here in sucrose there will be alpha-1,beeta-2 glycocidic linkage , not alpha -1,2glycocidic linkage. i was searching for my IIT jee ques but on youtube there is no any clear concept .
@shahryarmasood2602 Жыл бұрын
Yeah
@UsmanKhalid-cy6ue Жыл бұрын
Yes it is called alpha 1 beta 2 glycosidic linkage
@mila_beiseiku4285 Жыл бұрын
There's a mistake on the Haworth-projection of Fructofuranose. As seen in Fischer's projection, by completing the mechanism building the furanose ring, the C2 atom should have the C1-H20H, the intremolecular etherbridge (the O between C2 and C5), the bond with C3 and instead of, as shown, a bond to H, it has to be a hydroxy group.
@gnomon1957 Жыл бұрын
Wasn't Galactose Doctor Who's home planet?
@ugwuokechinedu83937 ай бұрын
Thanks mam😀 God bless you
@mariociencia124 жыл бұрын
The structure of fructose are shown wrong, since in C2 of fructose the CH2OH should be below (alpha) and the OH should de up (beta)
@fridericusrex98124 жыл бұрын
No, fructose (D-fructofuranose) in sucrose is shown correctly in the video. The furanose ring is simply shown flipped along the y-axis so that all the substituents pointing up are now pointing down, and all the substituents pointing down are now pointing up. By the way, the alpha and beta designations have nothing to do with whether OH (on C2) is pointing up or down. Rather, alpha denotes the OH (on C2 in the case of fructose) is trans from the CH2OH on C5, and beta denotes the OH is cis. For example, alpha-D-fructofuranose means OH on C2 is pointing down since CH2OH on C5 is pointing up in the D- enantiomer, thus making the OH and CH2OH trans. Beta-D-fructofuranose means OH on C2 is pointing up so that it is cis relative to the CH2OH on C5. However, if we are dealing with alpha-L-fructofuranose, CH2OH on C5 is pointing down, so OH on C2 must point up in order to be trans. And likewise, in beta-L-fructofuranose, OH on C2 points down in order to be cis.
@akashseenu11384 жыл бұрын
@@fridericusrex9812 thank u so much i was very confused abt it but now i am clear
@akashseenu11384 жыл бұрын
@@fridericusrex9812 likewise is there any cis ,trans in glucose?
@fridericusrex98124 жыл бұрын
@@akashseenu1138 Yes, the ring form of glucose can either be trans (alpha anomer) or cis (beta anomer).
@akashseenu11384 жыл бұрын
@@fridericusrex9812 how can i find that pls teach me
@ronaldrams54853 жыл бұрын
YOU ARE THE MAN
@phenomenalphysics35484 жыл бұрын
What is difference between alpha and beta 1-4 glycosidic Bond?
@mariusmorin-pauletto34324 жыл бұрын
i think that's the positioning of the first Carbon, as said at 1:03. you might check tho
@mila_beiseiku4285 Жыл бұрын
While in a ring configuration (Haworth-projection), the C-1-Atom is chiral. It has four different substitutes around itself, so no matter how you turn it, the order will always be the same. Alpha and Beta are different orders of the substitutes, thus they cannot look the same simply by turning. In order to differ these two orders, there's the alpha-beta-nomenclatur.
@UsmanKhalid-cy6ue Жыл бұрын
Simply we count first rings first carbon OH if first ring molecule is alpha then we name it alpha if first is beta then we called it beta
@mylittleworld49213 жыл бұрын
Sir it's very helpful.....simply u explained...
@tharinduwijerathna20293 жыл бұрын
Thank u 😍🙏🙏
@sahanav7093 Жыл бұрын
Pkease make a video about disulphate bond
@mariociencia124 жыл бұрын
Fantastic! Incredible! Marvelous! Wonderful!
@wing_your_dreamz4 жыл бұрын
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@monicamunyandi28872 жыл бұрын
Thanks for the video
@skuplkl4 жыл бұрын
Can I get a respons why ? It shuden be like that right ? Allso it shud be a OH at 5 that shud be number 2 right
@asalaabuabed98924 жыл бұрын
thank you for the helpful video. I have a question: so In disaccharides if any of the monosaccharides has an aldehyde or a ketone group we say the the disaccharide is a reducing sugar right?i mean not necessarily both should have it...
@mila_beiseiku4285 Жыл бұрын
What matters is, that there is a reducing group free at any end of the molecule. Mattter of fact, I think (at least with conventional sugars) it is not possible to form a glycosidic bond and keep the reducing properties of both monomers, since one of them is needed to form the bond. Thus, it only is important wether the end of a disaccharide has reducing properties.
@hasnain99264 жыл бұрын
Thanks alot❤
@crazyshitified41553 жыл бұрын
Awesome class👍
@Jason-o5s4 ай бұрын
Cheer~~any of a class of sugars whose molecules contain two monosaccharide residues.😊
@Deepak05973 жыл бұрын
Superb
@saumyaagnihotri75885 жыл бұрын
Gr8
@skuplkl4 жыл бұрын
I can only se 5 O on the Fructose ( Furanose) struktur and 6 on the Linear ? WTF
@skuplkl4 жыл бұрын
Can I get a respons why ? It shuden be like that right ?
@mila_beiseiku4285 Жыл бұрын
Nah, you're right it shouldn't. the video's missing an O... C2 should have the intramolecular ether bridge, the bond with C1 / C3 and an additional hydroxy group instead of an H. Took me a while, too
@lorrymaecadagat11239 ай бұрын
Ginoo ko😭😭😭
@sanjykumarmishra13655 жыл бұрын
Helpful
@tiyabanerjee05094 жыл бұрын
Why are you faking an accent and talking like this ?