DC Load Line and Operating Point of Transistor | Q Point and DC Load Line | Quiescent or Bias Point

[@Ft_Kuttu25]

Thankyou very much sir i have been searching for this topic in so many other channels but i got an idea through your way of explanation sir 🙏🙏🙏

[@schoolofphysics315]

welcome

[@withme5977]

Great explanation ❤️nd I understand very very very well😌 ...........thank u so much for this video

[@betterperson3053]

Sir ur way of teaching is mind-blowing ❤

[@sridharchitta7321]

In the analysis of circuits that make use of resistors, diodes and transistors, it is necessary to determine the operating point (voltage and current) of the device connected in a network, which is made from devices whose parameters are known. It is often necessary to determine voltages between terminals of a network with no current flowing. Consider for example the network which consists of two resistors R1 (terminals marked A and B) and R2 (terminals marked C and D). Their ends (A and D) are connected to the positive and negative terminals respectively of a power supply of 12 V dc. The other ends of the resistors are left unconnected. Suppose that the resistors R1 and R2 are 10 ohms each. What will a voltmeter read if it is connected between terminals A and B? What will be the reading of a voltmeter connected between the terminals C and D ? What will be the reading of a voltmeter connected between the terminals B and C ? Electrostatics and circuits belong to one science not two. To learn the operation of circuits, Current and the conduction process, resistors, capacitors and inductors and how discussing these topics with a unified approach makes it easier to understand how there is a voltage of a single wire connected to one terminal of a battery watch these two videos i. kzbin.info/www/bejne/ioXXpWVul5aXj9E and ii. kzbin.info/www/bejne/bnO0fpKurJeFnNE The last frame References in video #1 lists two textbook 4 includes topics that discuss simple networks and the physical processes which causes the appearance of potential drops. Specifically, in Chapter 3 discussions of load line graphs both dc and ac and their use in fixing the operating points of devices such as resistors, diodes and transistors are included. We continue for now with a brief discussion of the cause of the voltages between the dofferent terminals of the network example in this post. When the network is made, electrons will enter the battery positive terminal and the potential of the resistor R1 would have been raised. The battery positive terminal, would drop in potential due to the neutralising action of the few electrons, but then its chemical action will quickly restore its potential difference (p.d.) to 12 volts. The migration of electrons will stop, when the potential of the resistor equals the battery positive potential. And all this happens within a few picoseconds. There will be a few surface charges on the resistor R1, and these indicate its new status of potential. It should be clear that a voltmeter when connected between terminals A and B of circuit will read ‘0’ volts, because the potential of the resistor R1 and the battery positive, will be the same, namely, 12 volts. In the case of the resistor R2 connected to circuit zero, a few electrons would have entered the wire and the resistor R2 from the negative terminal of the power supply which is circuit zero, making the potential of the resistor R2 the same as circuit zero. There will be a few surface charges on the resistor R2 that indicates its new status of potential. A voltmeter when connected between terminals C and D of circuit will read ‘0’ volts, because the potential of the resistor R2 and the battery negative will be the same, namely ‘0’ volts. The current in the circuit will be zero because of the open circuit. Since the potential of terminal B is the same as that of A, its potential is 12 volts. Since the potential of terminal C is that of the battery negative or circuit zero (terminal D), it is ‘0’ volts. Therefore, a voltmeter connected between the terminals B and C will read the same p.d. as that between the terminals A and D namely, 12 volts. We can allow a current to flow in the circuit by simply connecting a wire between terminals B and C thus, short-circuiting them. The current in that case will be 12 V/(10 Ω +10 Ω) = 12 V/20 Ω = 0.6 amps. The two points marked on the x- (voltage) and y- (current) axes are joined together, and this line is called the “Load line” of the network. The load line is the locus of points, or pairs of voltage and current values for the voltage between terminals B and C and the current in the circuit, when the terminals B and C are bridged by a resistance. The load line is fixed for a fixed power supply voltage and fixed values of resistors R1 and R2. AC load line Circuit analysts usually draw ac load lines during the design phase of transistor amplifiers. In Section 3.4, Chapter 3 of textbook 4 in References in last frame of Video #1 more details including diagrams of the analysis of circuits using dc network load lines are provided. In the question Q.3.1 in the file "Additional Practice Questions for all chapters" in the CD with this textbook 4, a description of ac load lines is provided, which would be useful to read. Space does not permit a full discussion in this post.

[@emma_9629]

Thank you sir. The explanation was spot on🙌

[@tiruveediveeraraghavulu4447]

Sir amaging explanation, sir i am fan of your way of teaching

[@schoolofphysics315]

Thanks 😊

[@Emperor723]

compact & clear, thank you sir

[@SnehaMahapatra-ex3dp]

Thank you sir your explanation is so easier to understand A request is plz make a video on RC couple amplifier

[@vijayadurga2550]

Thank you so much sir.... We need A.C load line topic sir

[@nevinbeno1969]

Thank you sir❤️

[@n.s.shankar]

Simple and fabulous explaination sir ji

[@schoolofphysics315]

thanks

[@nasarathvalishaik4431]

Could u please do video on ac load line also

[@schoolofphysics315]

sure. we will try to cover it asap.

[@onlinecircuitsimulation8774]

Finally able to understand, thank you very much sir. In others videos they don't tell you why it's a straight line.

[@schoolofphysics315]

Thanks. 👍 Share to others.

[@gabrielcavuquila4380]

Thank you so much sir, after one semester, I finally understood this hahaha

[@nasarathvalishaik4431]

Thank u very much sir

[@schoolofphysics315]

Most Welcome 😊

[@santhankumar505]

Super explanation sir

[@schoolofphysics315]

thanks

[@Dispa_study]

So easy ❤️❤️❤️

[@y-a-mmoviemaking8153]

👍

[@TWHICH]

🔥

[@jarvisxu4976]

when Uce=0, Ic=0 according to transistor output characteristics graph, but Ic=Vcc/Rc according to output loadline. Can anyone explain that to me?

[@schrodinger4422]

Sir I didnt get the zero signal thing.....

[@schoolofphysics315]

zero signal means there is no ac input supply. input link is short circuited.

[@KiddoMouni]

Sir please make a new video for all topics Help for future students..

[@KiddoMouni]

Love u so much ❤️ Sir ... Sir aap ab video q nahi banate hai

[@Uniqueinventor]

বাংলাদেশের কেউ কী আছো

[@prasannareddy814]

Super explanation sir

[@schoolofphysics315]

thanks