Thank you Dr. Robert Eagle. Crystal clear explained! During and by watching this video, I made two new discoveries.
@navjotsingh-bl7jk6 жыл бұрын
Last 35 mins were awesome. No experimental facts, only theoretical work.
@payammadjidi47017 жыл бұрын
I really love the way you explain advanced concepts. I really appropriate your channel.
@northernskies867 жыл бұрын
you make very complicated topics so easy to understand. I looked at Wikipedia and I got nothing. for you, I actually understand the SEMF. I am so glad you are on youtube :)
@אביסהר-ט4י4 ай бұрын
best physics lecturer in the world/ period!
@sayanbhakta28924 жыл бұрын
Excellent explanation.....probably the best of it's kind I should say......
@Antarjyoti-c3i5 жыл бұрын
This is the best channel for learning advanced physics 🙏🙏🙏🙏
@brendawilliams80622 жыл бұрын
Absolutely
@magp200810 жыл бұрын
I am very happy because you are back. I missed you. I was afraid you stopped your classes. You are great! Thank you very much!
@AAAAAAAAAAAAAAAAAAAAHH3 жыл бұрын
Who downvotes this? Amazing teaching
@northernskies867 жыл бұрын
It is amazing how DrPhysicsA can make the most complicated things sound easy :)
@sakshibeniwal37296 жыл бұрын
Sir ,you just simplified nuclear concepts...thank you sir
@JohnSmith-cy8hq10 жыл бұрын
I was afraid you stopped making videos...
@jimdogma153710 жыл бұрын
Grab your popcorn and your calculators everyone, DrPhysicsA is BACK!!!
@luismorana507210 жыл бұрын
Yes!!!!....I was really concerned that DrPhysicsA was gone for ever. Thanks for not letting us down. Welcome back Professor !!!!
@ThomasJohnHyde10 жыл бұрын
Arrggg why do I find your channel a week after I finish my A Levels? Really nice videos anyway, they help allot :)
@iftekmahmud10 жыл бұрын
Finally you are back Sir!!
@DamienWilkins15 жыл бұрын
Beautiful physics and made very clear and understandable! Many thanks, final year physics undergrad
@MsJDW857 жыл бұрын
This has been so helpful, thank you
@brankozivlak32915 жыл бұрын
Great presentation. Best of all scientific. When you talk about stable nuclei in 1:14 minutes, can that also be an explanation for the existence of "magic numbers"?
@kjv353 жыл бұрын
Slight correction to the bit around 1:10:00: double beta decay CAN happen and very much does. It is the basis for neutrinoless double beta decay searches. Some example isotopes are Tellurium 130 and Molybdenum 100! DrPhysicsA is right that it is a quite rare process, however!
@AchrafAtila8 жыл бұрын
thank you so much for this good explanation to nuclear physics.
@AirIUnderwater7 жыл бұрын
Where were these videos when I needed them years ago!? T_T
@fjficm10 жыл бұрын
Thanks better than any text or lecture
@neelsharma26416 жыл бұрын
Hello.... Sir thank you It's very nice video thanks again for nice lecture.. 🙏
@orderrr93569 жыл бұрын
@40.11: The extra energy formulation looks like an arithmetic series to me rather than a geometric one. Factoring out 2*delta gives a nice ap 1+2+....+x/2 whose sum can be found and this would produce the same formula as shown.
@seale11332 жыл бұрын
Thank you so much for these videos
@poshmark98075 жыл бұрын
You're back! Thank you for making these!!
@gogoat10010 жыл бұрын
ahh :) good to see you back. great show !
@MakeMeScientific6 жыл бұрын
The best video lecture. #makemescientific
@yanemailg8 жыл бұрын
Thank you. Exactly what i needed !!
@muddassarhussain88716 жыл бұрын
great explanation please upload a lecture about the nuclear energy calculations in nuclear reactor,and a complete analysis of pwrs,lwr,lmfbrs and nuclear fuel cycle
@koushikrajkonwar24314 жыл бұрын
Sir one day you will be great.
@logearav8 жыл бұрын
Thanks Dr.PhysicsA. Very well explained. But how lighter nuclei like He, C, N, O etc have greater BE/A?
@RTRVII10 жыл бұрын
Very clearly explained. Thanks so much.
@thearchive267884 жыл бұрын
Does the fact that the binding energy per nucleon reaches it's peak at Fe56 have anything to do with the fact that a star collapses into itself after fusing into iron and couldn't fuse anymore? I've heard that's how black holes are created. Am I wrong?
@feelingzhakkaas9 жыл бұрын
Thanks for Clarification.
@MegaSKyFall6 жыл бұрын
mind blown, ty so much for this video
@sajateacher8 жыл бұрын
I guess this sort of shell model would also apply to quarks or to almost any other structure that could be made out of subatomic particles?
@sinhaji64695 жыл бұрын
Thanku so much sir Love from india🙏
@pekhoed10 жыл бұрын
i was gonna say R.I.P to DrphysicsA. Now he is clearly alive. Thank goodness
@heroncortizo19937 жыл бұрын
47:29 Is it means a semi empirical Formula does not have all explanations that "what is going on" inside the nucleus? -------- What is interesting is the limit of Being Fe56.... The limit if Super Nova to explode funding the element of Iron.... It is very interesting this relation.
@dvdmine10 жыл бұрын
A quick question about the binding energy of the nucleus, how can we measure the mass of a neutron if you said that measuring the mass of a proton was so hard to do? Thanks
@DrPhysicsA10 жыл бұрын
Actually you can measure the mass of the proton. But the nuclear mass of an atom with several nucleon is is more difficult to measure.
@khalil90310 жыл бұрын
Welcome back!
@ft675510 жыл бұрын
Is there any chance you could order the videos correctly in your Nuclear Physics playlist? This is #3 yet referring to videos further down in the playlist to watch first, rather confusing.
@ketansathwara62716 жыл бұрын
Great sir hats off👌
@vennesatyanarayana56967 жыл бұрын
sir i have a doubt. in pairing energy term. why the o-e and e-o have zero contribution.even single nucleon can decrease the binding energy of that particular nuclear.why wouldn't it be negative rather than zero.
@qwertycorno10 жыл бұрын
Can one say in words that for larger A it becomes favourable to have a bit more neutrons than protons because of the Coulomb repulsion?
@muhieddineshebaro66359 жыл бұрын
Should the most stable isotope be the most abundant one or it is not necessarly? I am using Weizsacker mass formula to calculate the binding energy of 10 isotopes. But i feel the results that i am obtaining is wrong i refer to a periodic table app (trusted one). I calculate for example the binding energy of an unstable isotope using Weizsacker and the number obtained is the highest than the number obtained when calculating the binding energy of a stable isotope but why?! Plz help me! (2wuestions ro answer plz dude)
@sajateacher8 жыл бұрын
Would there be a stable configuration at higher atomic numbers, like maybe above element 119 there could be a stable isotope of some as-of-yet undiscovered element?
@misstulipie6 жыл бұрын
There are theories about this! You might be interested in reading about the "Island of Stability" x
@ferdinandgrimm998610 жыл бұрын
finally a new video, thank you!!
@mfoucault19845 жыл бұрын
just great
@davidsweeney11110 жыл бұрын
Thanks for the video very thorough! So now I know why the isotopic mass number of an element is never an integer, not just because protons and neutrons are not exactly 1u to start with but more importantly their mass decreases because of binding energy keeping the nucleus together. So why did they define carbon to be exactly 12 and have everything relative to that? Because the isotopic mass of 12C isn't actually an integer value is it?
@divyanshukatiyar88866 жыл бұрын
I really appreciate your efforts towards this video, however, I had a doubt about the dependence of the 5th term on 1/(A^(3/4)). Please clarify.
@muhieddineshebaro66359 жыл бұрын
and how do i know if an isotope is stable if i have its binding energy? However, and can the binding energy be in the negative form?
@DrPhysicsA9 жыл бұрын
Mohieddine Shebaro There is a link between stability and BE. The greater the BE the more energy you need to break it up. Negative BE means the nuclei are not bound - i.e. no nuclei
@feelingzhakkaas9 жыл бұрын
Respected Sir, Can the BEnergy be created from empty space ? i read somewhere that empty space is not really empty it has tremendous energy ...!!! please clarify.
@DrPhysicsA9 жыл бұрын
+Prakash Kamath In quantum physics empty space (aka vacuum) can have all kinds of quantum effects including creating and annihilating particles. But where something is created from nothing it does not survive long. In a sense it has to pay back the energy borrowed from vacuum. The more you borrow the faster you have to pay it back.
@gmtoomey9 жыл бұрын
+DrPhysicsA "There is enough energy inside the space in an empty cup to boil all the oceans of the world." - Richard Feynman, possibly referring to zero point energy
@ZainAli-nz2us8 жыл бұрын
i think binding energy is because of the particles attraction.......energy in empty space reffers to the dark energy not to the binding energy....
@davidwilkie95516 жыл бұрын
If only for the sake of having fun with imagination and perceptions of evolving projectiondrawing wave-packages of the Superspin modulation integration.., turning the composite numberness of primes and cofactors insideout, or act-ually outsidein to the Singularity Origin, the multi-phase Temporal Superposition-point Singularity positioning of probabilities is an exercise similar/analogous to designing a very complex gearbox of virtual work. The design of a Tokomac Fusion Reactor that is purpose built to engage Protons and Neutrons into bigger packages is a clue to how Quantum Operator Fields Modulation Mechanism of probabilities in potential possibilities is arranged naturally, to push the numbers around in synchronicity, from liquid gas/energy->solid mass/energy balanced equations.
@brendawilliams80622 жыл бұрын
You are inspiring.
@sumanpramanick16466 жыл бұрын
At 40:10 min you say Geometrical Series, but I think the series is Arithmetic series....
@pistolart3302 Жыл бұрын
عمو دكتور فيزيكس ماتقدرش دير ملخص تع النووي في خمس دقائق وربي يجازيك ❤
@aakashthakur27859 жыл бұрын
that is not a geometric series it is an arithmetic series (in the calculation of asymmetric energy) thanks for your video sir
@benselemrabab55778 жыл бұрын
بارك الله فيك
@markskilbeck10 жыл бұрын
Awesome content. I've got to say though... you need a better camera!
@aakashthakur27859 жыл бұрын
in calculation of binding energy you replaced (ZMp+ZMe)c^2 by (Z*mass of H)*c^2+B.E. of H atom but u have already included B.E. of atom at RHS of the eqn then why we need to include BE of H again
@DrPhysicsA9 жыл бұрын
At what time in the video does this arise?
@asdsa743410 жыл бұрын
Thank god u're back >
@pabloo.o191210 жыл бұрын
Finally after so long
@rktiwa10 жыл бұрын
missed you.
@01rai018 жыл бұрын
50:13 92 Atoms? When was this video made, in the stone age
@muhieddineshebaro66359 жыл бұрын
plz somebody answer me. "As binding energy increases,stability increases,isotopic abundance also increases ". Is this statement right plz reply!
@DrPhysicsA9 жыл бұрын
Mohieddine Shebaro If BE for a particular isotope is high then it will be stable. But that does not mean that other isotopes (i.e. same p value) will be stable.
@muhieddineshebaro66359 жыл бұрын
thx u sir but can u answer the other comment plz if u see it !
@FrEEloa6 жыл бұрын
you are a monster, i would like to be like you
@anujrana25837 жыл бұрын
why even and odd case has delta equals 0?
@northernskies867 жыл бұрын
Because for an even odd case, there is only one lone pair but an odd odd case there are more unpaired nucleons.
@pekhoed10 жыл бұрын
if two hydrogen atoms fuse to create helium and release energy in the form of binding energy, then where is the extra energy provided by the fusion reaction??? Obviously, hydrogen bomb releases massive amount of energy. I'm baffled. Help me pls
@DrPhysicsA10 жыл бұрын
the two hydrogen atoms fuse and lose energy that is to say they give off energy. The energy they give off is positive energy leaving a negative binding energy which holds the helium together. You would have to put that much energy back in again if you wanted to break up helium nucleus.
@cadkls10 жыл бұрын
At least I understood the first 25 minutes.
@dhireshyadav17837 жыл бұрын
But isn't the lost mass obtained as heat or light energy?? The mass isn't actually lost and is conserved by the appearance of heat or light energy. Then why do we really need Binding energy for the energy-mass balance?? There is heat/light energy to balance it. Isn't it??
@DrPhysicsA7 жыл бұрын
The BE is the energy you'd have to put in to the system in order to get the individual nucleons out.
@mjl78104 жыл бұрын
Amazing
@seemaphadke1789 жыл бұрын
excellent
@outofturn10 жыл бұрын
thank you
@blub23232410 жыл бұрын
Or you could call it the Bethe-Weizsäcker formula ;)