Direct Memory Mapping - Solved Examples

COA: Direct Memory Mapping - Solved Examples
Topics discussed:
For Direct-mapped caches
1. How to calculate P.A. Split?
2. How to find out Tag Directory size?
3. Significance of Tag bits & unique method of calculating the number of Tag bits.
4. How to find out Cache size?
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[@AnuthaOneShields]

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[@rahulsyt_]

Same thought!

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Actually same ......

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R u donating now?

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My confusion is never ending on why these youtubers can explain these difficult stuff in very clear and concise way, while our university lectures suck at it.

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man this seems to happen in every country, mine isn't exception too. The lecturer is atrocious!

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Having worked as a teacher professionally, I can tell you that most teachers do not (a) find the time/energy to make their educational content in this way (I can imagine each short video on this channel took 2 hours to make i.e. a university lecture = ~8 short videos = 16 hours of effort vs 1.5 hours of plain lecturing) and more importantly (b) fail to place themselves in the shoes of the learner i.e. as a beginner (this is called expert blindness). In practice you need someone crazy enough/talented enough to make content like this --- imagine taking 2-4 hours out of your day to make this powerpoint a 10 minutes video? and/or an economy of scale.

[@fianyeku-kokonumichael4182]

@@willemhekman1788 well said

[@vedantvyas2979]

Maybe it's because in lectures we're not paying same amount of attention as we do while watching the video. Other reason is most of the professors are in college just to do their research and they're not interested in teaching

[@siddharthmagadum16]

third one can be done by 2^#tag bits= MM size/ Cache size , we know MM size and Cache size

[@sherazarain871]

Great explanation in just 10mins. keep it up. I recommended this lecture series to my children's XD

[@TheChargingCap]

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[@mustafaincheema2097]

Thanks!

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[@asterdogma]

Right on time for my exams

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Thank you so much!!!

[@mrincognito2371]

you made this so easy to understand, thank you sir!!

[@krambow1509]

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[@jishanbukhari223]

Very well explained. Thank you so much 🙏🙏

[@bob461]

Very informative and amazing lecture. Can you please suggest a good book also for computer architecture and to solve more numerical based problems like this

[@rahulsyt_]

Bow down 🙇🏻‍♂️ to him ❤

[@geheron1946]

You saved me, LOVE YOU ❤️

[@VinyZikss]

Awesome video and teacher. Thank you so much for these easy-to-understand videos. There's one thing I haven't understood, isn't 1Kb the same as 1000 bytes, and not 1024 like in your examples? I thought 1Kib was 1024 bytes

[@sinekad5132]

Thank you sir❤

[@shubhamdas6519]

Thanks for the video sir ....

[@onlyintellectuals]

so tag bits represent the log(times the cache would fit in the ram). if ram is 4 times the cache size, then the tag bits are 2. in above case, 2^10 times x cache size = ram size. therefore. cache size is ram size/2^10= 16 x 2^10 x 2^10 x 2^10 bytes. = 16 MB.

[@gourisworld4081]

Amazing🙏

[@angel11always]

my head hurts

[@himanshurana5880]

8:07 Consider a main memory of the size 64 kB with each word being of 8 bits (one byte) only and a direct mapping Cache memory of size 4 kB also having data word size of 8 bits. Find the following : (i) What is the size of tag and index fields of cache ? (ii) In what location of Cache, hexadecimal address to main memory (AABB) (if exists in cache) will be located ? can anyone solve this question..? @Nesco Academy can you solve it..?

[@kedharguhan]

Without knowing block size, I am gonna assume arbitrarily that it is 1kB. So 10 lines for block offset, and 4 lines in cache. So AABB will be in line#1 of cache since AABB ends with 01. If you take a different block size, AABB will still end up in line#1 (01) but there may be more lines in the cache.

[@anjaligupta-ew6ns]

Please complete lecture video on Compiler design plsss sir really need

[@himanshurana5880]

Consider a main memory of the size 64 kB with each word being of 8 bits (one byte) only and a direct mapping Cache memory of size 4 kB also having data word size of 8 bits. Find the following : (i) What is the size of tag and index fields of cache ? (ii) In what location of Cache, hexadecimal address to main memory (AABB) (if exists in cache) will be located ? what's answer of this question, can anyone tell..?

[@kamikamen_official]

For the last one, while I at first failed monumentally, after rewatching the video (and hopefully understanding better) I realized (to me at least) there's a simpler way to find the cache size. You are told the # of tag bits is 10. So you know you need 2^10 different tags, and by the same token that the cache fits 2^10 times into the MM. So you get this equation 2^34/2^x = 2^10. Since you know algebra, you know you can convert the system to (just use exponent laws) 34-x = 10. Solving for x you get 24.

[@livesdebug8225]

where can i find your course ppt or pdf ? can you share it? thanks

[@ritamghosh7622]

MM size = 4GB =2^2*2^30Bytes=2^32bytes=2^32*2^3bits=2^35 bits right?

[@nibirbaruah938]

have the same question man

[@Masakkalii]

Got it

[@anonfromearth]

So basically, the number of caches that can be fit in main memory = number of blocks that can fit in a cache

[@Plutonium_357]

WORD is 1 or 2 Bytes?

[@ishuanand4840]

i dont know why but the concepts are not clear might be too much vagueness is there..i have been watching neso for a long time now but only this time i m left with the doubts.

[@sunyuting7330]

example 3: 10 tag bits..... So 2*34/2^10 = 2^24 =16MB. no need other info i think

[@durasaksham]

I didn't get the concept of tag directory. Can anyone help me out?

[@oualidlaib5965]

the same

[@rajarshimondal1343]

you should have taken one example for word size != 0 that would be much helpfull

[@rahulchattopadhyay226]

Totally confused very confusing

[@thecritiquer9407]

❤❤❤

[@EzeroXP]

Screw it. Im'm going to fail

[@jurin8230]

+2

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Us b

[@sachinsudaraka6397]

❤️

[@annafebland4460]

8:44

[@mdshahnawaz645]

👍

[@sweetjimmy]

Hey! I noticed one thing that size of cache is equal to the no. of blocks in MM. Is this true for every computer?

[@kuntalbatabyal6676]

First viewer.. 👍🏾

[@VasuVijay-g1o]

quite bit confusing😂

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hates off

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hates off

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Its 'hats off' brothers 😭

[@yutaitadori7318]

This playlist is progressing too slow.If possible please fast a little bit.

[@asherhabib5276]

disliked because of cringe voice. taking lecture at 3 in night for exam at 8 and this boy sound so cheerful

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lollllllllll how did it go, i know im 2 years late but idc

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You're too quick, slow down

[@baloneypopo9609]

👍