Data Representation - Mantissa And Exponents Part 3 - (A Level Computer Science Made Easy (A2) )

[@jamil481]

Thanks again for this explanation.. It really help me a lot

[@alevelsos]

Happy to help, if you would like, consider subscribing it gives me more motivation to make videos :D.

[@jamil481]

@@alevelsos i have already subscribe

[@alevelsos]

@@jamil481 Thanks a lot mate!

[@jamil481]

@@alevelsos thanks a lot for helping me understand these chapters

[@fatmaelzahraahamdy6462]

explained better than high school teachers and college professors thank you and keep it up

[@HaseebAdnan0]

I love the fact that you don't have 20 hour playlists for a single chapter, many teachers just include all their livestreams in a single playlist and then you don't know which one will be helpful

[@alevelsos]

Yes half an hour is the max I think lectures should take.

[@shumiraigunzo9704]

You made it so easy to understand this. Thank you!

[@erenjaeger380]

ayo thank you so much!!! appreciate it..helped me a ton

[@tbnf21]

Legendary teaching

[@abdullaalkhalifa1195]

Example at 7:16 is incorrect

[@alevelsos]

Hey actually its correct! You can check it here: www.advanced-ict.info/interactive/normalise.html

[@abdullaalkhalifa1195]

@@alevelsos this website gives a different answer also. You shouldn’t convert the integer part and decimal part to twos compliment independently, you should treat it as 1 number

[@alevelsos]

@@abdullaalkhalifa1195 Ah let me look into this

[@elhaambasheerch7058]

Excellent lecture again, do you teach online btw, like class or smth ?

[@alevelsos]

I am planning to hold revision lectures where ill cover all the topics and questions for A2 CS, given I have enough students though. You can join our discord and let me know if you are interested there!

[@alevelsos]

I do so now if you are interested!

[@perfectoctogon2392]

Good job man!

[@daryushzavvar2999]

How did you get to -5/32 answer @12:11??? Not sure how the negative exponent come into calculations?

[@alevelsos]

It's 2s compliment and the most significant bit is 1 so it's negative.

[@daryushzavvar2999]

@@alevelsos so the exponent 1110 is actually -2, does that translate to shifting the binary point by 2 to the left or to the right?!

[@alevelsos]

@@daryushzavvar2999 Nop! Don’t look at the exponents Most Significant Bit, look at the mantissa’s Most Significant Bit.

[@amnesia.-.]

It boggled my mind as well.I have got some crazy number.It seems that when the most left bit of exponent is 1 you are moving the dot of mantissa to the left and you have to find second complement of the exponent as well.So 1110 becomes 0010,so you are moving it 2 digits to the left. Second complement of mantissa is 1010000.Moved to the left two times its 0.001010000,its -2^(-3)-2^(-5) which is -0.15625 the same as -5/32. I am just curious how did you know that that decimal can be represented as fraction -5/32.

[@alevelsos]

Let me explain that last part ( converting decimal to fraction part) in a bit ! It's a part i might have missed including in the video

[@erpktiwari]

Excellent

[@erpktiwari]

Please consider subscribing and sharing

[@hardikchojar9361]

bro aren't we suppose to use a sign bit 1 since its a negative number like we added 0 for the positive number and so our exponent will be like 4 instead of 3 (part of the video: 7.52) just as a question

[@photofarewell9647]

What's the biggest and the smallest negative number we can display in 8-bit mantissa and 4 bit exponents?

[@alevelsos]

Answer at 10:23 , just follow the pattern and reduce the number of bits as you like. (Remember these are not normalised mantissa and exponent).

[@photofarewell9647]

​@@alevelsos Wouldn't that be 0 * 2^7 Isn't the first bit just for sign? Correct me if I am wrong.

[@nightcorelegend2635]

Thank you very much :)

[@alevelsos]

My pleasure I've been able to help!

[@prakharsrivastava4755]

Can you please explain how pi value will be represented in 16 bit (1 bit sign, 5 bit exponent, 10 bit mantissa)?

[@alevelsos]

That is an excellent question, this spiked my interest let me solve it and get back to you asap.

[@prakharsrivastava4755]

@@alevelsos : yes please, it will be very helpfull.

[@alevelsos]

@@prakharsrivastava4755 I got the answer as 0.1100100010 00010 do you have an answer that can be cross-checked from? Also this is not the normalised form.

[@prakharsrivastava4755]

@@alevelsos I don't have any reference answer. But as per my calculation the same is coming.0000101100100100.

[@alevelsos]

@@prakharsrivastava4755 I can post a short video solving this today. Let me know if that would help you.

[@afifrazam6591]

smallest positive floating point is not 00000001 | 1000 as this(mantissa) is not normalised, so it should be 01000000 | 1000

[@alevelsos]

Yes that’s true for normalised, but the all the ones mentioned in the important mantissa and exponents section of the video are not normalised .

[@imangaliqalnazar7766]

How you solve it in 12:06

[@imangaliqalnazar7766]

Ooh I understood, exponent is negative here. So we need to move point to the left not to the right

[@ghulamalilaghari]

Great excellent.

[@abdullahahmed3274]

Very helpful

[@alevelsos]

Thanks! I'm glad you found it helpful!

[@abdullahmunir5882]

Damn bro this was great 🔥

[@alevelsos]

Thanks for your words!!

[@IndulakshmiVG]

How to solve 12.11 this sum ..I dont get -5/32. Can you clarify pls

[@alevelsos]

Its been a while, I wonder how i shifted the binary point in mantissa by 14 as in the exponent, let me get back to you soon

[@Zecos]

@@alevelsos broo its been 7 months you there?? 😭😭😭

[@RJChoi-ii4bb]

are this videos for the latest syllabus 9618?

[@alevelsos]

Yup! I just use old past papers sometimes as they are the same thing and easier to access, I also switch up the order of sub topics at times so its easier to understand. If u think I have missed anything anyways please let me know !

[@rafaelsubhan6530]

You didnt mention negative exponent indices. Work on that please.

[@alevelsos]

Actually a bit confused by what you mean, could you elobrate. (sorry it seems like a simple topic that I should know - but it isn't a part of A-Levels syllabus). Im pretty sure though negative exponent indices require for calculations to be made first, such as 5^-2 would first require the computer to calculate 25 and then its inverse. Point me out if I'm wrong.

[@slushie4376]

hey I appreciate your help but using your negative denary to floating-point method, I cant find the right answers. -3.5 cant be calculated

[@alevelsos]

Sorry for the late reply but I'll make a video for this and solve this problem in it 😃.

[@alevelsos]

Here you go I have something about it here kzbin.info/www/bejne/hnzaoIV5pdJ-nqM