DESIGN OF TWO WAY CONTINUOUS SLAB PANELS OF DIFFERENT EDGE CONDITIONS AS PER IS456|LSM | LEC39|RCC

HOW TO DESIGN TWO WAY CONTINUOUS SLAB PANELS WITH DIFFERENT EDGE CONDITIONS AS PER T-16 OF IS 456 2000 USING LIMIT STATE METHOD OF RCC DESIGN AND SP16, HAD BEEN EXPLAINED STEP BY STEP IN THIS VIDEO LECTURE.
TOPIC- DESIGN OF TWO WAY RCC SLAB.
TEACHER- DEBASIS PANDA, ASSISTANT PROFESSOR (TEQIP FACULTY), DEC.
DESIGN OF TWO WAY SIMPLY SUPPORTED RCC SLAB AS PER IS 456 & SP16 | LIMIT STATE METHOD|LEC-37 | RCC|
• DESIGN OF TWO WAY SIMP...
DESIGN OF TWO WAY RCC SLAB| INTRODUCTION| BM & BM COEFFICIENTS| TORSION REINFORCEMENT LEC-36 | RCC|
• DESIGN OF TWO WAY RCC ...
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Link For-------Introduction to Design of RCC Slabs | One way Slab, Two way Slab | IS:456 Specifications| Design Concepts| LEC 32 | RCC |
• Introduction to Design...
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Link For-------How to Design One Way RCC Slabs using Limit State Method as per IS: 456 & SP16 |LEC-34| RCC|
• How to Design One Way ...

[@SanghPath]

back lag jata bhai...tune bacha liya

[@supriyapal1780]

Development Length have to check or not?

[@mustafajarman1331]

Same process for one way slab???? Please reply as soon as possible

[@StructureManiac]

How to Design One Way RCC Slabs using Limit State Method as per IS: 456 & SP16 | Lec-34 | RCC| kzbin.info/www/bejne/iZS4pnWIj9uaZqc

[@souviksaha6408]

If Ast (req) < Ast (min) in that case what should we do ?

[@StructureManiac]

In that case you need to provide minimum reinforcement. If the minimum reinforcement also violates the maximum spacing criteria of main parallel reinforcement of slab, then you need to provide the reinforcements as per maximum spacing criteria of main reinforcement of slabs (As per IS456:2000).

[@harishjoshi1139]

Have you done interior panel design?

[@StructureManiac]

Yes, it's quite simple, you just need to calculate the values of negative BM coefficients along the shorter and longer directions from Table 26 of IS 456, then calculate negative BMs along shorter and longer directions, then follow the steps to complete the design. As its interior panel, all four edged are continuous, you don't need to provide torsional reinforcement. The detailing part will be different. Just go through the detailing of the two-way continuous slab, you will understand.

[@harishjoshi1139]

@@StructureManiac thanks for the response. I understood.

[@aibansharailyngdoh8608]

Where is the final diagram,without diagram is incomplete

[@nithinms2704]

What if 2 long edge discontinuous What is the value of Alpha X ?

[@StructureManiac]

if two long edges discontinuous, you will find the value of positive alpha x from table-26, pg no-91 of IS456, condition-6. Then calculate positive bending moment at mid span along x-direction, and negative BM along y direction and follow the steps to complete the design.