Data Transfer Instructions in 8086 Microprocessor - Instruction Set of 8086 Microprocessor

[@Ekeeda]

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[@RituKumari-bv6ip]

SP will be pointing to the latest data in the stack, in case of push, SP will be decremented by one and first data will be put at that location, once again SP will be decremented by one and next data will be copied to that location and SP will be pointing to that location. In case of POP, first data will be copied from the top of stack and SP will be incremented by one, once again second data will be copied and SP will be incremented by one so that SP will be pointing to the top of the stack

[@gratkg6562]

nice tutorial

[@addisunigatu1451]

why u use Ds in XCGH? can we use other segment registers?

[@HemantKumar-pq9hw]

PUSH and POP is wrong mam

[@kawsarmaxamed9228]

Norevy nice

[@sudharshandiv]

U can explain total 13 instructions plz

[@fardeenkhan7978]

Nice

[@bhanu2161]

v v nice

[@RituKumari-bv6ip]

push and pop explanation is wrong

[@sumithraba9610]

Why we have to multiply 10h for stack segment

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[@rupok3393]

physical address has to be 20 bit , we use 16 bit IP address and 16 bit segment address to calculate 20 bit physical address.so, we left shift segemt address and right shift physical adress to make 20 bit address.For example: Base Data segment address = 7400H .....left shift address = 74000H or (7400H * 10) Instruction pointer Adress = 2000H......right shift address = 02000H physical Address = 74000H + 02000H = 76000H

[@magyx7605]

@@Ekeeda shut up

[@avinandanpal9742]

How can there be 255 different ports from 000 to FFF

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[@avinandanpal9742]

@@Ekeeda Sorry, but I'm not asking for any doubt, I'm pointing out the mistake

[@SnehilopGaming]

@Avinandan Pal lol

[@SnehilopGaming]

@@avinandanpal9742 mistake se zyada dhandha zaroori hai bhai

[@anjuchauhantechnical3458]

Pls explain in hindi