Numericals on Bus Admittance Matrix | Part 1 (In Hindi)

[@DrAfrozAlam]

Download lecture notes (pdf) using the following link: drive.google.com/file/d/10_A3zXCcfjhpf32bLFA2vzmXjzmhV9Xf/view?usp=sharing

[@surendrakverma555]

Excellent lecture Sir. Thanks

[@shaikhriyaz9033]

Nice teaching sir ji

[@surendrakverma555]

Thanks a lot Sir for very useful lecture. Regards 🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@ashutoshdimri6514]

Interesting lecture

[@abbassyednooruddin3432]

Nice lecture sir✨

[@mranalijoshi1779]

very nice explanation &clear all points bjoshi sgsits indore

[@neminathnarule2257]

Tq sooo☺👏 Muchhhh sir

[@erumkinikar7705]

Thank you so much ....

[@DrAfrozAlam]

You are most welcome

[@naeemahmed1817]

Thanks a lot sir 😊

[@shafqatimam3690]

Nice gate problm.

[@ashutoshdimri6514]

Good afternoon sir

[@DrAfrozAlam]

Good afternoon Ashutosh

[@64NVG]

Thanks a lot for your lectures Professor. Just a small question..isn't the prefix for V in that general formula (using sigma notation) for I should be i instead of k?

[@DrAfrozAlam]

No

[@DrAfrozAlam]

For its derivation, you may watch the following lecture: kzbin.info/www/bejne/ZoaXo2driNx-jtU

[@user-khanaamir8765]

Sir , preffer UR lectures than our AP

[@sreedhartelugu2084]

Please confirm, No of transmission lines = 45-20 i.e 25, ( not 20)

[@DrAfrozAlam]

It is 20 because, (50-10)/2 = 20 as No. of transmission lines = (Total non-zero elements - no. of diagonal elements)/2. Watch the lecture carefully.

[@sreedhartelugu2084]

@@DrAfrozAlam Thank u very much sir, can we solve in this way ?, No of transmission lines=[(maximum no of line)-(no of zero elements/2)]i.e maximum no of transmission line= (10^2-10)/2=45, so no of zero elements=50/2=25, hence No. of transmission lines=45-25=20, please clarify my dought.

[@DrAfrozAlam]

Why do you want to make your calculation more complex ?

[@nafisgazi857]

Sir reference book name please...

[@DrAfrozAlam]

You may read Hadi Saadat

[@nafisgazi857]

@@DrAfrozAlam many many thanks sir...

[@DrAfrozAlam]

Most welcome Nafis

[@neminathnarule2257]

Tq sooo☺👏 Muchhhh sir