MECHANICS | TANGENTIAL & NORMAL Velocity & Acceleration - Theorem & Proof | KINEMATICS | DYNAMICS

[@hinarehman6231]

Vv.v..v..v.v...v.v.v.v. helpful lecture , once I read this topic from mine notes I am going to skip this topic but this tutorial made this easily understandable ......thanks alot respectful sir Keep sharing Lots of regards from 🇵🇰

[@_anuj_gupta]

Option (A) is right answer of the given question I just read the question and reply the answer within 2 seconds only 😁 Thanks a lot to GP sir.. Hats off.

[@amitrajsingh8812]

Aap devta bn kr aaye ho sir🙏

[@Ramnareshkuri]

sir everything is great ,but plz keep uploding on daily basis continue..

[@manikant012]

Option (A) is the correct answer to the given question. Thanks sir ❤

[@Vidya-l9p]

The great concept and useful video sir

[@Krishna-900]

Thanku so much sir 🙏🙏 Great concept and useful vedio

[@arvindgupta7198]

Sir hme bhot acche s smjh aa rha h.....

[@sahilrajak8]

Your video is very helpful for students sir thanks for sharing this video 😊

[@anandShuklaAllahabadUni]

Thank you sir for this video🙏🙏

[@learnergursimran5545]

Thank you very much ...all concept clear.👍👍

[@viralfever7302]

Thank you for free class's 🙏

[@hdjdh794]

Sir ki suruaati speed bahut acchi hai 😊😊😂😂

[@darshanagowala4274]

Yeah I check my speed if I turn it into 1.5 x

[@akshayjangid2014]

Option A that is 0 Sir everything is nice, just keep uploading dynamics videos, that will be a kind of you sir

[@aniruddhamukherjee6434]

Option a will be the correct answer sir... Please continue this series

[@natulligaming8548]

Option (A) is ✅

[@Ytvlogs11951]

Ans - 0 sir 1 millisecond time laga solve karne me 😊😊

[@-KundanYadav]

Super sir 🔥

[@prajwal_sheeti]

The position vector of a moving particle at time t is r = t i-t j +t k. Find the tangential and normal components of acceleration at t =1

[@Rp63888]

Nice class sir 🙏🙏🙏🙏🙏

[@sankalpdwivedi5343]

(A) 0 Sir 8t took 0 sec. I got the answer as I completed the question. Thanks to your brilliant teaching..

[@reinhardt-p8m]

Sir Aap Bohot Accha Parahte hai...

[@ibrahimrizvi9909]

Thank you❤

[@Sortingo13]

Arabi

[@fujail360pro3]

Good please continue series

[@durgeshyadavvlogs4897]

You are great sir for all poor students

[@DREAMUPSC-lx7um]

Thank you so much sir Continue sir please

[@poojasingariya3759]

Thanks sir 😎

[@reinhardt-p8m]

Keep Teaching sir

[@pavanverma4363]

Sir bahuta achchha hai sir par 1din me two(2) video daala kariye sir please

[@ME1DINESHSINGH]

Sir 🙏🙏🏻

[@ME1DINESHSINGH]

I wait 2nd lec.

[@vishalrai8688]

Sir, msc in mathematics and computing can eligible for gate exam

[@nishantkumar5022]

Thankyou so much sir

[@singhshashwatsingh8066]

Keep helping sir ji

[@tencenttencent4272]

Thank you sir

[@divyasingh7889]

Option a is correct 👍 one second sir

[@pushpachavhan5223]

Solve this if you can x-sinx=a(x is a unknown variable, a is any real number ,and angles are measure in radians)

[@Jay-ib7tr]

Thanku

[@daudkhan7160]

Great

[@laxmiprasadmishra7703]

Kyo ki apni video hamare liye helpful hai

[@laxmiprasadmishra7703]

Sir dynamic & statics ki series ki video upload kariye

[@laxmiprasadmishra7703]

Sir more videos dynamic & statics ki upload kar dijiye

[@sandeepkumar-vm7oe]

helpful

[@everythinginthesenseofscie7232]

Sir pichle dynamics video ke last question ka answer bata digiye pls Mera ans minuse lambda square upon r(m²+1) Nikla hai.

[@apkeshwargond5371]

Sir upsc ok a syllabus ko padaeye

[@be.enthusiastic]

Sir we need lecture on keplers law....

[@sandipansinha9930]

Sir please..ek video just for topic clarification.🥵

[@arkyadav7859]

A option is corect, because normal velocity at point P is always zero

[@KhushiChauhan-h9q]

Normal velocity of any curve is 0(zero).

[@abhishekmishra4140]

Sir please also provide the PDF of all the notes . It will be very beneficial for us.

[@saurabhpalxiimaths25]

14:59 option a 4 sec

[@anshikagupta8017]

Option-a

[@Krishna-m29]

Options (A)is right sir

[@simranshishodiya3532]

X=0,sinx=sin0=0 so option a is correct one

[@everythinginthesenseofscie7232]

In this video last question's ans is a)0.

[@sandipansinha9930]

Sir artificial satellites ke bare main kuch daalo.. please exam aa rahe hai 7 Feb seee...

[@sumanphalswal6939]

Sir BSc Physics Hons 1st semester ke notes pdf dalo

[@AkhileshSingh-ln3sd]

Sir main iit jam physics ki taiyari 2022 ke liye kar raha hu

[@sandipansinha9930]

Please ek video bas..thode doubts aaa raha hai artificial satellites main..please sir 7th Feb 22 se exams hai help kardo ekbaar sir pleaseee

[@bibhurawat8167]

A is correct

[@harshitpandey3371]

Proof of the question are the lifeline of mathematics

[@Himanshu_D173]

Sir mujhe Statics bhi aapse padhna hai.

[@14quiztechnology25]

Jnvu bsc 2nd year 2022 ka paper solved karo

[@Tushar-fh6qz]

Sir vo "SHY" nahi "SAI" hota hai 😔

[@ajaydewasi1288]

Option A (0)

[@mathsbysanskaribrahaman3734]

A) 0

[@PoemKumari-qr5li]

(A) 0

[@ritu1410]

Ans will be 0

[@lavishgurjar9648]

Sir geometry aap ne beech me hi chod di please sir usko complete kraiye

[@sarvadharmmathspoint3017]

B

[@reinhardt-p8m]

So Please... Un logo pe dyan mat dijiye jo aapki efforts nahi samajh te....

[@nirmalabishnoi3384]

Zero=N.V

[@yashsuman8313]

Option A Destroyed in seconds 😂

[@RohitKumar-qp1ve]

Zero 🤗

[@ayushsahni2492]

Sir ans ( 0 ) hoga

[@mohdkaif2785]

A answer

[@tencenttencent4272]

A

[@paraghostgaming7454]

0 is the answer

[@khushbookumari900]

Sir support kro gate postpond 2022 ko

[@sspeducation7470]

Sir aaap h to mera net jerf pakka h

[@bootysingh7197]

0 1second

[@eqwerewrqwerqre]

is this in english? I can't tell if like, half the words aren't english or if I'm having a stroke. Every single written word in the video, description, and even these comments is in english, and I keep hearing english words for all the physical concepts, but I feel like there's a bunch of words between the concepts that are definitely not english lmao.

[@khushbookumari900]

Sir student committee ko support kre

[@humayrakhan2779]

, zero

[@mayankyadav6805]

Normal velocity =0

[@Shubhambhadana801]

Student me t silent 🙏🙏🙏🙏🤣🤔

[@SHIVAMYADAV-dv7wc]

0 hoga

[@sachinheggond6209]

Sir please use english more

[@anshikakushwaha9604]

0

[@divakarchaurasia5487]

Thank you sir

[@sandipansinha9930]

Please ek video bas..thode doubts aaa raha hai artificial satellites main..please sir 7th Feb 22 se exams hai help kardo ekbaar sir pleaseee

[@lavishgurjar9648]

Sir geometry aap ne beech me hi chod di please sir usko complete kraiye

[@ayushisharma4337]

A

[@sayanpaul2554]

0

[@ajaymahawar]

Thanks you sir

[@lavishgurjar9648]

Sir geometry aap ne beech me hi chod di please sir usko complete kraiye

[@moniaadav71]

A

[@kanhaiyalalbadgoti9069]

0

[@lavishgurjar9648]

Sir geometry aap ne beech me hi chod di please sir usko complete kraiye

[@HizarKhan-m1o]

0

[@lavishgurjar9648]

Sir geometry aap ne beech me hi chod di please sir usko complete kraiye