Cubic Equation 2 | CAT Preparation 2024 | Algebra | Quantitative Aptitude

Advance Algebra by Ravi Prakash | Quantitative Aptitude for CAT 2024
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[@Rodha]

At 15:40 : 2ac is 2*1*25

[@sachinkumarsingh2518]

Sir , what is this 2ac , i think it should be 4ac na ??, please reply..🙏

[@mindfullmallu7511]

@SARTHAK BORA 🤡

[@mindfullmallu7511]

@SARTHAK BORA 🤡

[@arvind109singh]

@@sachinkumarsingh2518 it's a condition ig. Not a discriminate

[@mr.tembhurne2977]

@@mindfullmallu7511 correct

[@ROHIT-SHARMA-897]

RESPECTED SIR KINDLY CLARIFY ONE DOUBT IN X^3+5X^2+25X+125 2AC SHOULD BE 2*1*25 AND NOT 2*1*125.KINDLY CLEAR THE DOUBT. WITH REGARDS ROHIT SHARMA

[@zoro3188]

Your perception is correct sir made a little mistake their

[@rayzoldyck8044]

nigga wrote a whole ass application lmao

[@namansharma2721]

Great Job sir. You are a real Hero! Thanks a Million times!

[@prashantvats4852]

You are using 125 instead of 25. So please pine a comment for confirmation..

[@humairaalam969]

Yes isn't that a mistake ? Like c is supposed to be 25 i guess he used the value of d ..

[@rajatghosh7272]

why did we use b^2 - 4ac previously and now its b^2 - 2ac? What's the difference between the two?

[@overexcitedladki23]

It's a condition...not a discriminant

[@ShuvamNayak]

At 8:01 shouldn’t the equation 3 be equal to -b ?

[@vedantmishra3697]

Yesss

[@kanakh7775]

yes sir told it in a different way, like b is negative so value is negative only.

[@sreyoshibanerjee5887]

Why is the Discriminant of the cubic equation (b^2-2ac) and not (b^2-4ac)? Please help.

[@deekshitabora8280]

Because that's not the DISCRIMINANT, it's just a condition.

[@lazy_sorbet]

There's nothing like b^2-2ac like quadratic equation,in cubic equation we have to compare b^2 to 2ac , if it is less then 2 imaginary roots and 1 real root. Else all roots are real.

[@abhinavkumar-qg6lj]

Where is descartes sign rule video?

[@rohankrishna1818]

Amazing concepts!!! Thank you sir❤️

[@soumadipranjanbiswas1779]

Hi Sir, Thanks for the series. I wanted to know where is the "Descartes sign change rule" video ?

[@MaxwellNaradd]

Did you find it?

[@soumadipranjanbiswas1779]

@@MaxwellNaradd no

[@yashasharma9963]

Thanks for your efforts, Sir.

[@Endever10]

Wlcm😊

[@saurabhmishra4953]

If apna= beta= gamma= delta=3 Then this root must satisfy the equation of bi-quadratic mentioned here which is not! Can anyone suggest me if I am wrong anywhere ?

[@saswatarouth1516]

I think you have done something wrong in the calculations

[@sachinkumarsingh2518]

Answer of the eqn by putting x=1(let's say), its coming out to be equal to 16 instead of 0 & by putting X=2 , Eqn. equals to 1 , why so ????? Can anyone clarify this doubt ...

[@amanvarma4839]

Wrong Calculation. It is satisfying. Putting x=3, eq=0

[@hiteshahlawat4886]

Sir very nice conceptual video ❤️

[@yatinjoshi6802]

at 11:50 if the roots are non negative then how come the b is -108

[@fenzhang]

B is not a root

[@naveenkamath907]

b is not a root it is a coeffiecient of x

[@shekharankiya2414]

Why we can take abcd as the roots instead of alpha gama bita?? Abcd = 3*3*3*3 B= 3 A=3

[@vishalrajoriya8557]

hey can anyone share the descartes sign change rule video link

[@sachinkumarsingh2518]

Dear Sir, Good Morning At 8:40 , facing problems till the end of this question, because after putting the values in the equation, values doesn't satisfy the equation, please check once..

[@ritikagaddellu7938]

Nope..equation satisfies✅✅

[@smitpatil1584]

b must be negative

[@academics7471]

At 15:55 should c be eual to 25 instead of 125?

[@raviprakash6021]

Yeah .. thanks for figuring it out.. we have recorded more than 300 videos, so even after reviewing there can be small errors in around 5% of the videos . I will again review and I will put an ERRATA comment for correction.

[@SiddharthBasu100]

@@raviprakash6021 Please upload more videos. Less than 3 months for CAT 2019.

[@manjunathm7987]

yes

[@Sanchofan1]

@@raviprakash6021 thank s sir for all your efforts.

[@avinashnair8433]

@@raviprakash6021 Thanks Sir for the effort and time you had put to make us understand the topic. :)

[@Shivam_General_Fitness]

Thanku sir

[@raghav_daga]

What is the use of calculating the value of one root among the three roots in the last question? How will that help to solve the question further?

[@sidharthnair881]

Then you use that factor(E.g. if 1 is a root, (x-1) is a factor) and divide the whole cubic equation by this factor using long division method to get a quadratic equation. Then solve the quadratic to find the other 2 roots.

[@therevealer672]

You can use synthetic division method to reduce the equation to quadratic and solve quadratic for other two roots.

[@ss590]

Thankyou 💜 so much sir 🙏🏻

[@cumulusmusic100]

Thank you Sir🙏

[@dakshpatel2839]

Thank you so much sir

[@KuNjAcHaNBasil]

Thank you.

[@HOLIKESH]

Sir, where is the next video containing Descartes sign change rule as you have mentioned in the video. Kindly help

[@anandhus603]

did you get it ?

[@ypoojaa]

thank u sir❤

[@soumadipranjanbiswas1779]

I wanted to know where is the "Descartes sign change rule" video ? Can you please help ?

[@samaymohale3050]

At 15 condition is not satisfying for eqn x^3+2x^2-3x-10=0 ....which has one real root at x=2 and 2img roots

[@saisanthoshr464]

At 14.17... The discriminant of cubic equation is b^2-3ac and not 2ac...

[@avinashnair8433]

Well That's not at all a discriminant he is saying. That's just a condition.

[@sapeduworld]

At 11:13 now he has taken minus sign where as in last video he took positive sign😕😕😕

[@avinashnair8433]

@@sapeduworld Here the condition is different. Here we have four roots while in the last video we had 3 roots. Actually u need to understand properly how those roots are being evaluated!! Similarly when we will have 5 roots and 6 roots, it will be different. Try to understand the pattern properly. So that u know what will be for n no. of roots!!

[@sapeduworld]

@@avinashnair8433 Bro plz tell from where i can get more info about how these roots work...plz send the link if any

[@avinashnair8433]

@@sapeduworld Watch Ravi Sir's introduction video of Cubic Equation. Sir explained those concepts really well 🙂

[@jaidevtyagi1033]

Sir in the first eqn the roots are p,q,r. Now at x=1 the equation satisfy. one of the roots is 1. whatever we add to 1 we'll get the answer as greater than 1, then how can the answer be 0.25

[@jaidevtyagi1033]

Ok so the question is wrong as 1 root is real and two are imaginary ✌️. Discriminant= -4

[@samparkestates-kr9od]

hi. Can anyone pls share the cubic equation part 3 link... The playlist has cubic equation part 3 but it has quadratic eqn lecture.

[@Dev-jp4rn]

There is only 2 video of cubic eqn

[@snehsingh4]

At 4:48 how can denominator be equal to 4???

[@rahulsinghchauhan6182]

Bcoz in question p²q²r² is given in denominator and the formula is pqs = -d/a means =2 so p²q²s² = 2² = 4. Hope u understand.

[@subhasmitabehera2947]

Discriminant is b^2 - 4ac na...

[@sachinkumarsingh2518]

Yaar wahi toh yahan 4ac hona chaahiye na, bahut confuse ho gya iss video me...If you got proper explanation of this 2ac , please reply ..

[@jaideepsingh4395]

@@sachinkumarsingh2518 bhai ye discriminant nahi hai ye bas ek condition hoti hai jo cubic equation pe apply hoti hai. Or wo jo b^2-4ac hota hai vo bas quadratic equation ke liye hota hai.

[@abhishekpatidar7740]

🙏🙏

[@soumadipranjanbiswas1779]

I wanted to know where is the "Descartes sign change rule" video ? Can you please help ?

[@akarsh121]

Thank u sir🙏

[@mindfullmallu7511]

☑