best binomial theorem explain video ever, explain why use c(n,k),relationship with Pascal's triangle. love it
@grinishkin5 ай бұрын
4:00 So far, the most valuable note on the topic on KZbin
@leapdaniel80582 жыл бұрын
Very cool! Would love to see a video expanding to the concept of multinomials as well.
@angelmendez-rivera3512 жыл бұрын
Here is an addendum: the polynomial α·(α - 1)·(α - 2)·•••·(α - k + 1) actually has a special name: it is called the kth falling factorial of α. This is a kth degree polynomial on α, and the coefficients are known as the Stirling coefficients of the first kind. The binomial coefficient choose(α, k) is this equal to falling(α, k)/k!. This generalization of the binomial coefficient also appears not only as part of the binomial series, but it appears naturally in other contexts. For example, one idea may be to generalize higher-order derivatives to fractional order, and a Newton series, with this generalized binomial coefficient, can be used to explore this idea.
@PritishMishra2 жыл бұрын
Your visualisations are getting more and more intuitive to understand!
@DrTrefor2 жыл бұрын
Thank you!
@geraldsnodd2 жыл бұрын
0:37 The Sierpenski triangle 🔺️ is hidden inside Pascal's triangle . When I found out about it I was amazed.
@DrTrefor2 жыл бұрын
That's so cool, eh?!
@geraldsnodd2 жыл бұрын
@@DrTrefor Yes sir it is 🤓
@starlord2252 жыл бұрын
@@geraldsnodd You can also "collapse" iterations of Sierpinski's Triangle to get Pascal's Tetrahedron.
@geraldsnodd2 жыл бұрын
@@starlord225 how exactly?
@starlord2252 жыл бұрын
@@geraldsnodd The layers of Pascal's Tetrahedron are the coefficients of (x+y+z)^n. If you consider, for example (x+y+z)^2, you have x(x+y+z)+y(x+y+z)+z(x+y+z) =x^2+xy+xz+xy+y^2+yz+zx+zy+z^2 =x^2+2xy+2xz+y^2+2yz+z^2. The last line can be arranged geometrically in to a triangle of Pascal's tetrahedron, but the line before that essentially consist of three triangles one where x is first, one where y is first and one where z is first. If you consider the values (x,y,z) arranged in a triangle, you can visually multiply two of these triangles to get the terms above (e.g. x*(x,y,z) would be x^2+xy+xz). The nine terms of the product before you "combine like terms" can naturally be arranged into an iterate of Sierpinski's triangle. For example xx xy xz yx zx yy yz zy zz You get part of Pascal's tetrahedron by the commutative property: xy=yz, xz=zx, yz=zy x^2 2xy 2xz y^2 2yz z^2 Sorry if these diagrams don't look very clear by the way, they are difficult to type out in the comments section of a youtube video. So, each layer of Pascal's Tetrahedron could be considered as a commutative version of Sierpinski's Triangle. The idea is that multiplication of these diagrams behaves similarly to how Sierpinski's triangle iterates, you replace each thing in one diagram by a scaled copy of things in the other one.
@RealLoveDragon Жыл бұрын
Only man who can explain difficult concepts in minutes!!
@MelodiCat7532 жыл бұрын
Extreemly extremly cool generalization. I loved also the way you paired up the binomial expansion to make itobvious why it is n choose k. Wonderful work!
@aashsyed12772 жыл бұрын
Before seeing the whole title I was like this is gonna be multiminomial expansion , and it was not . But do that topic in another video please! The shirt is so cool !!
@DrTrefor2 жыл бұрын
I do want to go that direction too!
@jkgan4952 Жыл бұрын
I learnt so much in this video it's kinda crazy
@zaydmohammed68052 жыл бұрын
The timing of this video being released was awesome coz just today I was thinking about how newton calculated pi with the binomial expansion of (1+x) ^1/2 nd then realised that the formula for binomial theorem can't take 1/2 as an input so this cleared alot for me.
@DrTrefor2 жыл бұрын
Indeed, that's awesome!
@fyrerayne88822 жыл бұрын
Very helpful, thanks
@user-wu8yq1rb9t2 жыл бұрын
And ... 200k .... You almost done. Congratulations 👏🎉
@DrTrefor2 жыл бұрын
So close!
@dqrksun2 жыл бұрын
Amazing explaination 😍
@TrinityTwo2 жыл бұрын
The Binomial Theorem, along with the Fundamental Theorem of Algebra, has to be among the most important concepts in intermediate algebra.
@Xanade2 жыл бұрын
Did... did you just read my mind or something? These are the topics I've been working in four of my classes these weeks. They're advanced pre-SAT(well.. not in US, so sort of) classes, so I'm on binomial expansion and I always add the generalization with this exact notation of alpha choose k. haha
@DrTrefor2 жыл бұрын
nice!
@ivanyamasaki6612 жыл бұрын
nice!
@blobberberry2 жыл бұрын
nice!
@samsunnahar91752 жыл бұрын
Thanks a lot for excellent explanation!
@DrTrefor2 жыл бұрын
You are welcome!
@eriktempelman20972 жыл бұрын
Cool fact: in the triangle's prime numbered rows, all terms excerpt the 1's are multiplies of that row's prime numbers. E.g. row 5 is 1-5-10-10-5-1, and indeed, 5 and 10 are multiples of 5. Sweet.
@DrTrefor2 жыл бұрын
So cool!
@AlessandroZir10 ай бұрын
and what happens when I have values for which the Taylor series won't work? when x is not between 1 and -1?!
@minimath58822 жыл бұрын
that was awesome!
@Michael_Fischer2 жыл бұрын
0 choose x = sinc(x) - Replace ! with the Gammafunction and compare with Euler's reflection formula. 1 choose 1/2 = 4/pi
@SuperDeadparrot Жыл бұрын
How do you compute Pascal’s Triangle when N is large?
@albinbiju17002 ай бұрын
I didn't actually get why the series wouldn't work outside the interval -1
@forthrightgambitia10322 жыл бұрын
Hey, why are the bounds -1 < α < 1? Also if you extend this to x + c where c is some kind of constant, the result will just be the same just multiplied by c^(α-k) at each summand right?
@DrTrefor2 жыл бұрын
The easiest way to see this (bounds are for x not alpha), is to do a ratio test on the binomial series. And yes, shifts are totally fine:)
@abrahammekonnen2 жыл бұрын
Great video, and great sweater lol. A natural followup question would be can we generalize k to be any real number?
@angelmendez-rivera3512 жыл бұрын
There is some sort of generalization you can come up with, using the Gamma function, but it just is not anywhere near as elegant, nor is it useful, since you never encounter series where the series index runs over the real numbers.
@khamidullokh60562 жыл бұрын
Can you also make videos on series of functions, thanks in advance
@user-wu8yq1rb9t2 жыл бұрын
Great, as always. Thank you so much Professor. But ... *Eat. .. Sleep ... Physics and Math ... Now Repeat*
@DrTrefor2 жыл бұрын
haha i still love physics majors:D
@user-wu8yq1rb9t2 жыл бұрын
@@DrTrefor Please make videos about Physics too. Thank you 💗
@godfreypigott2 жыл бұрын
Doesn't the expansion for (1+x)^(-1) only converge for x in the interval (-1,1)?
@angelmendez-rivera3512 жыл бұрын
Correct, but this is not specific to exponent -1.
@godfreypigott2 жыл бұрын
@@angelmendez-rivera351 He presented that specific example.
@GeoffryGifari2 жыл бұрын
when you said (x+y)^π my first thought was to expand π in a series then do an infinite product lol
@bobtivnan2 жыл бұрын
I use the binomial theorem to prove the power rule for derivatives when the exponent is a nonnegative integer. But it seems like circular reasoning to then extend the power rule for real exponents to prove the binomial theorem for real exponents. I’m guessing there must be another way to prove the power rule over the reals.
@DrTrefor2 жыл бұрын
Main way is via induction
@gaboqv2 жыл бұрын
I feel ashamed about thinking you miswrote "sequence" as series cus i didn't remember an infinite sum related to the bn coeficient even tough I took a full semester of combinatorics some years ago... I must say the density of the pascal triangle as shown by Derek in one of his videos could have been a good adition
@dirceureis12 жыл бұрын
Awesome!!!!
@koenth23592 жыл бұрын
At times he speaks so fast, actuaIly checked my playing speed,
@sr.tarsaimsingh92942 жыл бұрын
Is there anyone ; Who is seeking for MULTINOMIAL THEOREM as well 🤨🤨..?? 🧐
@DrTrefor2 жыл бұрын
Haha that would have also been an awesome direction to go!