Design of flanged sections |Concepts Through Questions| CE | By M.K Singh Sir | Faculty MADE EASY

[@10108rahul]

Best teacher of RCC ever 💐🌹

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Dear Rahul, Thank You for your valuable feedback and we would request you to stay tuned to our KZbin channel for more upcoming videos. Regards, Team MADE EASY

[@rajkumar-pk1lm]

My favourite lecturers are swamy sir and M K singh sir very sensitive and sincere towards their profession

[@MADEEASYEducation]

Dear Raj, Thank You for your valuable feedback. Request you to stay tuned to our KZbin channel for more such videos. Regards, Team MADE EASY

[@ashwaniparashar2588]

one of the best teacher 🙏

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Dear Ashwani, Thank You for your valuable feedback. Stay tuned to our KZbin channel for more such videos. Regards, Team MADE EASY

[@kuldeeprajput6475]

Sir u r best🙏i will always remember u in my life👌🙏🙏🙏🙏🙏🙏everytime i learn new things from u

[@MADEEASYEducation]

Dear Kuldeep, Thank You for your valuable feedback and we would request you to stay tuned to our KZbin channel for more upcoming videos. Regards, Team MADE EASY

[@AbhishekKumar-lo8es]

Sir happy to see you again i enjoy ur teaching ♥️🙏🙏🙏

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Dear Abhishek, Thank You for your valuable feedback and we would request you to stay tuned to our KZbin channel for more upcoming videos. Regards, Team MADE EASY

[@riteshkumarroy146]

very good teacher

[@saurabhkumar-cz6jd]

Inspiration to civil engineers thank you sir

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Dear Saurabh, Thank You for your valuable feedback and we would request you to stay tuned to our KZbin channel for more upcoming videos. Regards, Team MADE EASY

[@Civilcracker]

Best teaching skill

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[@kuldeeprajput6475]

Memories ❤🙏namste sir😭❤🙏

[@ashwanisinghofficial]

It was very very helpful sir. Please provide one more on bond and development length chapter,if possible.

[@MADEEASYEducation]

Dear Ashwani, We have made a note of your suggestion and will forward the same to the concerned team. Request you to stay tuned to our KZbin channel for the latest videos. Regards, Team MADE EASY

[@shuvang96]

Sir , to calculate final Mr we can use tension approach as well ? Mr = .87fyAst (d-0.42xu)

[@SanjaySingh-bf1lp]

Best teacher of rcc ..

[@MADEEASYEducation]

Dear Sanjay, Thank You for your valuable feedback and we would request you to stay tuned to our KZbin channel for more upcoming videos. Regards, Team MADE EASY

[@ABHISHEKKUMAR-tg3mp]

Sir each subject ka play list discription box me dalo,taki log asani se lecture dekh sake

[@MADEEASYEducation]

Dear Abhishek, We have made a note of your suggestion and will certainly work on the same. Request you to stsy tuned to our KZbin channel for more videos. Regards, Team MADE EASY

[@chandrashekhar-uz6us]

U r amazing sir ❤️🙏 thankyou

[@cl-b-56sudhakargadade23]

If continuous beam is given in question. Then, for effective width(bf) why formula for isolated T beam is taken??

[@prakash-tn6ql]

s bro .....exactly ......... in question did not mentioned isolated T beam ...... we have to general T beam formula bro.....

[@khushabooshukla1506]

Sir here continuous t beam then why u use formula for isolated t beam for flange width?

[@MKSINGHIESME]

The beam is Isolated beam. A continuous beam may also be Isolated T beam. You need to understand the difference between a simply supported and continuous, that depend on type of support. But Isolated means a single T beam. An Isolated T beam may be simply supported also and continuous also. This question is about a continuous isolated T beam. Watch the video carefully you will understand these differences.

[@SanjaySingh-bf1lp]

Sir pls provide video on water tank and stair case....

[@MADEEASYEducation]

Dear Sanjay, We have made a note of your suggestion and will forward the same to the concerned team. Request you to stay tuned to our KZbin channel for the latest videos. Regards, Team MADE EASY

[@manindersingh-dz4bn]

Jis RCC ko dekh kar darr lagta tha, aap se padhne ke baad usme interest aa gaya🙏🙏

[@MADEEASYEducation]

Dear Maninder, Thank You for your valuable feedback and we would request you to stay tuned to our KZbin channel for more upcoming videos. Regards, Team MADE EASY

[@RainbowStudyCentre]

Thank u sir . Awesome concept.

[@MADEEASYEducation]

Dear Candidate, Thank You for your valuable feedback and we would request you to stay tuned to our KZbin channel for more upcoming videos. Regards, Team MADE EASY

[@adilmansuri8680]

Legend of civil engineering

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Dear Adil, Thank You for your valuable feedback. Stay tuned to our KZbin channel for more such videos. Regards, Team MADE EASY

[@sunandatudu7629]

Thank you sir 😊

[@adeebkamil8203]

Structure analysis k lecture upload kijye sr

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Dear Adeeb, We have made a note of your suggestion and will forward the same to the concerned team. Request you to stay tuned to our KZbin channel for the latest videos. Regards, Team MADE EASY

[@maheshkumar559]

Sir one question on design of double Reinforce beam

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Dear Candidate, We have made a note of your suggestion and will forward the same to the concerned team. Request you to stay tuned to our KZbin channel for the latest videos. Regards, Team MADE EASY

[@engineerali7897]

Thank u sir

[@engineerali7897]

Most talented guru ji of made easy I like your teaching style sir

[@lakshmibai0420]

Sir provide more vedios for civil engineering sir

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Dear Lakshmi, we have made a note of your suggestion and will forward the same to the concerned team. Request you to stay tuned to our KZbin channel for the latest videos. Regards, Team MADE EASY

[@ManjitSingh-ct1up]

🙏🙏

[@amitseth4870]

Traffic engineering bhi upload kar do sir

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Dear Amit, We have made a note of your suggestion and will forward the same to the concerned team. Request you to stay tuned to our KZbin channel for the latest videos. Regards, Team MADE EASY

[@VIKASHSINGH-zk5uv]

🙏🙏🙏🙏🙏

[@MrChandan123]

Sir, question is asking about Continuous T beam, But you solved it for Isolated T beam i.e. (Eff. width of flange), So whole answer is gone wrong. Please clear my doubt, weather i am wright or wrong?

[@MKSINGHIESME]

See the Lo value considered is 0.7 times the effective length of beam that is for a continuous beam. The beam is Isolated beam. A continuous beam may also be Isolated T beam. YOu need to understand the difference between a simply supported and continuous, that depend on type of support. But Isolated means a single T beam. So solution is absolutely correct. Try to understand these points. Go through the video in details with concentration.

[@MrChandan123]

@@MKSINGHIESME Thank you sir. Now its clr.

[@indianxdcuber1004]

@@MKSINGHIESME concepts are crystal clear.thank you sir

[@sudityabhattacharya5423]

Clear sir

[@arpitshukla6154]

Thank you sir

[@avikroy4783]

Thank you sir