Your enthusiasm is contagious! Thanks for this video, even though I knew that I should have never watched it, because now I'm obsessed with trying to solve the same problem with an elastic chain... 😀
@DotPhysics2 ай бұрын
glad you enjoyed it. I really have fun with physics.
@ajejebrazor49362 ай бұрын
Lovely stuff going on here! Hope for the springy challenge!
@fizixx2 ай бұрын
Great problem and the mix of math and python is always a winner! 🐍
@dogspaghetti71182 ай бұрын
11:02 Shouldn’t it be Bb²•e^(-bt)?
@mrslave412 ай бұрын
1:24 λ=linear density of chain =entire mass / entire length =M/R
@mrslave412 ай бұрын
1:41 x=length of chain on the table y (s) = length of chain hanging off table
@ruhailmir2 ай бұрын
Amazing stuff as always, Thanks. We can also use something called "Verlet Integration" as an alternative to connecting the masses with springs. It's a very efficient and powerful method.
@mrslave412 ай бұрын
0:56 R = entire length of chain M = entire mass of chain
@mrslave412 ай бұрын
2:00 R=x+y(s)
@mrslave412 ай бұрын
2:34 R=s+(-x) x=s-R x=-(R-s)
@martyrosadil99892 ай бұрын
Love your videos ❤❤❤ Can you make small videos about solving some question ⁉️
@mrslave412 ай бұрын
2:40 you already lost me 😢😢😢😢😢. please slow down when explaining. 😢😢😢
@padraiggluck29802 ай бұрын
Let’s do a slinky.
@godphysics24732 ай бұрын
There is no mention to the initial condition to start the motion of the chain; is a simple case, ideal physical situation?
@abicol60102 ай бұрын
Assuming no friction, as long as part of the chain is hanging off, the chain will fall. It would be a lot harder to figure out with friction. Although I would like to see him solve that.
@pashaw83802 ай бұрын
@@abicol6010 Not that hard, just use the Rayleigh dissipation function and combine it with the Euler Lagrange equation to form the system's dynamic equation: (d/dt)(∂ℒ/∂ṡ)-(∂ℒ/∂s)+(∂R/∂ṡ)=0 in which R(ṡ)=[1/(0+1)]·∑ᵢ₌₁[(C₁)(ṡ₁)⁰⁺¹]=Cṡ and C=F(µ). Later do a little ODE then you'll get the answer identical to the one obtained from the Newtonian method. If you want the complete process I can show it here.