Determinate vs Indeterminate Structures - Intro to Structural Analysis

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Structures with Prof. H

Structures with Prof. H

Күн бұрын

Пікірлер: 47
@The_Civil_Lab
@The_Civil_Lab Жыл бұрын
I can't believe I finally found a youtube gem about civil... I've been struggling to find resources, the domain seems void of sharing intellectual knowledge! Thank you sir.
@StructuresProfH
@StructuresProfH Жыл бұрын
Glad I could help, and welcome aboard!
@islamqa5165
@islamqa5165 Жыл бұрын
You have a really good natural talent to teach.. it is surely making you feel better that you are helping and serving to students... May Allah bless you.
@StructuresProfH
@StructuresProfH Жыл бұрын
Thank you!
@offthegridengineer2198
@offthegridengineer2198 3 жыл бұрын
I greatly thank you for these videos. They are extremely helpful!
@StructuresProfH
@StructuresProfH 3 жыл бұрын
You are welcome!
@gecaprathamesh6583
@gecaprathamesh6583 Ай бұрын
Amazing explanation for determinacy formula of truss!! Never had this clarity before 🙏🙌
@jiteshyar1218
@jiteshyar1218 9 ай бұрын
How hard work have done during explanation can be easily noticed Really great 👍
@zxzhan5287
@zxzhan5287 Жыл бұрын
Great and straightforward revision before my structural analysis final exam
@StructuresProfH
@StructuresProfH Жыл бұрын
Yep, that is the goal here. Glad you liked it!
@Harry-qc6ny
@Harry-qc6ny Жыл бұрын
Your teaching style is amazing, very clear, straightforward which confuses me less. Cheers :)
@StructuresProfH
@StructuresProfH Жыл бұрын
Thank you! I'm glad this was helpful!
@anarmyoftigers
@anarmyoftigers 2 жыл бұрын
Great video. You explained it well and I’m happy to have learned something.
@StructuresProfH
@StructuresProfH 2 жыл бұрын
Glad it was helpful!
@ScottESchmidt
@ScottESchmidt 4 ай бұрын
I never learned this method in engineering school, but I can say that most civil engineers with experience and all structural engineers can generally look at a structure like this and determine if it is either statically determinate or indeterminate by inspection. Knowing the degree to which it is indeterminate is interesting, but in practical application, most engineers will just plug it into their computer and let it do the hard part. Thank you again for an excellent video.
@MecTudor
@MecTudor Жыл бұрын
Hello, what about those systems where DoI=0, but you can't solve the reactions? (the critical ones)
@luziya7486
@luziya7486 8 ай бұрын
This is my question as well
@MecTudor
@MecTudor 8 ай бұрын
@@luziya7486 These systems are very dangerous (they allow some displacements nearby the position of equilibrium and the magnitudes of some reactions are tending to infinite) so you have to avoid them. The problem of recognizing the critical forms is a serious problem.
@ronyshamcghee6927
@ronyshamcghee6927 8 ай бұрын
How do you know at what points equilibrium can be considered for the trusses example?
@PunmasterSTP
@PunmasterSTP 3 ай бұрын
Determinate? More like "Definitely awesome; thank you mate!" 👍
@felixcsgocs2
@felixcsgocs2 2 жыл бұрын
Beautifully explained
@StructuresProfH
@StructuresProfH 2 жыл бұрын
Thank you!
@MohamedAli-fo3xb
@MohamedAli-fo3xb Жыл бұрын
THANK YOU FOR HELPING ME WITH THESE VIDEOS
@StructuresProfH
@StructuresProfH Жыл бұрын
Glad this was helpful!
@burhanuddinmotiwala1428
@burhanuddinmotiwala1428 7 ай бұрын
for the last example if there were no hinges in the frame then would it be indeterminate to the fourth degree?
@StructuresProfH
@StructuresProfH 7 ай бұрын
That is correct!
@stevenpro7321
@stevenpro7321 2 жыл бұрын
Thanks for sharing, it really helps. May I ask a question for the last frame, if there is only one hinge in the middle on the top how could I make the cut?
@StructuresProfH
@StructuresProfH 2 жыл бұрын
Great question, because this can get a little weird. Two cases to clarify here. (1) If the middle column only has a hinge on one side (instead of hinges on both sides, as shown in the video), then you would only need to make a single cut on the side with the hinge. The degree of indeterminacy would then be: 7 reactions + 6 internal forces - 3*(4 FBDs) = 1... meaning the frame is now indeterminate. (2) However, if both beams and the middle column all come together at a single hinged point, that's a bit different. This moment release is now applied to all three members, unlike in Case 1 described above where the hinge-to-the-side only affects a single beam and the column. To "cut" this, you'll separate all three members that connect into this hinge from each other. Once you've done that, you will have identical free body diagrams as in the video, so the DOI is still 0.
@stevenpro7321
@stevenpro7321 2 жыл бұрын
@@StructuresProfH It makes perfect sense and thank you for the explaination.
@harisshakoor79
@harisshakoor79 2 жыл бұрын
extremely helpful sir. very well explained. Thanks you sir
@lazyyan2918
@lazyyan2918 3 ай бұрын
I learned something today : )
@bekehbenjamin775
@bekehbenjamin775 6 ай бұрын
Does it mean that when ever your calculations gives you zero as an answer, it shows that the trusses is determinate?
@StructuresProfH
@StructuresProfH 6 ай бұрын
Yep, zero means determinate (unless there is some other issue that causes instability).
@salemsimeon7471
@salemsimeon7471 Жыл бұрын
Thank you. It was really helpful.
@clanwarme6152
@clanwarme6152 Жыл бұрын
I don't understand the frames.. Is there any other simple way..?
@StructuresProfH
@StructuresProfH Жыл бұрын
There is an equation too. For two-dimensional frames, the Degree of indeterminacy (DOI) can be computed as: DOI = Reactions + 3*Members - 3*Connections - Releases ... where ... Reactions is the total number of reaction forces or moments Members is the total number of members (beams, columns, whatever) in the structure Connections is the total number of connections between members (including connections to the ground) Releases in the total number of hinges, expansion joints, etc. in the structure
@joealex2463
@joealex2463 7 ай бұрын
how do you find r?
@StructuresProfH
@StructuresProfH 7 ай бұрын
"r" is the number of releases, where a release counts as a single known internal force. So for example, a hinge in a beam forces the bending moment to be zero at that location - that counts as one release, because we know that M = 0 at that point. You can also have releases for shear and axial forces as well. These can even be combined. For example, a roller-like expansion joint in a bridge might count as two releases if both the axial force N = 0 and the bending moment M = 0 at that location.
@joealex2463
@joealex2463 7 ай бұрын
@@StructuresProfH thank you!
@romarssieverything9667
@romarssieverything9667 2 жыл бұрын
thank you! You made this so easy.
@ferozpatthan
@ferozpatthan Жыл бұрын
Very Nice explanation ...
@StructuresProfH
@StructuresProfH Жыл бұрын
Thank you! I'm glad I could be of service.
@shivasalehi2199
@shivasalehi2199 Жыл бұрын
Thank you🙏🏼🌺
@StructuresProfH
@StructuresProfH Жыл бұрын
You are welcome!
@Tankaxattri403
@Tankaxattri403 Жыл бұрын
Nice🎉
@SrilankanProud1
@SrilankanProud1 Жыл бұрын
Thank you
@StructuresProfH
@StructuresProfH Жыл бұрын
You're welcome!
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