Demorgan law in Boolean Algebra | Lect 4 | Boolean Algebra in Hindi | Discrete Mathematics Bsc

[@ramankr0022]

sir the "dragon trick" which u shared for distributive law is extremely extremely helpful. really grateful to u sir ..................

[@sigmamaddy007]

I cannot express my gratitude towards you in words sir. May god bless you❤

[@kritikapatil8309]

Wow ek ek point clear ho gye sir se padh k to paper bhi clear ho jana h

[@ItsmeAditya496]

The way of teaching is unforgettable. thanks

[@shikharshrivastava1917]

Thankyou so much sir very best explnation❤️🙏

[@jashandeep7635]

The way you explain the question is excellent 👏👏👏

[@ansh_kulhari_01]

Love you❤ sir unforgettable trick💝

[@thecookingcave]

Well explained 👏 👌 👍

[@rockphoenixyedduofficial6890]

Wow you explain just like a friend and a brother

[@rishabhsinghjadoun9322]

Thank you sir for trick and explanation

[@lavinautani6792]

Thank you for all lectures. But aapne unique representation theorem nhi karaya !?

[@jobansingh1369]

Thnk you very much for your lecture

[@_Jindgi_68]

Thank you sir ji

[@ShivayAbrol]

Sir hum kya direct hasse diagram ki help se proof kar sakte hai de Morgan's law because, jab hum a ka complement (a') waha show kar rahe hai b ko toh bhi automatically b ka complement (b') a hoga according to defenation of Boolean algebra.

[@huehui]

Thank You Sir. Nice Eplaination.🙏🙇

[@4321acb]

Thank you so much u hepled alot ❤️

[@ShashibalaSrivastava-e1f]

Thanks sir😊😊

[@AbhishekSharma-hf9lj]

Thank You sir ❤❤❤❤

[@ramanmittal2311]

Thanku so much sir 🙏🙏🙏

[@ankitrastogi7107]

Thank you for this lecture..

[@purv_vlogs]

Good

[@ajju_jaihind]

wah kya trick hai

[@prernabedla1313]

sir thank you 🙏🙏🙏🙏🙏🙏

[@aishwaryadas2516]

Nice explanation

[@madhavgarg0220]

Nice😊😊😊

[@rukhsatansari2863]

Thank you..

[@abhisheksharma4019]

Thanks a lot sir ❤❤

[@vikramjitsinghsandhu81]

Thnks sir

[@Anonymous-ct8xb]

Nice 👍

[@dancetoyourownrhythm5975]

Thanx.... awesome explanation 👍

[@Kanikasharma536]

he study like we are listen a serious story....😅 but still good explanation

[@jeetharman7425]

Sir , a+1=1 boundedness law hoga na ??

[@Skincare.always]

Same doubt

[@jaydeepmehta5213]

Upper bound always join and its value 1 that's why a+1 =1

[@jaydeepmehta5213]

DAA ki playlist he kya

[@Amaypai2006]

Ooga booga

[@jaydeepmehta5213]

Thanks sir for make it easy

[@musafirfir8886]

Thank you very much for the lecture

[@ramanmittal2311]

Thanku so much sir 🙏🙏🙏

[@ankitapawar7084]

Nice

[@rajnandani569]

Thank you sir

[@ramanmittal2311]

Thanku so much sir 🙏🙏🙏