Divergence Theorem example: Flux across unit cube // Vector Calculus

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Dr. Trefor Bazett

Dr. Trefor Bazett

Күн бұрын

In this example we use the divergence theorem to compute the flux of a vector field across the unit cube. Instead of computing six surface integral, the divergence theorem let's us compute one triple integral of the divergences of the vector field over this unit cube.
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Пікірлер: 37
@Sasuke-Uchiha
@Sasuke-Uchiha 3 жыл бұрын
bro, you just came in real clutch for my final later today
@DrTrefor
@DrTrefor 3 жыл бұрын
hey nice! Hope it went well:)
@alfredandens7911
@alfredandens7911 Жыл бұрын
Thank you brother, the whole serie have helped me a lot.
@michaelwinder7879
@michaelwinder7879 3 ай бұрын
You are a legend! These videos have carried me through my Calc 3 class
@nat6429
@nat6429 2 жыл бұрын
This was really helpful and clear, thanks so much!
@ManojKumar-cj7oj
@ManojKumar-cj7oj 3 жыл бұрын
vocabulary 'flux' and 'circulation' makes the questions more interesting and simple
@张鑫-e9o
@张鑫-e9o 2 жыл бұрын
The handwriting of z is a little bit confusing.
@softwarephil1709
@softwarephil1709 Жыл бұрын
Yes. I thought some z were 2 (squared).
@tiomemo8958
@tiomemo8958 11 ай бұрын
same here lol@@softwarephil1709
@utsavdesai3451
@utsavdesai3451 3 жыл бұрын
Really Helpful for finals next week!!!
@TheDeluxeBacon
@TheDeluxeBacon 3 жыл бұрын
Thank you for making these, I have my vector calculus final tomorrow lol
@DrTrefor
@DrTrefor 3 жыл бұрын
Good luck!!
@chloemirisch8159
@chloemirisch8159 Жыл бұрын
Did you not take the partial derivatives correctly? I thought the partial derivative in respect to x,y,z would be . very confused as to why you added z to each of them.
@Brenticus12
@Brenticus12 Жыл бұрын
the field equation is (xyz, xyz, xyz) not (xy^2, xy^2, xyz)
@j.o.5957
@j.o.5957 3 жыл бұрын
Nice, good stuff. Question to self: how do I solve this using standard flux calculations? I frankly don't know, don't think I've been through that. Should look into it later.
@dantepillon
@dantepillon 3 жыл бұрын
Hi this is a great video! But I was wondering when you were talking about the deformation theorem, that is; when divF = 0, any 2 closed boundaries share the same flux. What I cannot seem to get is, if divF = 0, should the total flux for any closed boundary also = 0??
@DrTrefor
@DrTrefor 3 жыл бұрын
The total flux over all boundaries have to zero, any specific closed region might not be though
@dantepillon
@dantepillon 3 жыл бұрын
@@DrTrefor @Dr. Trefor Bazett thank you very much for replying sir, but I guess what I still don't get is, can you call any specific closed region its own region. And then apply the divergence theorem on that region alone to say it has 0 flux?
@firstlegend5105
@firstlegend5105 Жыл бұрын
​@@dantepillon You are correct that if divF = 0, the total flux for any closed boundary should be 0. In other words, the flux entering the boundary must be equal to the flux leaving the boundary. This is actually a consequence of the divergence theorem: if divF = 0, then the integral of F over any closed surface should be 0. The theorem should read: when divF = 0, any 2 closed boundaries share the same amount of flux and the total flux for any closed boundary is 0.
@CaseyKlein
@CaseyKlein Жыл бұрын
Thank you!!
@rodaneblackwood1079
@rodaneblackwood1079 3 жыл бұрын
Thanks!
@brianofarrell1977
@brianofarrell1977 3 жыл бұрын
F*** me, my final was yesterday... never understood the concept and now i do!
@DrTrefor
@DrTrefor 3 жыл бұрын
Haha great timing😂
@ShubhamPatel-gx7pb
@ShubhamPatel-gx7pb 3 жыл бұрын
If F= yz i + zx j + xy k and S is the part of the surface of the sphere x^2 + y^2 + z^2 = 1 , which lies in first octant , the the value of double integral F•n ds is Sir why we can't use Divergence theorem in this question?
@DrTrefor
@DrTrefor 3 жыл бұрын
Divergence theorem ONLY applies to a closed surface, not part of one.
@ShubhamPatel-gx7pb
@ShubhamPatel-gx7pb 3 жыл бұрын
@@DrTrefor Thank you Sir
@carultch
@carultch Жыл бұрын
@@ShubhamPatel-gx7pb You can often use the divergence theorem as a shortcut to evaluate the flux over a surface that isn't closed, when symmetry works in your favor. Like if it is easier to find the flux over a closed surface using the divergence theorem, and the open surface in question is just one octant of 8 identical octants, that would form a closed surface if you connected them.
@leondavidpedraza8618
@leondavidpedraza8618 Жыл бұрын
What happened with the x that comes out of the first integration? I am sorry, I missed it, it was too fast for me to be too slow! thanks.
@swayamkumarpatro776
@swayamkumarpatro776 3 жыл бұрын
Sir, can you please attach a list of problems which are very important in this vector calculus course ?
@NelsonMbigili-es6pw
@NelsonMbigili-es6pw 4 ай бұрын
💜
@emilykang4354
@emilykang4354 Жыл бұрын
Thank you for such a clear statement
@im_KiraL
@im_KiraL 3 жыл бұрын
How did you get yz+xz+xy from this F
@zeeeeeeeeeev6493
@zeeeeeeeeeev6493 Жыл бұрын
good vid
@aashsyed1277
@aashsyed1277 2 жыл бұрын
What is flux core welding and fabrication near me a lot of
@carultch
@carultch Жыл бұрын
It's an unrelated meaning of the word flux.
@ironsideeve2955
@ironsideeve2955 3 жыл бұрын
0 people disliked this :-)
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