totally 7 tables should be there isn't it, bcuz acc to the rule many to many relationship has to have a seperate table for relationship as well ryt ?
@laxmisarika23382 жыл бұрын
Not 7 tables..! 7 rules are there!
@santhoshreddy4464 Жыл бұрын
yes I guess u r right at last the final table is wrong I guess Bcz m:n relation have three tables
@santhoshreddy4464 Жыл бұрын
may be total 7 tables
@tushar7305 Жыл бұрын
Also in the subject we should have lecture id and course id
@zainkhanz16 ай бұрын
yes you are right
@dipayankanrar1145 Жыл бұрын
very simple and easy explanation ,its very easy to understand
@stalinanthony8 ай бұрын
Thank you so much maa'm it was very helpful
@rswm939 Жыл бұрын
Superb 😊👍👍... Clear and simple !! Pls make more !
@Crazy_moments_of_footbal-qz1qr6 ай бұрын
you made it absolutely easy madam!!!!!!!!!👏👏👏👏👏👏👏👏👏
@csittutorialsbyvrushali3 ай бұрын
Thanks😊. Keep Learning👍
@Banditxam4 Жыл бұрын
Tq ma'am back paper test hai kal... This video helped me a lot
@chandlerzhao18111 ай бұрын
Very good video and easy to understand! 👍 ! I got a question about the last example, the M:N relationship between the students and lectures, also between the students and courses, but the logical model diagram does not present this. Do we need to present both the M:N relationship when we modling the data?
@vijaykhetre56782 жыл бұрын
Nice teaching 😊👍
@austineodhiambo4095 Жыл бұрын
No questions, superb
@nikhilkamode909011 ай бұрын
Aabhari aahe 😊
@maryamakbar8772 Жыл бұрын
How can we solve if we have both maximum and minimum cardinality
@sakshikhangar48197 ай бұрын
Thank you so much
@csittutorialsbyvrushali3 ай бұрын
Welcome😊. Keep Learning👍
@AnkiitOp2 жыл бұрын
Case 3 and Case 4 way 01 is Similar ?
@binodsadhikari387811 ай бұрын
There must be primary for rollno and mobile no both in multivalued attribute
@mangalwagh8694 Жыл бұрын
Very nice video 👍👍
@Umais_Rasheed24 күн бұрын
6:00 Mam so we ignore the remaning attributes ?
@BluePaneTechnologies-nu4hh7 ай бұрын
great...thnx
@csittutorialsbyvrushali3 ай бұрын
Welcome😊. Keep Learning👍
@LiyaGahnug9 ай бұрын
thank you
@bablutadikonda1812 Жыл бұрын
Here we need to check data redundancy also know then how to check it ?
@isuruanuranga Жыл бұрын
thanks
@subhashthakur7352 Жыл бұрын
Firstly , the relationship is not possible between the entities if there is not even a single same attribute in each entity.
@Ashitha084 ай бұрын
7 tables should be there in the last eg
@Islamic_thoughts3874 ай бұрын
Ma'am Jo ap ny example di table k sth ER diagram ki... Uski statement b bta dein kindly!!???.
@milanstefanovic50905 ай бұрын
Last table is not good, we have 2 M to N relationships, so we should have 2more Junction tables so instead of 4tables we should have 6
@milanstefanovic50905 ай бұрын
Instead of 5 we should have 7***
@IsayaOdongo Жыл бұрын
No 4 Explantion is not clear why leave out emp name,salary dept name
@shivanshusawan4237 ай бұрын
How to get slides
@maazsatti8375 Жыл бұрын
What if there is no primary key?
@nikhilkamode909011 ай бұрын
+1
@MJ.bucketlist_10 ай бұрын
Mam..you left age?
@itsecurity24238 ай бұрын
mam you are confusing the students in explaining rule No4, you are not explaining completely. kindly avoid confusion in your videos plz
@sakshiarya29913 ай бұрын
@@itsecurity2423 bhai confuse ki baat kya dono trike he represent krne ke