bro, you just came in real clutch for my final later today
@DrTrefor4 жыл бұрын
hey nice! Hope it went well:)
@alfredandens7911 Жыл бұрын
Thank you brother, the whole serie have helped me a lot.
@nat64293 жыл бұрын
This was really helpful and clear, thanks so much!
@michaelwinder78796 ай бұрын
You are a legend! These videos have carried me through my Calc 3 class
@utsavdesai34513 жыл бұрын
Really Helpful for finals next week!!!
@ManojKumar-cj7oj3 жыл бұрын
vocabulary 'flux' and 'circulation' makes the questions more interesting and simple
@张鑫-e9o2 жыл бұрын
The handwriting of z is a little bit confusing.
@softwarephil1709 Жыл бұрын
Yes. I thought some z were 2 (squared).
@tiomemo8958 Жыл бұрын
same here lol@@softwarephil1709
@TheDeluxeBacon4 жыл бұрын
Thank you for making these, I have my vector calculus final tomorrow lol
@DrTrefor4 жыл бұрын
Good luck!!
@dantepillon3 жыл бұрын
Hi this is a great video! But I was wondering when you were talking about the deformation theorem, that is; when divF = 0, any 2 closed boundaries share the same flux. What I cannot seem to get is, if divF = 0, should the total flux for any closed boundary also = 0??
@DrTrefor3 жыл бұрын
The total flux over all boundaries have to zero, any specific closed region might not be though
@dantepillon3 жыл бұрын
@@DrTrefor @Dr. Trefor Bazett thank you very much for replying sir, but I guess what I still don't get is, can you call any specific closed region its own region. And then apply the divergence theorem on that region alone to say it has 0 flux?
@firstlegend5105 Жыл бұрын
@@dantepillon You are correct that if divF = 0, the total flux for any closed boundary should be 0. In other words, the flux entering the boundary must be equal to the flux leaving the boundary. This is actually a consequence of the divergence theorem: if divF = 0, then the integral of F over any closed surface should be 0. The theorem should read: when divF = 0, any 2 closed boundaries share the same amount of flux and the total flux for any closed boundary is 0.
@chloemirisch8159 Жыл бұрын
Did you not take the partial derivatives correctly? I thought the partial derivative in respect to x,y,z would be . very confused as to why you added z to each of them.
@Brenticus12 Жыл бұрын
the field equation is (xyz, xyz, xyz) not (xy^2, xy^2, xyz)
@rodaneblackwood10793 жыл бұрын
Thanks!
@j.o.59573 жыл бұрын
Nice, good stuff. Question to self: how do I solve this using standard flux calculations? I frankly don't know, don't think I've been through that. Should look into it later.
@leondavidpedraza86182 жыл бұрын
What happened with the x that comes out of the first integration? I am sorry, I missed it, it was too fast for me to be too slow! thanks.
@im_KiraL3 жыл бұрын
How did you get yz+xz+xy from this F
@CaseyKlein Жыл бұрын
Thank you!!
@ShubhamPatel-gx7pb4 жыл бұрын
If F= yz i + zx j + xy k and S is the part of the surface of the sphere x^2 + y^2 + z^2 = 1 , which lies in first octant , the the value of double integral F•n ds is Sir why we can't use Divergence theorem in this question?
@DrTrefor3 жыл бұрын
Divergence theorem ONLY applies to a closed surface, not part of one.
@ShubhamPatel-gx7pb3 жыл бұрын
@@DrTrefor Thank you Sir
@carultch Жыл бұрын
@@ShubhamPatel-gx7pb You can often use the divergence theorem as a shortcut to evaluate the flux over a surface that isn't closed, when symmetry works in your favor. Like if it is easier to find the flux over a closed surface using the divergence theorem, and the open surface in question is just one octant of 8 identical octants, that would form a closed surface if you connected them.
@aashsyed12773 жыл бұрын
What is flux core welding and fabrication near me a lot of
@carultch Жыл бұрын
It's an unrelated meaning of the word flux.
@swayamkumarpatro7764 жыл бұрын
Sir, can you please attach a list of problems which are very important in this vector calculus course ?
@emilykang4354 Жыл бұрын
Thank you for such a clear statement
@brianofarrell19774 жыл бұрын
F*** me, my final was yesterday... never understood the concept and now i do!