Cycloaddition Reactions: Correlation Diagram Method for (2+2)and (4+2) Cycloaddition Reactions

[@pradhumansinghchouhan9237]

Ap bahut accha padhate ho mam , Thank you

[@NOBLECHEMISTRY]

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[@sree1017-b4f]

Very very excellent explanation mdm.thanks a lot mdm

[@NOBLECHEMISTRY]

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[@al-chemist2682]

Maam first time apka lecture suna good effort. Thank u maam❤

[@NOBLECHEMISTRY]

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[@Amazingjindgi]

Bahut ache explain krte ho mam

[@NOBLECHEMISTRY]

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[@v.j6703]

love you mam love you sooo much🤩😭😭❤❤❤. best explanation ever... tqq soo much..... your hardworking 🙏🙏🙏

[@NOBLECHEMISTRY]

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[@ShivaniPrajapati-p9f]

4n+2 system photochemically allowed kese hai? Bcz ground state ka correlation ground se hi match karta hai

[@sandeepsinghbisht3489]

Very good explanation mam

[@NOBLECHEMISTRY]

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[@krishnakrishna-zf5pz]

EXCELLENT EXPLANATION MAM.. KYA PDF MIL SKTA HAII MAM

[@NOBLECHEMISTRY]

Sorry bachcha.. I don't have pdf

[@dimpleagarwal1020]

Superb explanation. Mam

[@NOBLECHEMISTRY]

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[@rahimtullashaikh1095]

Excellent explanation with proper understanding, mam can you help me for solving the problem for csir net study ,

[@NOBLECHEMISTRY]

Sure beta

[@ankitagaonkar4298]

Nice explanation mam

[@NOBLECHEMISTRY]

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[@DDevi-vk1ne]

Good 👍👍👍

[@NOBLECHEMISTRY]

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[@demirajmusic7744]

Maa'm I'm little bit confused. In 2+2 , I can see that the symmetry of 1st excited state Homo of reactants is matching with symmetry of GS Homo of products. Isn't it? Please explain.

[@NOBLECHEMISTRY]

No beta... You will have to see overall symmetry matching.. Reactant orbitals in first excited state are lower 3 orbitals i.e. Psi 1 psi2 and psi3 star.. Product orbitals are lower 3 orbitals i.e. Sigma 1 sigma 2 and sigma 3 star.. All the 3 orbitals symmetry of reactants is matching with the 3 orbitals symmetry of product.

[@sambahadur-et8ss]

mam in 2s+2s i think wave function 3 and wave function 2 must be reversed coz in 3 there is one bonding interaction btw ++ and - - but in 2 there is no bonding interaction instead there are only antibonding interactions . So plz clearify this mam

[@NOBLECHEMISTRY]

No... Watch it again beta...first We have to see bonding interaction of pi MO.. Then anti bonding interaction of pi MO.. Then bonding interaction of pi star... And then anti bonding interaction of pi star

[@ajedits4805]

Ma'am NET Ki preparation kaha se start kre ....? I am in msc 1st sem. ...kaun kaun sa book padhna hoga maam NET ki preparation k liye ..

[@NOBLECHEMISTRY]

Books to bahut saari hai..tum kaun si branch se start karna chahte ho.. inorganic, organic ya physical..par apne aap padhne se kai baar samjh nhi aata..jab tak ki koi samjhaane waala na ho ..tum koi online coaching join kar sakte ho..isse topics samjhne mei aasaani hogi..phir bhi apne aap hi preparation karna chahte ho to mere paas bhi kaafi material hai ..mai send kar doongi

[@SeemaChaudhary-ht3md]

Good

[@NOBLECHEMISTRY]

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[@statussky9393]

Thanks a lot mam💕💕💕

[@NOBLECHEMISTRY]

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[@debapriyanayak3031]

Thank you mam

[@NOBLECHEMISTRY]

Most welcome,😊

[@cooldude-um5rg]

Notes mil jayega mam

[@NOBLECHEMISTRY]

Notes to hai . Par Pdf banaane ke liye time nhi milta.. Aap screenshot lekar apne notes bna sakte ho

[@Arya-2407]

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[@NOBLECHEMISTRY]

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[@divyatakkar2984]

Maam pls check in 2+2 cycloaddition the excited homo is not matching with ground state lumo..is there any mistake..or I am wrong..pls check?

[@NOBLECHEMISTRY]

In correlation diagram method of cycloaddition we have to match the symmetry of orbitals of reactants and products in the ground state or in the excited state..here symmetry of first excited state orbitals of reactants is matching with symmetry of first excited state orbitals of products..why are u matching excited homo and ground state lumo..?

[@AbdulRehman-rn5sk]

Good

[@NOBLECHEMISTRY]

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