A description of Simple Harmonic Motion, including its definition, and examples of SHM in the form of oscillating springs and pendulums.
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@abdulqadirtirmizey27277 жыл бұрын
Sir, By grace of Allah and your helping videos, I have scored B-Grade in my A-level Physics Exam. By the end of January, I was totally zero at Physics and scored lowest in class. And by the start of February, I started watching your A-level revision videos. Since, I didn't scored well in my AS-Level exams, I was giving composite paper, so the burden on me was double. Believe me sir, by the end of March, I covered the whole syllabus of AS-Level, and 80% of A-level. You know, April is the month of tests for A-level student, and since I had covered almost all of my syllabus, I performed really well in those tests. And then, in A-level exams, I performed excellently. Due to which, I scored B-Grade in Physics. This grade is enough to get admission in Architecture (My dream) and excellent for a student like me :D All thanks goes to you sir, these videos are the reason I scored so well. Thank You So Much.. :D Yours Truly, AbdulQadir Tirmizey
@madboy11057 жыл бұрын
congratz man
@abdulqadirtirmizey27277 жыл бұрын
Thanks Bro.. :D I wish sir could also reply to my comment. But still, your concern is pleasing :)
@PR0Z0MBIE98777 жыл бұрын
You do A-Levels at April?
@abdulqadirtirmizey27277 жыл бұрын
Nope bro... By 'tests' I meant model tests which are taken by your school teachers, for beter practice.
@kalanijayasekara52857 жыл бұрын
How many hours a day did you study? and how did you study? any technique? BTW congrats!!!
@abhishekshrestha64417 жыл бұрын
The "hello" in the start of this video.
@aurelian32685 жыл бұрын
he has achieved Nirvana
@tendayimbudzi57073 жыл бұрын
Davy Jones underrated comment😂
@xubarney1326 Жыл бұрын
hahahahahahaha
@microman996 жыл бұрын
Low resolution video, high resolution output concept You save my physics!!!!
@harolddiaz70466 жыл бұрын
You're going to be the reason why I pass my physics classes. You give such good clarity while also being very descriptive with your mathematic explanations. Thank you sir. You are not only a big help but a big inspiration.
@DrPhysicsA11 жыл бұрын
Think of a spring with a mass M oscillating up and down. When the mass reaches its lowest point it stops going down and starts going up. At that point its velocity is zero. But the spring has its maximum extension at that point. For a spring the force acting on the mass is F = Kx (where k is the spring constant and x is the displacement from the mid point). Since x is maximum at this point, so will be the force. But F = Ma so the acceleration is also maximum.
@MrRasco9710 жыл бұрын
This is extremely helpful and I now fully understand but I wish they didn't have to call it simple haha
@nedelser72334 жыл бұрын
2:36 Me in most lessons
@amrinahmed22793 жыл бұрын
This is so accurate
@DrPhysicsA11 жыл бұрын
Yes. You use the cos term if t=0 is when the pendulum/spring is at its maximum displacement from the mid point. You use the sin term if t=0 is when the pendulum/spring is at the mid point. y is the displacement from the mid point in each case. Just try values of t=0 in each formula and see what different values you get for y.
@DrPhysicsA11 жыл бұрын
The playlist is in the most logical order that I could get it. I start with all the videos which relate to classical mechanics and then begin to move on to the concept of wave mechanics before going on to other aspects of physics.
@lindadada-dadadal98646 жыл бұрын
Everyone doing alevel physics needs to see this video! I am quite good at maths but smh used to puzzle me...not any more! Thank you soooo much sir!
@Kundaikeith Жыл бұрын
Indeed very helpful ,have been using this tutorial since Advanced Level Physics Class until now in my Engineering Physics Class........DrPhysicsA is a star
@DrPhysicsA11 жыл бұрын
A guitar string oscillates as a standing wave. This means that its fundamental vibration will result in the middle of the guitar string having a much larger displacement than near the end. So the velocity of the oscillating guitar string in the middle will be greater than that at the end.
@DrPhysicsA11 жыл бұрын
Yes. As the spring/pendulum oscillates it is exchanging Kinetic and Potential Energy. When displacement = 0, PE = 0 and KE is max. Hence v = max.
@DrPhysicsA11 жыл бұрын
The pendulum example only works with small angles because we make the assumption that Cos theta equals 1, which is true for very small angles but becomes an imprecise assumption as the angle increases.
@poligon3339 жыл бұрын
Very good video, straight to the point , no disruptions , thanks.
@comic4relief2 жыл бұрын
I am not English, and not taking a physics course, but enjoy your videos. I study math on my own.
@DrPhysicsA11 жыл бұрын
Yes. Omega is the angular sweep per second.
@DrPhysicsA12 жыл бұрын
Yes but when the angle Θ is very small (which is the condition for the pendulum to swing with SHM) the two are pretty much the same. All motion is in the left-right direction and the up-down motion is ignored. So T=mg to a very good approximation.
@DrPhysicsA11 жыл бұрын
A pendulum doesn't have a spring in it (usually). The reason both a pendulum and a spring oscillate is that whenver they are displaced from the mean position there is a restoring force which is acting to restore to the mean position. In the case of a pendulum that force will be due to gravity. In the case of the a spring it is caused by the inherent nature of the spring.
@samadrashid798810 жыл бұрын
This video made it so easy. Thumbs up!
@onkarkepkar38019 жыл бұрын
beautiful explanation!!! helped me in my exams......
@toofresh9111 жыл бұрын
Total Mechanical Energy must be constant, through out the wave motion. At the crest, the PE will be at a maximum and KE at zero. Vice versa at the trough. E=PE+KE OR E=PE+(-KE)
@skhoosy Жыл бұрын
if we are considering a particle travelling through some sine curve y=sinx, how have you gotten to the conclusion that it would be defined by y=sinwt?
@owensande5 жыл бұрын
I suggest watching at x1.25
@EliteHalo58 жыл бұрын
sounds like an asmr video
@inthebackwiththerabbish5 жыл бұрын
rickmcn1986 weird
@thomasgoodey157011 жыл бұрын
doing gcses at the moment and i found this so helpful preparing myself for a levels as i am doing further maths, maths, physics and chemistry thanks again
@afshinzaman26513 жыл бұрын
How did it go
@sraynambal8707 жыл бұрын
Hi, I'm confused why F=Ma= -TSin(Theta) , just confused with the negative sign.
@DrPhysicsA7 жыл бұрын
Because its a restoring force i.e. it operates in the opposite direction to the displacement (whether measured by x or theta).
@adn1710 жыл бұрын
Thank you sir.Very instructive and interesting. Simple to understand!
@anupamac21518 жыл бұрын
great vdeo . nice to c all topics stacked in 9 mins
@SuperCricket77710 жыл бұрын
Strictly, when you define SHM, you get the equation 1) a = -(2piF)^2 x (taking 2piF as the constant, the angular frequency) But deriving this equation from the second derivative of displacement gives a = - A(2piF)^2 To account for the Amplitude in 1) is it correct to take the constant as A(2pif)^2 instead? Thanks
@sushmitamondal9628 жыл бұрын
so useful... and u have actually cleared my basics concepts
@comprehensiveboy11 жыл бұрын
Is omega the circular distance the particle moves in a second in radians? So.2*pi is one circuit so times that by the frequency and you get how many times it goes around in a second. But a radian is an angle size so getting a trig value of this for the y direction displacment is always gonna be between 1 and -1 which represents the amplitude without an A component?
@joeradomski56710 жыл бұрын
My brain hurts
@CorretorAlyssonGomes7 жыл бұрын
Your brain may not be ready.
@profilename1009 жыл бұрын
great video but in edexcel physics you use it all the other way around as you start the oscillation at a max like in the cos graph so v is in sin and a is in cos
@philipchristiansen14958 жыл бұрын
At 5.32, how do you get w*sqrt(A^2-y^2). Though it should be w*sqrt(A^2-y^2/y^2) no?
@sedani211 жыл бұрын
why is the velocity at a maximum when the displacement is zero?? is it because its kinetic energy is greater at that point?
@joemason319 жыл бұрын
could you say that Acceleration of a spring can be written as -(2*pi*f)^2*x when f = frequency and x = displacement ???
@DrPhysicsA9 жыл бұрын
Joe mason Yes because w = 2*pi*f
@gertwallen12 жыл бұрын
Hi, when you are referring to the restoring force at 7:55, shouldn't the restoring force be tangent to the arc described by the pendulum motion due to gravity, i.e., mgsinΘ and not TsinΘ as you mention in the video? Thanks
@NaraAIApp6 жыл бұрын
What? You can do that 😂..now im amaze..(the derivaation part)
@sedani211 жыл бұрын
thank you DrPhysicsA!! Im starting to get the hang of SHM now. Just one quick question if you dont mind? Is a pendulum oscillating because of the tension in the spring causing to contract when it reaches a certain amount and the force of gravity acting on it causes this process to continuously repeat? hope im making sense :P
@zeckem834011 жыл бұрын
a great summary of SHM. thanks a lot!
@alen76485 жыл бұрын
I think I‘ll give this video a chance.... looks good so far.....
@turicaederynmab534311 жыл бұрын
I went from learning about Friction too the oscillation of particles relative too harmonic motion? I think the playlist is a bit messed up...
@SpaceOutlaww9 жыл бұрын
There is a minor mathematical error at the end of the video. The acceleration of the pendulum should be -gx/L instead of gx/L.
@DrPhysicsA9 жыл бұрын
Arthur Johnson Correct. The force and acceleration are always in the opposite direction to the displacement. I was calculating the magnitude.
@AlchemistOfNirnroot9 жыл бұрын
+DrPhysicsA Hence the annotation?
@therealmaveric12 жыл бұрын
Brilliant video, it really helps with my a levels .
@karishmamohun24738 жыл бұрын
that is exactly what I was looking for thank you sir
@PrimeEpoch9 жыл бұрын
At about 8:10, I don't see how you get that t sin theta is the only restoring force, since the mass also has to move downwards to get to the equilibrium position. This also, by logic, means that your 2nd equation must be wrong. Also, the weight is constant whereas the vertical component of tension varies with theta, so this is true only for a certain value of theta, but since the mass is in motion, the equation can't hold. Hope this helps :)
@PrimeEpoch9 жыл бұрын
Ignore the first part, I misunderstood for a minute. I'm pretty sure that the 2nd equation doesn't hold though.
@DrPhysicsA9 жыл бұрын
Kristen R You are right that the restoring force will vary with theta - thats how we get the SHM. The force, hence the acceleration, varies with displacement (which depends on theta).
@andykopfleck11 жыл бұрын
Hi, Dr.Physics. How would you derive the Time Period of a Pendulum using F=ma & W=mg? Thank you for your attention.
@DrPhysicsA11 жыл бұрын
Its included in many A2 level courses.
@surry999 жыл бұрын
what type camera an microphone do you use?
@DrPhysicsA9 жыл бұрын
Just an ordinary digital camera with built in microphone.
@ShadowZZZ6 жыл бұрын
at 5:28 how do you get to dy/dt = w*(A^2-Y^2)^1/2 ?
@CrestinaBerzentho11 жыл бұрын
Sometimes we start with y=Acos(wt) except for y=Asin(wt) is there a difference ? a yes or No answer will suffice.
@arielkatzir91265 жыл бұрын
The way he says ''what is happening'' at 2:36 ...
@anbtebist59619 жыл бұрын
HI DRPHYSICS, why are you multiplying y= sinWT by omega (w) when you derive it?
@SilverArro9 жыл бұрын
Chain rule
@TheVashJa8 жыл бұрын
+Anbesa Teame Differential of the inner nested function in respect to its dependent variable multiplied by the differential of the outer function in repect to the inner nested function.
@alwaysdisputin99303 жыл бұрын
In DrPhysicsA's video "What is Light?" kzbin.info/www/bejne/q2LEaHetoK1qd8U he starts with an equation: Ψ = sin (kx - ωt) & then he differentiates in 2 different ways like this: ̲dΨ̲ = k cos ( kx - ωt ) dx ̲dΨ̲ = -ω cos ( kx - ωt ) dt So the letter that you put on the front depends on whether you say: dx or: dt
@jointcc28 жыл бұрын
why is omega square k/m
@Sayeedur1236 жыл бұрын
Using a=-w^2 x
@Mugetsuism10 жыл бұрын
Huh. Dy/Dt was never explained to us when we did SHM last month. It was simply: As the max and min values of sin and cos are 1 and -1 respectively, v = -wAsin(wt) and a = -w^2Acos(wt) simply become: v.max = wA and a.max = w^2A. Iv'e done AS maths and doing A2 now, but haven't differentiated cos/sin/tan so I didn't know how e was doing that (it looks like multiply by w and sin becomes cos, and cos becomes -sin). We're starting Chapter 8 Differentiation (last chapter) in C3 next week so I guess we'll learn that then?
@TheLaprasMan10 жыл бұрын
d/dx cos(x) = -sin(x) d/dx sin(x) = cos(x) where y is the displacement of the particle: y=Asin(ωT) to find dy/dT which will give us the velocity we need to use the concepts above and the chain rule: The chain rule is used to find the derivative of two composite functions. Let's say y=f(g(x)), let's set g(x) to equal a variable to simplify things: z=g(x) (This is all the output of a function is: a variable) Then we have y=f(z) - much simpler. Let's take dy/dz=f '(z) we know z=g(x), so dz/dx=g'(x) now to cancel out dz we multiply dy/dz by dz/dx to find dy/dx: dy/dx = f '(z)*g'(x) z=g(x): dy/dx = f '(g(x)) * g(x)
@ZyNeEnZyNe9 жыл бұрын
Ben Towers Thank you for taking the time to write that.
@Mugetsuism9 жыл бұрын
Ben Towers I must have missed the notification in regards to your comment earlier; Just saw it now! Yep, we've finished doing the derivatives of trigs e.t.c. I really appreciate you taking the time to explain all of this. Iv'e finished with both SHM and Differentiation (chain/quotient rule e.t.c.) but never thought about using them together lol. I wish they integrated more maths into the physics course, but I guess those who aren't doing maths as-well will just lose their minds XD
@AlchemistOfNirnroot9 жыл бұрын
+Asfandyar Khan A bit late but what he hell :P Someone in my class doesn't do A Level Maths. We just started Capacitance, when we started doing exponential relationships (i.e Q=Qe^-(t/RC)) she was baffled, the integral calculus for the coursework is going to be hell for her :D
@yogithamanu78315 жыл бұрын
Asfandyar Khan up HD h kg h
@hunnybean2695 жыл бұрын
Shouldn't horizontal be cos and vertical be sin?
@thenerdpoint54925 жыл бұрын
No, the component through the angle is always cos and the one away from the angle is always sin. What he did is correct.
@natureandchange8 жыл бұрын
why is the acceleration 0 at point B??. 3:12
@PR0Z0MBIE98777 жыл бұрын
Are you still interested in the answer? Acceleration in terms of SHM takes the form of a -sin(theta) wave. This means the value for acceleration will always be opposite to the displacement. At point B where displacement is 0, acceleration is opposite which also makes it 0. e.g. if displacement is -1, acceleration will be +1 (when looking at the two sine graphs).
@JrYong6 жыл бұрын
Wow it doesn't seem so mind racking anymore, thanks for putting the simple in simple harmonic motion HaHa...
@ahmadislam23649 жыл бұрын
why it is not f=-ma? why it is positive? as acceleration is vector, acceleration should be negative, right?
@Cobenis_Kar8 жыл бұрын
+ahmad zahir It is taken generally as a convention that, down or in the direction of gravitational acceleration, the sign is positive and that up or against gravity is negative. You can do it your way but, it will be more difficult. It has been made that way to make it more easier to do calculations.
@PR0Z0MBIE98777 жыл бұрын
Because for this equation we are not looking at gravity. Simply, the acceleration of the pendulum. a can be resolved into it's component vectors which will then directly be looking at gravity. But the a in the example in the video is solely looking at the resultant acceleration.
@gertwallen12 жыл бұрын
right, T=mgcosΘ, so when Θ
@Crehan.9 жыл бұрын
At 6:50, how did you derive that K/m is equal to omega?
@DrPhysicsA9 жыл бұрын
Alfie Crehan I had previously shown that the general condition for SHM is a=-w^2 x So in this case k/m must be w^2
@jamieshelley607911 жыл бұрын
also can i ask, when you said maximum velocity at the point of 0 displacement, does this mean the velocity changes like this with other examples e.g a guitar, Having trouble visualising that for some reason. p.s thx for explaining the formulae in this clear manner
@wangliz72088 жыл бұрын
Why does F=ma=-T sinθ (in the pendulum question)?
@DrPhysicsA8 жыл бұрын
+Wang Liz (Ludwig) When the pendulum is at an angle theta (and provided this is not more than a few degrees), the restoring force F=ma is provided by the component of the tension in the string.
@PerspectiveX28 жыл бұрын
+DrPhysicsA why does F=ma= minus Tsin(theta) and not positive Tsin(theta). Don't both the restoring force and the horizontal component of the tension act in the same direction?
@DrPhysicsA8 жыл бұрын
+Saku Yes. But they angle is measured in the opposite direction to the restoring force hence the - sign.
@waltermaths6 жыл бұрын
thank you, thank you, thank you
@indikabatagoda9411 жыл бұрын
you are the best Drphysics :D
@calteckk4 жыл бұрын
9:00 how does sin(theta) = x/L ?
@suprimghimire43517 жыл бұрын
very good explanation
@internetuser93157 жыл бұрын
Sir, how to know if a given equation represents a SHM or just a periodic motion???? pls help!!!!!!
@arturopena37657 жыл бұрын
force proportional to displacement and in the opposite direction...an example hook's law...F= -kx.....bigger displacement X,,,,,,, bigger restoring force F..... but in opposite direction.....
@omirza77816 жыл бұрын
I have created 2 playlists for A-level Physics for Edexcel, they are Paper 1 and Paper 2 make sure to check them out.
@sedani211 жыл бұрын
ok thanks a lot, i kind off get how these systems work now
@CrestinaBerzentho11 жыл бұрын
Thank You, The explanation helped a lot.
@yumenoritsu8 жыл бұрын
Nice, thanks so much!!
@9point99poundsonly11 жыл бұрын
this is in fact as level. I have SHM in my unit 2 physics module.
@xeryan27478 жыл бұрын
sir, i dont understand why w=(k/m)^1/2
@DrPhysicsA8 жыл бұрын
+Ting Tiew Yik We establish first that SHM occurs when a is related to x by the constant -w^2. Then when we find a relation for a spring that a=-kx/m we can deduce that k/m is w^2.
@jokerman92957 жыл бұрын
So omega=angular speed right?
@marcushill25447 жыл бұрын
Yes fam
@DrPhysicsA7 жыл бұрын
Well actually its a frequency term. w = 2 pi f Frequency is number of cycles per second. w is no of radians per second.
@surry999 жыл бұрын
Thank you.
@greghudson6478 жыл бұрын
why does F=-kx? Isn't Hookes law F=kx
@DrPhysicsA11 жыл бұрын
That is in essence what I do at 08:20.
@maniac86928 жыл бұрын
awesome dude
@SamsherSinghJoon10 жыл бұрын
i want A1 Level
@AlchemistOfNirnroot10 жыл бұрын
AS?
@hassanahmad32917 жыл бұрын
there isn't a simple harmonic motion chapter in AS Level physics
@dr.najeebullahqadir58586 жыл бұрын
download a copy of the 9702 syllabus and see what topics are listed in As prepare accordingly
@ninad03089 жыл бұрын
is this for A2 CIE? OR AS?
@DrPhysicsA9 жыл бұрын
N vhgmghhk Not sure. I prepare vids to cover AS and A2 level for AQA, OCR, Edexcel and CIE but not too sure how each board splits its AS and A2 work.
@yousseftarkhan92107 жыл бұрын
This is A2 in Cie
@Nyuum6 жыл бұрын
ow meh gah
@mukundjha7927 жыл бұрын
sir how to calculate epoch
@DeMakAtak11 жыл бұрын
this helps.thanks
@dk0r5111 жыл бұрын
06:19 "mid-position" = rest length
@marystown239 жыл бұрын
nice video :)
@17sahilkumar8 жыл бұрын
Thank you sir
@jamieshelley607911 жыл бұрын
could you perhaps tell me why it only works with small angels, or buy that did you simply mean less than 90 (cos sin 09 - 1- seems that won't work)..idk if I answer my own question here :d
@FaxandProbed11 жыл бұрын
This was a very good video.
@asmacomidy714711 жыл бұрын
mrc
@masoodkhan8577 жыл бұрын
nice
@arshahuja84907 жыл бұрын
You sound like Richard Dawkins
@andrewh99611 жыл бұрын
Is this a level? Because ive never seen this in my life
@cilva7able7 жыл бұрын
HELP! I have a question and anybody feel free to answer. I'm confused about "frequency" and "w". What's the difference? Can you explain how T=1/f but when I'm doing sinusoidal modeling T=2pi/f.
@Faste137 жыл бұрын
T is how long per ONE cycle, f is how many cycles per ONE second therefore Txf = 1 in a way. what's sinusoidal modelling?
@DrPhysicsA7 жыл бұрын
w - or omega - is the frequency in radians per second. f is the frequency in cycles per second. Since there are 2 pi radians in one complete circle (cycle) w = 2 pi f.
@RedzyOne10 жыл бұрын
Nice¬¬¬¬¬
@linkchibi12 жыл бұрын
so difficult -.-
@clotanoob11 жыл бұрын
It is so blur...
@jamieshelley607911 жыл бұрын
I'd been expecting something well ..more challenging for A2,not sure if I'm going to like the following year or get annoyed at examiners simplifying to the extend you have to learn how to simplify your own studies to tick the boxes so to speak. anyone got experience in this ?
@azerverycarry38793 жыл бұрын
COMES HERE BECAUSE YOU HAVE HOMEWORK OF MECHANISM OF MACHINES