Demorgan's Law Proof

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Күн бұрын

If you take courses involving set theory you will see this - you will need this - all hail Demorgan and the Laws. Kidding, but this is a nice theorem and a good intro set theory proof. Enjoy!
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Пікірлер: 29

@BriTheMathGuy 4 жыл бұрын

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@kkqum17 11 ай бұрын

But doesnt the union sign mean OR operation? Why did you write AND operation over there?

@Hassanbinaisha 4 ай бұрын

Because x is neither in A nor B or x is not in A and also not in B

@DB-nl9xw 4 жыл бұрын

This is amazing. Simple English for math graduate courses. Please do topology explaining.

@Cat_Sterling 2 жыл бұрын

But how did you go from "x € A' and x € B' " to " x € A' /\ B' "? Shouldn't we use "or" in order to get an intersection?

@ryanjackson0x 2 жыл бұрын

Intersection is AND, so these statements are equivalent.

@roberttoltowicz9452 4 жыл бұрын

Thanks. Can you provide a brief explanation of subset vs proper subset and the notation used for each?

@Shivangvinci 3 жыл бұрын

keep it up you will definitely grow because something is better than nothing

@shiblyhossain6020 Жыл бұрын

Fantastic,!!!!!!! Couldn't thank you enough, sir....

@sreejaGhosh-b6x 2 ай бұрын

There is and and there is also intersection, how this can be correct?

@shadykhatri5668 2 жыл бұрын

Briefly explained Thanks

@i.arcturus 3 жыл бұрын

thanks for this it's super helpful!

@BriTheMathGuy 3 жыл бұрын

Glad it was helpful!

@abbasfadhil1715 2 ай бұрын

Great vid man😊😊

@szshyng5599 Жыл бұрын

This guy sounds so familiar... Khan Academy?

@pranayblue 3 жыл бұрын

I came across this, and had to watch a video

@gowtime 3 жыл бұрын

Great video, I wish you could prove the other law (A intersection B)' = A' union B' This one is trickier for me and is hard to grasp...

@ryanjackson0x 2 жыл бұрын

Taking the second part first, since union is OR, it means that x lives somewhere outside A OR somewhere outside B -- this leaves out the middle. A AND B complement describes this scenario, because x could exist in A or B, but not both.