A stone is dropped from a height h. It hits the ground with a certain LM DTS 07 Q4

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A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by
(a) 68%
(c) 200%
(b) 41%
(d) 100%
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[@rajlakhera419]

Sir m×root2gh kaise aaya

[@AdityaRaj98754]

Velocity ki value under fall manipulate karke aati hai

[@Dinki-_-official]

​@@AdityaRaj98754kiase bhai derive kar ke bata sakte ho

[@AdityaRaj98754]

​@@Dinki-_-officialyaha par momentum ko hamne mv likha ye clear hai m given hai baat aayi velocity ki toh uniform acceleration hota hai jab sirf gravity ka hi effect lete hai untill or unless question aur kuch data na diya ho ham toh jab koi bhi dropped likhkar aaye toh logically uski initial velocity u=0 lete hai ham ab motion ki vo vali equation yaad karo jisme final velocity v2 ko ham relate karte the acceleration displacement aur initial velocity se that v2=u2+2as ye case motion under gravity me use kar rahe hai free fall hai u ki value 0 li hamne bacha a ki Jagah motion under gravity, g dala aur displacement, s ki jagah h equation of motion me substitute karne ke baad dono taraf root le liya jisse v=under root 2gh agya aur question solve ho gaya and I and believe tumhara doubt solve ho gaya hoga best of luck

[@Dinki-_-official]

@@AdityaRaj98754 thanx bhai ... vese neet clear hua ki abhi nhii ...

[@AdityaRaj98754]

@@Dinki-_-official arey jee wala hu bhai