Current Electricity July Attempt Solutions of JEE Main 2022 | Physics PYQs | Eduniti | Mohit Sir

[@mohitgoenka99]

In this video Mohit Goenka Sir discusses all 22 questions asked on Current Electricity July Attempt JEE main 2022. 😍 Just in Rs 99 get all Physics Concepts, Chapter wise PYQs (2019 to 2022), Tests and How use web version - kzbin.info/www/bejne/fWmxgaCXrrlmgpo 👉July Attempt Chapter Wise Solutions Playlist Link - bit.ly/3LeU4zB 👉June Attempt Chapter Wise Solutions Playlist Link - bit.ly/3AHXgjJ

[@Piyushverma2578]

Sir I take your paid course and it is very fantastic and distraction free that you said. THANK YOU SO MUCH FOR THIS EFFORT!! 😊

[@Music-SUKOON2006]

😊

[@Nerdiamond]

It's 4:22 am and I'm done for the day (or night). This will be my last late night study session and I'll try to change my sleep cycle, but I'll surely remember these days.....

[@AyushKumar-eh2bs]

Kaise change Kiya bhaiya 😢😊

[@DARKRAI-i5j]

Hmm batayeye

[@AyushKumar-eh2bs]

@@DARKRAI-i5j mera bhi change hogya subah subah thand me half shirt aur lower pahenke running krne jata hu ab 6:30 baje se 7 tk maja aaa jata ha pure body me 🔥🔥

[@DARKRAI-i5j]

@@AyushKumar-eh2bs bro I mean to say that ki late night jaise 4 baje tak kaise padh lete hoo Mera toh 2:30 avg jata hai

[@ao_oxnn]

​@@DARKRAI-i5jsame bro 2:30-3:00 avg hota h 4:30 baje tk padhunga toh burn out ho jayega

[@adrijachoudhury4034]

3 . 5:53 9. 18:00 14 . 28:58 (remember increases BY twice means 3l not 2l) 18. 35:10(from not revised part) 21. 42:34( theory) 22. 42:20

[@shreyansh739]

👍

[@Masooooom]

mai video like karna bhool gai thi phir vapas aayi like karne .....because I thought itna toh kar hi sakti hu,like toh banta hai....he deserves it.

[@paramveersingh9167]

Q2 3:23 silly mistake Q9 18:17 do once again Q10 20:01 once again Q12 23:35 concept Q14 29:15 Q15 30:26 current sensitivy Q17 34:43 do once again Q18 36:36 formula Q22 46:02 confusing #learnlikeneverbefore

[@SanyogShobhit]

2. 3:42 (revise again) 9. 17:55(Va-Vb=E-ir) 15. 29:27(current sensitivity (theta / I) 22. 44:22 ( draw diagram step wise become easier)

[@mohitgoenka99]

very good dear keep learning and solving

[@soumyaverma927]

Q12 23:05 good conceptual one Q13 26:23 tricky one (looks easy) Area kat jayega uppar niche se and only length bach jayega 29:18 increased by teice bola hai dhyan se dekh (Theta/I) = current senstivity Q19 39:27 Q21 theorytical 42:25

[@mohitgoenka99]

well done on completing it keep learning and solving

[@arnavsharma-lm5qm]

POTENTIOMETER:::::::::::::::::::::::::::::Q3)7:45 Q8) 14:00 Q16)30:57 AC MIXED PROBLEM-----Q10) 20:25 REPEAT------------------------------------------- Q1) 2:40 point potential method!! Q9) 19:25 standard que repeated multiple times! Q12)25:30 drift velocity 2 formulas and its relations Q13)27:37 Meter bridge ka very concept! Q14) Length of wire increases type que Q15) Galvanometer ka formula and relations wala que Q18) Bulb que must repeat*** Q22) good que must repeat*** LOOK AGAIN----------------------------------- Q2) 3:50 Q6) 12:20 Q7)13:20 Q17)34:55 for statement 2 Q19)41:00 compare it to connecting 2 resistors together! Q20) 42:10 Q21) Theory que

[@mohitgoenka99]

well done on completing it keep learning and solving

[@arnavsharma-lm5qm]

@@mohitgoenka99 thank you sir!

[@SanyogShobhit]

2. 3:26 (revise again 9 18:03 (Va-Vb=E-ir) 14. 28:23(increase by - length become 3l) 18. 35:06(put values at last) 19. 44:13( revise again)

[@mohitgoenka99]

very good dear keep learning and solving

[@singhranntej]

Q4 7:19 SM - (diff likha hai) Q8 13:40 - potentiometer Q9 17:56 CM - (emf mei pd zero ka mtlb ye ni ki poore circuit mei no current) Q12 22:50 - drift vel Q14 28:00 SM - (increase by likha hai bhai) Q15 29:35 - Concept (galvanomter sensitivtiy) Q18 35:07 - solve smartly , put values in end Q21 42:25 - concept Q22 44:10 - bdhiya ques

[@mohitgoenka99]

well done on completing it keep learning and solving

[@padhaku.neeraj]

1 2:07 easy but see 3 5:45 easy but weak 9 18:06 nice q 10 20:24 AC ke badh 12 23:27 nice 13 26:30 nice concept 15 29:36 new concept 18 39:20 batman cocept + caclution 19 39:44 batman 20 41:52 improve concept 22 47:12 batman

[@user-yk5tv6sl7j]

[2:03] o or vo ke beech me to pura hai [9:58] re do [17:57] re do must late concept [19:05] irms =io/root2 [21:51] do again silly mistake [25:02] repeat silly mistake learn sare formule khol lena contro [26:00] repeat [28:00] drawn out and increased by repeat [30:00] niab=c theta theta /i currrent sensitivity [37:00] common khechna [41:00] repeat new {43:00] length and area volume constant

[@breadman235]

3:28(revise) 5:44(redo) 18:22 (revisit) 21:15 (easy but conceptual do again) 22:46 28:41(tricky) 33:50(just see it) 35:15 (very good tougher side question) 41:25(try again)

[@mohitgoenka99]

well done on completing it keep learning and solving

[@adityathakur011]

potentiometer rev 17:00 and 9:00, meter bridge wala 11:13 ( wheatstone), 40:14 effective conduvtivity is resistance offered are same 43:10 fact based 47:18 patience question

[@S8018-v9f]

25:57 sir, V = I T by ohms law V directly proportional to I .......(Eq 1) And I = n A V(d) e I directly proportional to V(d) ..... (Eqn2) Therefore by 1 and 2, V(d) directly proportional to V

[@anshul4192]

litteraly telling this man is like someone god has sent in these last days for first attempt ab 1st ka toh pta ni dusra attempt toh fod hi denge sir like litterally hats off to ur revision series as well as pyq solvings uh r damnnnnnn awesome sir thankuu soo much

[@anushkanath8741]

for revision 8:30 potentiometer 13:50 potentiometer 24:25 drift velocity bina=k theta implies theta/i= bna/k = current sensitivity 31:00 potentiometer 33:50 ratings of a bulb conductivity (sigma) inv proportional to resistivity (rho) 43:00 facts

[@Diksha-_7000]

35:00 rem❗inv ratio 39:07 redo 41:28 cond inv res 42:18 1 st mrk the pot 47:19 ✅ 43:03 mang cons -R 30:37 NIAB=ctheta c is torsial const,I SENSITIVITY IS THETA/I 29:10 elongatn q me volm ∆ ni krte A*L=v 29:10 r pe R depend nhi krta 24:00 vd =eE/mTou I =nAvd. E -v/l 19:29 chk🚫 1:36 ye yad rkh, 5:10 re chk 20:17 ac me peak i =i./√2 Heat prod-h =i^2Rt

[@shrexeditz_]

Q2 5:19 Q8 15:40 Q13 26:54 Q18 37:00 Q19 40:16 Q22 44:50

[@mohitgoenka99]

well done on completing it keep learning and solving

[@SHIVAPREETHAM]

Current Electricity-REVISE💥 42:27[Conceptual] 18:24[Most Repeated] 20:15[AC] 26:20[Remember IMP] 28:23[Increased BY] 47:07[Length doubles then Area halves] 30:43[Current Sensitivity] 31:46[Potentiometer Resistance and RB in Series] 34:36[V const due to parallel so take v^2/R] 39:00[Bulbs] Thank You Very Much Sir❤

[@TheItachiUchiha_07]

*Timestamps* CURRENT ELECTRICITY Q10 19:43 Peak value wala problem Ac pdho Q14 28:18 language problem Maine length 2x leliya woh 2L + L hogi Q15 29:30 concept problem Current sensitivity = Theta / current and NIAB = C theta Q19 39:27 Easy tha dhyaan rkhna next time R = R1 + R2 Q22 45:20 ye ban gaya tha answer galat tick hogya but acha question tha to ek baar phirse krlena

[@Irkntl-rm8qe]

0:40 silly 18:06 repeating 19:44 AC 28:18 language 30:53 35:08 calc 42:28 correct but gq PM 7:17 13:45

[@rockmohit006]

28:10 very good question 35:14 concept clearing question 42:30 good Ass reasoning 44:07 vv good question

[@mohitgoenka99]

well done on completing it keep learning and solving

[@anish.ee0]

For revision 4:40 ( resistance) 17:55 ( same ques in previous session) 20:33 ( peak rms i) 24:09 ( drift velocity) 27:35 ( metre bridge concept clear) 28:22 ( 🫡) 29:59 ( galvanometer) 35:30 ( power rating) 40:00 (conducting) 44:44 ( beautiful question on resistivity)

[@mohitgoenka99]

very good dear keep learning and solving

[@Shashank-i3x]

3:05 formula based 3:38 left 7:11 ez 8:11 not in mains 9:19 balance wheat stone bridge 10:57 meter bridge 100 cm.. 12:52 ez as f 💀 15:28 not in syllabus 18:03 Stan-Dard 💀 que (redo) 21:17 ez 22:36 unit 🙂 24:53 controversial que 27:33 good question on meter bridge 29:16 R=L^2 30:38 thetha=niba/c 32:33 left 33:55 2nd statement 39:06 ACHA QUE MUST REDO 41:09 calculation 🙂 42:19 circuit diagram 44:45 this question must be solve very very carefully

[@celestia4439]

qno.2 5:10 be careful about multiplying by a constant based on series or parallel connection qno.22 47:15 do again

[@mohitgoenka99]

well done on completing it keep learning and solving

[@abhisardubey7489]

Q2 - silly mistake Q9 - 19:30 Q10 - 20:50 (use Irms to calculate heat ) Q12 - asesertion Q22 - (redo)

[@sanidhyasharmaiitr]

Good

[@bhargavidorle6983]

Revise later: 11:44 Q6 (Remember) R+x 19:46 Q10 RMS concept AC 23:20 Q12 Formulae 26:04 Q13 unable to solve 28:56 Q14 (L+2L) not simply 2L (note: Need to read question more carefully.) 29:41 Q15 formula 35:31 Q18 Easy calculations 42:42 Q21 Conceptual

[@mohitgoenka99]

very good dear keep learning and solving

[@anshika5327]

1:03, 19:50( use i rms in ac source for heat calc), 35:12( lengthy calc se bacho), 40:26 (eff conductivity ke liye equivalent system draw karo then proceed

[@mohitgoenka99]

very good dear keep learning and solving

[@snehakumari4326]

26:24 q13 independent of radius 28:43 increased by 2x not increased to 2x 29:52 magnet q 34:40 q17 silly mistake 38:08 q18 39:32 q19 property write the equations 44:26 q22

[@DefinitelyPrateek]

19:39 27:13 Independent of area 29:36 Conceptual 37:16 40:32 New variety 42:57 Factual

[@Aditya__rajput_]

1:00, 19:09,20:47,23:07,27:38,28:36 mistake,30:18,36:30 kim, 39:32,40:41mistake,43:28kim,44::11imp

[@HX018]

26:00 NTA should be serious about this 😓😓 5 marks can make huge difference in rank

[@themicahbell]

Bhai wo shi h dekh Drift velocity = I / (neA). me sir current ka dependency check ni kiye .... I=V/R. aur kyuko R=pl/A to area cut jayega aur inverse relation with L hi aayega

[@peterparker-17]

yes@@themicahbell

[@kumarabhinav4333]

​@@themicahbellyes same ques asked in 2023 also

[@Karan_Singh14]

​@@themicahbellCorrect Explanation

[@Championaryan.AK47]

@@themicahbell woh sab toh thik hai, Lekin i noticed that only original drift velocity formula was used to find ans.(Vd=eEτ/m) Ig we have to ignore I=neAVd ones.

[@Unkow744]

21:18 peak vlaue current ko rms lo heat solbe krne k leiye 34:55 gud 38:15 bulb 41:30 conduc 42:50 factual last q imp

[@anhad2093]

21:00 rms use kro 27:52 repeat 37:08 revise 41:28 blunder 43:28 goof assertion reasioning 45:31 repeat

[@mohitgoenka99]

well done dear keep solving, learning and revising #learnlikeneverbefore

[@atomsandhormones]

0:42, 20:01, 26:10, 28:06 (increased by not increased to!), 29:33, 35:12 (easier calculation), 39:32 (silly error), 42:30

[@ThermoWrld]

for my revision: 17:56 Great Standard Ques which was asked in my institute test and didn't knew how to solve lol 22:49 Great Conceptual and Controversial Ques but the explanation here is(sir ne nhi bataya) that if we write I = V/R then write R=rhoL/A then Area cut ho jaata hai, which only leaves us with L in denominator. 26:40 Great Conceptual Ques 28:14 Great ques and confusing coz BLUNDER KRDIYA BHAI MAINE 35:05 Easy ques but follow the calculation the way sir showed 39:26 Good ques 42:25 Fact Based Ques(remember this) 44:14 Great ques

[@mohitgoenka99]

well done for completing it keep learning and solving

[@prattyushray]

25:55 Hello sir, My opinion regarding the option B is , drift vel. = I/(neA) drift vel. = (V/R)/(neA) drift vel. = (VA/neA*l*rho) [ as R = rho*l/A] thus A gets cancelled. hence drift velocity *doesn't depend on area of cross section of conductor.*

[@avani6040]

q1 1:51 used eq emf but used v= e-ir instead of just using v = 4 (doubt) q9 18:50 similar type q13 27:17 solved but conceptual q19 41:13 forgot the 2 q22 44:18 good ques

[@mohitgoenka99]

very good dear keep learning and solving

[@AYUSH-tu3gx]

1:00 rev 5:00 dont panic and apply basic conc 10:35 meter bridge 19:00 basics pe khelna hai 20:00 DC to AC rev 22:00 units ka khel 24:00 27:00 aata tha but still rev 29:30 current sensitivity 40:00 aise ques mein diagrams bana liya karo agar atko 42:30 theory 44:03 good ques

[@iamA0509]

3:27 re🔥 15:59 core❤ 20:06 for ac source Irms=i0/root2🤔 22:50 conceptual try once more🥲 27:20 core ❤ 28:28 English wali cheezein dhyan se padho! ⚠️ 30:01 current sensitivity (theta/i)🕸 32:07 dhyaan do🦔 33:36 re🦭 35:16 practice once🦋 43:56 conceptual guess😂 44:14 ek baar aur🐌

[@rahulsumanixdrollno8677]

5:31 redooo 12:23 20:24 alternating source or peak source m i rms values 27:55 ❌ 29:19 39:16 46:56

[@JUSTANSHKUMAR]

19:00 47:11 very good q 22:55 26:11 check 28:10 galat ho gaya 35:41 38:14 very good q 42:30 Factual 44;008

[@rameshwarsahu001]

Thanks sir ❤. Sir no error by nta Q12 25:35 , you proved it in 2023 jan vid at 59:09 by substituting 'I'. #learnlikeneverbefore Q. 18 # 35:10 revisit Q. 19 # 39:26 silly

[@mohitgoenka99]

Very good

[@anilsanjay6353]

in 12th question 25:00 B will not come becoz it is given area of crossection of conductor but actually it should be only area .......

[@gulammustafakhan9835]

20:31 e rms lena h. Also try to solve again 23:09 important based on drift velocity 38:00 calculation mistake 41:27 retry

[@user-lq1eb5nz7l]

25:56 sir B is correct. A is not correct. If we expand the formula for current it comes out to be rho l/A and hence drift velocity is inversely proportional to the square of area of cross section is the correct statement. Kindly let me know about the shortcomings of the approach if any. Thank you

[@brijmohansharma1369]

Yes bro B sahi hoga because If A increase hoga to n bhi to devrease karega which will nulify effect of A and current to same rehta throughout conductor.jaise jaise area of conductor change hoga waise waise n bhi change. Correct me if I am wrong

[@shenlong027]

Sir Looked Kind Of Sleepy But Still He Did The Entire 47 Min Video... Dedication 🔥🔥🔥🔥

[@700me]

[@harshalnikam4258]

19:20 Khela Khatam Supremacy by Mohit Sir

[@premprajapati-kf4nc]

18:14 20:35 imp becoz of my mistake 44:49 26:19 29:22 silly mistake by many 38:17 39:36 imp

[@SyedRizwan-]

For JEE 2025 aspirants.. Potentiometer deleted questions Q4: 7:20 Q8: 13:44 Q16: 30:50 Skip these questions 👍

[@mohitgoenka99]

well done on completing it keep learning and solving

[@aryanarijit]

REVISION QUES. OF JULY 2022 :- ●QUES. NO. 15 [ CURRENT SENSITIVITY] ●QUES. NO. 22 [ 44:00 ] TYSM ❤❤ FOR UR LOVE & SUPPORT 😊❤🔥..

[@mohitgoenka99]

well done dear keep solving & learning #learnlikeneverbefore

[@arthdaware05]

35:07(calculation), 39:30 (new length =2l),44:04

[@eternalmusic8459]

sir 12 wale(25:58) mein hum agr drift velocity ko sirf drift velocity ke ek formula lekar chale i.e. v(drift v)= I/neA ya pe agr hum sab jo parameters puche hain sirf unko manipulate karke formula mein put kare unwanted parameters ko substitute karke then we get the form [ v(drift v)= V/nep(row)l ] yaha pe we can see that for this form the drift v is independent of A and only inversely related to l and p(row) is directly dependent on temp so v(drift v) is inversely proportional to temp and directly proportional to V thereby connecting all parameters asked in the question and proving only statement A and D correct i.e. option B

[@shauryasharma7949]

26:00 Sir, if we write I as V/R and then open R as Rho.L/A, then Area will be eliminated from drift velocity , so how does it depend on area then?

[@swayamclass1185]

Exactly current is a dependent quantity

[@Karan_Singh14]

U r ryt

[@mayukhmandal007]

In Q.12, I=neAVd...then V/R=neAVd....now write R as (rho into length)/area.....u have VA/(rho into length)= neAVd.....now Area from both sides get cancelled....so drift velocity is independant of area.....I think this is the solution

[@nikola6tesla]

👏👏👏

[@Championaryan.AK47]

woh sab toh thik hai, Lekin i noticed that only original drift velocity formula was used to find ans.(Vd=eEτ/m) Ig we have to ignore I=neAVd ones.

[@tony-hh4su]

1:44 did it but a good question 17:54 wasn't able to solve good question kind off new type (to me) 20:29 take rms not peak 23:03 controversial question 26:39 did it but maybe i will forget this if i don't revise 28:17 length is increased by twice not length became twice 35:26 too calculative 39:37 got it wrong 45:39 did it but a good question language wise wasn't able to solve 6 questions out of 22 questions

[@aimiitjee8028]

25:25 Sir B wala galat hoga cuz when we put I=V/R then put R=rho*l/A , A will get cancelled and we get the expression Vd=V/rho*lne hence we can say Vd is independent of the area of cross section

[@pramiladevi3218]

Same😊

[@viratsingh0310]

For 2nd revision - Question - 22 ( good question) Question - 18 ( good methid for less calculation) Question -10 silly mistake on peak current Question - 5 silly mistake thankyou sir #learnlikeneverbefore

[@kanishksaini9610]

0:54,3:21,10:39,18:04,26:04,35:11,39:43--REVISE

[@mohitgoenka99]

well done on completing it keep learning and solving

[@Divyansh-bp8ni]

41:21 good 😊 47:10 beautiful question 🎉

[@prakharsrivastava2267]

4:38 6:35 19:25 20:23 24:33 30:09 36:01 37:10 41:10 44:12 44:59 47:14

[@mohitgoenka99]

very good dear keep learning and solving

[@sadiqahmad2014]

20:30 27:30 29:00 41:00 45:30 circuit analysis and potentiometer not strong

[@ThermoWrld]

Sir what if in 44:14 , we take both length as L1 and L2 for X and Y respectively, Then when we stretch the wire X to W, the Area and Length both will change but volume will remain constant, So we use LA=V which gives A=V/L and when we put it in Resistance of W we get (L)^2 which is basically (L1)^2 and then we equate it with Resistance of Y and then we write the terms in expression of Resistance of X(R1) and Resistance of Y(R2), where we get the expression 4R1=2R2, so we get R1/R2 = 1/2 which is the answer. Sir is this approach correct?

[@SG05153]

At 25:35, B Sahi nahi hoga sir. Agar A badlega to resistance kam hoga jiske karan current bhi same amount mei badh jayega to no effect. E ko V/l wala isliye valid hai kyuki source same hai

[@aimiitjee8028]

Yes we can also put I=V/R then put R=rho*l/A in the formula and we will see that A gets cancelled hence we can say Vd is independent of A

[@pro2006kash]

30/09/2024 Attempted - 18/19 Correct - 15/18 Can't attend 21th assertion reason question 😢 Thank you sir 😊❤ 47:08

[@mohitgoenka99]

very good dear keep learning and solving

[@Aakarsh_Jain_07]

5:34 26:41 44:48 ( 39:26 solid mai bhi aise) 35:13

[@5hanu]

28:20 this question had my brain bawling, I was so confused, thank you for the explanation

[@mohitgoenka99]

very good dear keep learning and solving

[@excited0628]

Thnq sir ❤ Done 🙂 For rev 0:36 gud ques 🔥 18:01 gud ques 🔥🔥 19:40 silly mistake 26:13 gud ques 🔥 28:02 silly mistake 39:26 silly mistake 42:33 gud ques 🔥 44:12 gud ques 🔥🔥

[@mohitgoenka99]

very good dear keep learning and solving

[@ishika_goel]

Bro your comment when translated in hindi😂😂😂

[@shashwatroy3849]

got 18/22 correct Thank you Sir for this beautiful session ❤️

[@dipupathak2024]

0:45 , 3:30 , 10:30 , 17:55 , 19:45 , 22:52 , 26:10 , 28:05 , (29:30) , 33:30 , 35:10 , 39:30 , 42:30 , 44:05

[@rijulsachdeva3513]

1:40 29:36 39:30 42:33 REVISE LATER: 44:15

[@arpitpathak7276]

Sir , with the help of eduniti i am in nit Srinagar (ece) now once again going to follow this channel for get into nit Trichy ❤️ Love you sir 💝

[@shreeyashmishra2120]

is nit srinagar any good? i haven't heard anything good about it

[@ao_oxnn]

3:34 parallel h toh divide ker dena yad seh direct multiply nhi 18:09 silly mistake 22:53 controversial q 26:31 depends on lenght not on radiu 28:53 increased by its original length... Not increase to its original length 29:33 silly mistake 35:09 repeat 42:40 repeat 21:00 rms use kero 45:31 repeat again

[@mohitgoenka99]

well done dear keep solving, learning & revising #learnlikeneverbefore

[@HimanshuSharma39005]

Q01 Q09 *REPEATED* Q12 *CONTROVERSIAL* Q13 *CONCEPTUAL* Q14 *GOOD* *WAY* *SOLVING* Q15 *STATEMENT* *BASED* Q17 Q18 *SMART* *CALCULATION* Q19 *PURE* *CONCEPT* Q21 *FACT's* Q22 Long Que. *But* *very* *Conceptual*

[@TheAishupramod]

Yaay completed the pyqs of current electricity!! Enjoyed solving these questions with you sir! forever grateful. ❤

[@mysteriesworld7027]

44:10 amazing question Completed now 🫡

[@PratikBargal]

Revise 26:26 35:17 Theory 42:41 44:19

[@mohitgoenka99]

well done dear keep solving & learning #learnlikeneverbefore

[@aryangupta2342]

Sir in 1 question me parellel combination me Req bhe to aayega and fir vo potential se earth wale jagha tak current bhe flow karega to effective emf alag hoga plzz reply sir 1:51 ❤

[@deepprajapati2525]

2:22 SIR AGAR QUESTION 1 ME YE CAPACITOR PARALLEL KE BAJAY SERIES ME HO TO KONSA FORMULA LAGEGA??

[@premlingayat-hi4te]

Sir 35:00 que 17 me H=I^ 2 R t bhi hota hai na to uske hisab se 2nd statement right honi chahiye pls explain if possible thanku❤️

[@_Cadet]

19:36 27:27 28:51 silly mistake note :increased by 39:06 41:22 47:21

[@mohitgoenka99]

well done on completing it keep learning and solving

[@shubhampandey3837]

12:00,19:00 ,25:00 27:00,40:00,42:00 redo 28:00 made the same mistake stated by sir 38:00 put data in last 45:00 good qs

[@mohitgoenka99]

well done dear keep solving and learning #learnlikeneverbefore

[@JARH-2025]

24:05 but in thermodynamics relaxation time is directly proportional to temperature then it should increase with temperature

[@GlowinJEEaspirant-l5u]

13:32 19:37 must revise 27:54 30:43

[@mohitgoenka99]

well done on completing it keep learning and solving

[@shikhar_2209]

Sir in at 25:20 min in ques no. 12 option B is also wrong B'coz there we can write I=V/R and then R=rho(L/A) so in the final expression Vd=V/rho×n×e×L

[@RimaSingh-l7y]

33:18 lagging in this concept must ⌚ 39:19 calculation 🧮

[@RandomRandom-h3c]

25:00 sir second equation me I ko V/R likhe aur R ko rho(l)/A likhe to A cancel out ho jayega

[@Memer09157]

I think sir in q:12 Drift velocity should be independent of A in case of conductor, because it has electron cloud or charges spread on surface Maybe isiliye nta ne.. nhi rakha ho 25:42

[@yashnamdev4015]

It's 2:46 am and july 2022 current electricity pyqs done ✅ Thank you so much sir for this amazing session ☺️

[@tsushma07]

And now I am your biggest fan. . Because you are real hero of all students thanku so much sir 🧿

[@mohitgoenka99]

#learnlikeneverbefore

[@sardarji162]

At 39:18 laajawab sawal and approach reducing calculation

[@mohitgoenka99]

#learnlikeneverbefore

[@shauryasharma7949]

Solved in time bound manner (50 min) Wrong Qn- 1(Absent minded, in E equivalent did not divide by r) Qn10( In case of A.c current I rms is used) Qn 18( stuck in calculation) Qn 19( Did not take effective length as 2L

[@Hutao0099]

Day 9 Day6,7,8 - completed wpe revision with imp pyqs will do 2022-2024 after revising com, rbd + completed current electricity module + lecture + imp pyq Day 9- Wrong - 9,17,22 Rest done

[@mohitgoenka99]

very good dear keep solving and learning

[@bhumika2082]

For personal revision ques.12 ( just see the relation) ques.13 ( balancing length does not depend on radius if area is uniform) ques.14 (just revise once) ques.18 (put the values at last)

[@mohitgoenka99]

very good dear keep learning and solving

[@NatikSangwan-b8w]

Sir bohot hi ajib lag raha ha padha nhi ja raha tha isliye socha aapke sath pyq hu solve kar lu sir you gives very positive vibe and very dedicated and motivated at the same time apke jaise toh pata nhi lakin apki ye dedication apne andar lan eki puri koshish karugi may God bless you sir🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

[@mohitgoenka99]

very good dear keep learning and solving

[@VISHALKUMAR-yg1gw]

revision Q: 9,16,18,19,22...Thank you so much sir!

[@shreyansh.ch_]

37:02 what a smart play sir 🫡🫡, isiliye aapke sath que solve krne me mja aa jata hai❤️💖❤️❤️ 47:26 ❤❤ always sir❤❤

[@challengeacceptededunitian7391]

Thank you so much sir for this beautiful video 😊 We will make u proud in jee 2023 😊❤️

[@aliafsar7362]

What happen bro

[@Vishhh_20]

15/18 correct Incorrect ~ 3 ~ 22,14,12 3 out of syllabus Doing pyqs consistently and trying ❤️✨

[@mohitgoenka99]

very good dear keep learning and solving

[@Vishhh_20]

@@mohitgoenka99 thank you sir ❤️

[@absharahmad6847]

Bhai ques 1 ma v° -0=4 kese ho skta hai bich ma ek resistance bhi toh ayega 1/3 ka?? Pls btado bhai

[@ShreshthiGupta8]

@@absharahmad6847 U CAN SOLVE THIS QUES BY USING KCL (CURRENT LAW)