ISRO- Technical Assistant Electronics-Previous Year Questions 2018 part2

[@KUMARA-mt3yu]

Thank u mam for very useful videos

[@vikas9890]

Thanks a lot mam. Very useful video

[@nethravathi1573]

Thank you so much for this video 🙂

[@gopikadusu6049]

Nice mam..

[@gopikadusu6049]

Thank you very much

[@geethanjalir2301]

Tk u mam

[@EasyElectronics_jobupdates]

Please share and Subscribe if Useful

[@sowmyapc2431]

👍

[@TECHTONICSTAMIL]

Hi mam How this 1000+2*445+10^3=1910 KHZ please reply

[@manik2676]

Mem in CMRR u total 20log instead of 10log...plz reply.

[@EasyElectronics_jobupdates]

Yes, it is 20 log. But where have I applied CMRR equation in this video.

[@manik2676]

@@EasyElectronics_jobupdates in one other videos..u told to find CMRR to dB take 20log ....but in this video to find in dB u take 10 log...so

[@manik2676]

Mem..to find CMRR in dB we should take 20log. N to find power in dB we should take 10log.. Is it correct?

[@EasyElectronics_jobupdates]

@@manik2676 yes, here in the question have they given that we are using a opam, no right. So simply take 10 log. That is the equation to convert power to db.

[@manik2676]

@@EasyElectronics_jobupdates thanks mem..

[@authenhicseries2530]

Maim apse request hai ek 3 to 8 decoder ka question hai vssc isro technical Assistance electronic 2018 series A ka question no 21 hai.... Pls uska solution provide kr dijiye usme samjh me nhi a rha

[@EasyElectronics_jobupdates]

I will see

[@authenhicseries2530]

@@EasyElectronics_jobupdates pls maim explain that question 🙏

[@EasyElectronics_jobupdates]

Please send me the Question I can't find the Question paper now. Please send to mail I'd [e-mail]

[@authenhicseries2530]

@@EasyElectronics_jobupdates forward kr diye maim

[@authenhicseries2530]

@@EasyElectronics_jobupdates maim apne short me bta diya hai but samjh nhi a rha screen shot de dijiye na pls