CSIR NET MATHEMATICS DEC2016 || COMPLEX ANALYSIS || COMPLETE SOLUTION || Part C.

[@monikad9128]

In problem 79 finding zeros of (1-e^z) sinz alone is not enough to say that they are simple pole. Showing derivative of (1-e^z) sinz doesn't get vanishes on those zeros will say that those zeros are simple poles of the function

[@naveendixit9304]

yes you are right. mam, pahle apne concept clear karo tab video banao. students ko gumrah mat karo.

[@rpriyadharshini5029]

Mam q.no 81 12complex roots (option d) also right answer ?

[@AbuHuraira-ez6hy]

How?

[@SaddamHussain-js6ut]

In question 79 correct options will be 1 and 3.

[@pmathematics]

Option 2 and 3 are correct options

[@SaddamHussain-js6ut]

In 2nd option if we put k=0 then zero will be pole of order two.

[@pmathematics]

@@SaddamHussain-js6ut Nhi.. If we put k=0 then Z=0 is a simple pole

[@SaddamHussain-js6ut]

Ya mam you right . I'm extremely sorry.

[@SaddamHussain-js6ut]

I shouldn't blamed like that.

[@akashhalder8698]

Good work

[@pmathematics]

Thank you.. Please like, share with your friends & subscribe to our channel.

[@arunnagargoje1439]

Thank you so much madam

[@pmathematics]

Wlcm

[@mathematical2508]

Mam in 82 question in first option u did in wrong way i think bcz if g holomorphic take z-1 and when u will do g/z then it has sing at z =0 so g/z is not analytic First option is correct for correct approch of this option is that h(z) = g'(0) and g is entire and nth derivative is also entire so h is entire so first correct If i am wrong please correct me