Memoryless Property of the Geometric Distribution

[@gipetgifta8888]

Out of all proof that i found in the internet this is the most understandable one. Thank you very much for providing a very comprehensive proof of this memory-less property！

[@DrHarishGarg]

Many thanks for the appreciation.

[@kalaivanic1008]

S really happy that I can understand geometric distribution this much easier 👍🏻

[@taeyann6153]

this is the most understandable proof of the memory-less property! Thanks alot!

[@Newfacts-18]

I couldn't understand before seen your lecture but i got completely after to seen your lecture sir you are so genius i am so happy to learn probability to you

[@kathirsrk9503]

6yok😊

[@enzokuhlemsotra6383]

thank you sir for this great explaination

[@035mdatiqurrahmanakash7]

sir , please solve those practice questions

[@shaonlipal8225]

Thank you, Sir! Awesome explanation!

[@DrHarishGarg]

Many thanks

[@kyloramon4970]

Sorry to be so offtopic but does any of you know of a tool to get back into an Instagram account? I somehow lost my password. I appreciate any help you can offer me.

[@kasonadrien1585]

@Kylo Ramon instablaster :)

[@kyloramon4970]

@Kason Adrien thanks so much for your reply. I got to the site through google and im waiting for the hacking stuff now. Looks like it's gonna take quite some time so I will get back to you later with my results.

[@kyloramon4970]

@Kason Adrien it did the trick and I now got access to my account again. Im so happy:D Thank you so much you saved my ass !

[@sneakybinders]

Very well explained !

[@Newfacts-18]

You are best sir i am able to got that you tought us

[@soumyaagrahari2107]

Sir please make a video how to solve questions using memory less property

[@priyansukumar3875]

Thanku so much sir ❤️ for this series

[@DrHarishGarg]

So glad!... Keep watching and sharing

[@ridhimachauhan4962]

Amazing session sir!!

[@DrHarishGarg]

Many thanks.... Join my telegram link of Probability and Statistics t.me/gargProbability

[@ai.art_ara]

Sir, alternatively could you explain proof of P(Y=t|X >=k) = pq^t = P(X=t)? It is the prood given in VK Kapoor book.

[@snehashirgaonkar1065]

Thank you so much sir 🙏🙏

[@venkatnaidunallabothula1910]

Thank you so much sir

[@DrHarishGarg]

My pleasure always

[@elomi8092]

Thank you so much ❤

[@rasikashetye2698]

Thank you!

[@hariniharini5692]

It's very useful and understandable but please put the solution for practice problems

[@user-gv3lq2qy2g]

Thankkkkkkkkk u very much sir🙃

[@DrHarishGarg]

My pleasure always. Keep watching and sharing.

[@harshbari9066]

What are the answers of the given 2 questions at the end ?

[@Dupamine]

this is the hardest video of yours so far

[@DrHarishGarg]

But it is the easiest one too. .. Keep watching

[@jayeshpatil5112]

done

[@Dvibes2899]

👏👏🙏🙏