linearsecondorderconstantcoefficienthomogenousequation hahaha keep up the good work
@uselessdiscussion73555 жыл бұрын
This right here is crazy lol I think it's starting to make sense. Because it's linear, it's actually just like taking the differential equation evaluated at y1, and adding that to the differential equation evaluated at y2. Since each is a solution, each differential equation itself is 0 = 0, and so that equation plus itself is still 0 = 0 and is still totally a solution/valid. Wow!
@TheLazyEngineer5 жыл бұрын
Useless Discussion exactly!
@mohfa18062 жыл бұрын
Thank you for your great videos I have question : if we look at it geometrically then Y1 and Y2 and Y=Y1+Y2 are three different functions that satifies our differential equation , so we will draw three different functions that are totally different when C1 and C2 are non zero . Accordingly how Y includes Y1 and Y2 knowing that graphically they are totally different functions ? Thank you
@Ahmad-gn1pd5 жыл бұрын
To be able to put two intial conditions
@senurahansaja32874 жыл бұрын
What if one solution is zero, then do we need to write it as y= c1 + c2e