KM DTS 29 Q2 A particle of mass m is projected with velocity v making an angle of 45° with

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A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be (a) mv√2 (c) 2mv (b) zero
(d) mv/√2
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[@TheAstroEnthusiast]

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[@Neetaspirant.0987]

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[@Neetaspirant.0987]

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