David Griffiths Electrodynamics | Problem 3.18 Solution

[@brandonberisford]

Correction: The integral of two legendre polynomials is actually equal to 2/(2l + 1) given that the two legendre polynomials are the same (Still = 0 if they are different). This would cancel the (2l + 1) term that is in the expressions for A_l and B_l (however, since were dealing with the l = 0 terms in this problem, (2l + 1) = 1 so I got lucky.

[@lordricka.kahinga5096]

Great work sir

[@nl8163]

Hey! I don't really drop comments on videos but I don't see you getting enough comments so I decided to write one. I am really grateful that you did these video series and solved this book. It is helping me a ton during my electrodynamics course. You have made things way easier for me. Godspeed.

[@brandonberisford]

Thank you so much! I really appreciate that, and glad my videos have helped you out. It's been awhile since I've posted and I'm actually doing some review of PDE's/ODE's to get back into the swing of things. I hope to start posting more solutions again starting where I left off in chapter 3.