Determinant and area of a parallelogram | Matrix transformations | Linear Algebra | Khan Academy

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Realizing that the determinant of a 2x2 matrix is equal to the area of the parallelogram defined by the column vectors of the matrix
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Пікірлер: 30
@khanacademy
@khanacademy 15 жыл бұрын
Thanks. Appreciate your appreciation :)
@PederBHellandMusic
@PederBHellandMusic 8 жыл бұрын
Thank you very much! Great video.
@davidmurphy563
@davidmurphy563 3 жыл бұрын
This seems overly complex. Surely it's just: 1. p = v2.dot(v1) 2. v3 = v1 * p 3. H = v2 - v3 4. Area = v1 * H
@gracepointks
@gracepointks 12 жыл бұрын
Sol, others may have told you this, but I treat your sessions like my DVR. Sometimes I stop you and start over, sometimes I pause you to think about what you have said, sometimes I rewind you a little bit to just confirm what you said and how I thought about it. Also, I sometimes go to other videos that you refer as you go along!
@D0g63rt
@D0g63rt 12 жыл бұрын
But how do you prove the cross product then? Do you simply accept it as given or do you wonder where the algorithm for cross product comes from?
@masterslayer111
@masterslayer111 13 жыл бұрын
do you teach math? if not you should
@IrishBog
@IrishBog 3 жыл бұрын
So many videos on KZbin just compute this as a given..... it's not intuitive at all that the Det should match the volume but you actually worked it out by hand.... amazing
@warrenchu6319
@warrenchu6319 4 жыл бұрын
Some teach forming matrix A by using V1 and V2 as row vectors instead of as column vectors. But the determinant of A is the same. Same for 3x3 matrices: det [A] = det [A transposed].
@akshaybodla163
@akshaybodla163 4 жыл бұрын
For anyone watching this now, if know a bit of calc iii or vector algebra, you can prove ad-bc right from the beginning. We know that the area of the parallelogram is the cross product between the two vectors, in this case v1xv2 which equals x. Since the cross product is more intuitively defined in 3d, then we can write x. We get the terms (0-0)-(0-0)+(ad-cb)=ad-bc. Therefore, the determinant of a 2x2 matrix is ad-bc.
@BaLiMultiwude
@BaLiMultiwude 10 жыл бұрын
if you are interested, proceed to develop volume of parallel-piped and other solids area, volume...using that of determinant directly.
@MercerBay
@MercerBay 7 жыл бұрын
Very helpful, thanks!
@sputternik8
@sputternik8 14 жыл бұрын
It seems to me that this can also be proven using the cross product. It was earlier shown that the area of a parallelogram is the length of its vectors' cross product, and the cross product of two R3 vectors is the vector (a2b3-a3b2 , a3b1-a1b3, a1b2-a2b1). If you regard two R2 vectors as R3 vectors with zeros for their third elements, then it simplifies to (0 , 0 , a1b2-a2b1).
@farhad14
@farhad14 14 жыл бұрын
thanks aloooot i learn frrom ur videos much better than books please keep on. espacially on engineringfield.
@nachocab834
@nachocab834 15 жыл бұрын
This is really helpful. Thanks a lot!
@bewarethebeef1
@bewarethebeef1 12 жыл бұрын
mind = blown
@charl160
@charl160 Жыл бұрын
Excellent video, thanks!
@beta5770
@beta5770 12 жыл бұрын
Yes. You do know that u derive the cross product of two vectors by constructing a parallelogram
@Michelle930911
@Michelle930911 11 жыл бұрын
its is good, but the calculating process is wayyyyy tooo slow! i m assuming ppl here are uni students
@yustinayasin5539
@yustinayasin5539 3 жыл бұрын
wow you're genius, respect!
@Syeal7
@Syeal7 11 жыл бұрын
Did not just interpret your comment sexually. No, I did not.
@beta5770
@beta5770 12 жыл бұрын
Wow... I never knew how the determinant of a 2x2 matrix is ad - bc. Thanks!
@Waranle
@Waranle 15 жыл бұрын
Thank you Alot, for taking some time to do all these videos, i really do appreciate :)
@ingenierox
@ingenierox 13 жыл бұрын
Thanks a lot it's very helpful
@rameshmungamuri36
@rameshmungamuri36 8 жыл бұрын
i want proof area of the triangle in vector not problem
@magnus__reeves
@magnus__reeves 6 жыл бұрын
lol English
@lafyguy
@lafyguy 12 жыл бұрын
harry - problem
@beta5770
@beta5770 12 жыл бұрын
somewhere else as in?
@jonabirdd
@jonabirdd 7 жыл бұрын
This is a ridiculously stupid method for computing the area. You could do it in 1/4 the time by subtracting the area outside the parallelogram from the rectangle perpendicular to the coordinate axes that bounds it.
@debendragurung3033
@debendragurung3033 7 жыл бұрын
This is in the context of linear algebra and will be applicable later. Sometimes Maths is also about proving 1+0=1 but in higher dimension
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