I think your answer is off. If you use Thevenin's theorem, the circuit becomes a 12 volt battery in series with two resistors of value r/2 each (since R = r/2 and the Thevenin derived resistor is r/2); since they are in series, they have a combined resistance of r. So the current through R is 12volts/0.3 ohms = 40 amps and the power across the resistor R is I x I x R = 1600 x 0.15= 240 watts