear sir, I follow all of your uploaded videos. It's quite easy to get your logic. Sir, I have some previous year problems on CSIR net . Can I get your email id or anything through which I can contact you. please sir, I will be very grateful.

[@RahulMapariBasicMaths]

Ok. My whatsapp number 9405316462

[@shossain8995]

It's my pleasure.

[@lalbahadursingh4079]

Csir net

[@not_avii]

ur video is not clear

[@RahulMapariBasicMaths]

Plz change setting of resolution above 420p then u will get clear video. Some times bcoz network problem it will take default resolution. So plz try and watch. Thanks

[@RahulMapariBasicMaths]

I hv check my friend, plz do above procedure u will get HD video. Bcoz I hv uploaded Full HD version of this video.

[@MandeepKaur-cn8ct]

@@RahulMapariBasicMaths such a kind and humble person you are . Replying to each n every student and resolving their issues on time . Sir you have INSPIRED a lot of people

[@RahulMapariBasicMaths]

Thanks for appreciation.

[@damanhunjan8215]

Thanku so much sir ... Sir plz upload videos on linear algebra also...