Electric Charge And Field - Important PYQs | Physics | Class 12th Boards 🔥

[@NCERTWallahPW]

FREE Class 12 PYQs: bit.ly/4jeY5V5 Telegram Link 🔗: t.me/pwncertwallah

[@Twilight_sakshi_queen]

1:40:27 E = 10^5 N/C Torque = 8√3 Nm 2l = 2 × 10^-2 m Angle = 60° q = ? As we know Torque = PEsin theta Torque = 2ql × E sin theta q = Torque / 2l E sin theta On putting all the values , we get q = 8 × 10^-3 C or 8mC 💯

[@DeepBrothers01]

Vote for physical education in this series' 😢😢😢😢

[@Mithu1401]

No class for physical...Joa kahi aur se padho...chup chap rho

[@DeepBrothers01]

@Mithu1401 why

[@Mithu1401]

@@DeepBrothers01 abe bhai Is pe saare bacho ko Physics , chemistry aur Maths ki padi hai...Isiliye Jyadatar bache Physical Education One day before exam padhte hain....Mai bhi unme se ek hu...Even Batch me bhi padha diya gya hai... Isiliye PE ki no classes...YT se padhna hai To there's many channel jao study karo mast raho..Spamming karne se koi fayda nhi hai brooooo

[@krishnapal7380]

Ap pedia channel sai padhlo

[@riyakumari371]

Thank you sir, hope all lakshyan's and other students get above 95%in board 👍👍👍👍👍 best of luck

[@Twilight_sakshi_queen]

1:39:50 horizontal force acting on Bob = qE F1 = 2 × 10^-8 × 20000 F1 = 4 × 10^-4 N vertical force acting on Bob = mg F2 = 30 × 10^-6 × 10 F2 = 3 × 10^-4 N Tension in the thread will be √ F1^2 + F2^2 F = √ 25 × 10^-8 F = 5 × 10^-4 N 💯

[@Twilight_sakshi_queen]

1:40:37 E1 = 50 i E2 = 100 i Theta 1 = 180° Theta 2 = 0° Total flux = E1dscos180° + E2dscos0° = -1/2 + 1 = 1/2 Total flux = 0.5 Nm^2/C💯 Total charge (q) = flux × epsilon not q = 4.425 × 10^-12 C 💯

[@Twilight_sakshi_queen]

1:42:19 E = 1000 V/m q = 10^-12 C Distance between dipole = ✓3^2 + 4^2 = 5 mm = 5 × 10^-3 m sin theta = P / H = 4/5 Torque = PE sin theta Putting all the values Torque = 4 × 10^-13 Nm 💯

[@Twilight_sakshi_queen]

1:39:24 electric dipole is first placed parallel to electric field , it means angle between dipole and electric field is 0° . Then , it is rotated to 180° . Then workdone in rotating it to 180° = PE (cos theta 1 - cos theta 2 ) = PE ( cos 0° - cos 180° ) = PE [ 1 - (-1) Workdone = 2PE 💯

[@Twilight_sakshi_queen]

1:40:00 Here in this question 64 small drops each of charge q constitute to form a larger drop of charge Q Q = 64q To get the ratio of surface charge density we must find the radius of larger drop to get area of larger drop . As we know , volume will be same for total 64 smaller drops and larger drop So, 64 × 4/3 × π r^3 = 4/3 × π R^3 From here we get ,( R = 4r ) Charge density of smaller drop = q / 4πr^2 Charge density of larger drop = 64q / 4 π (4r)^2 Ratio of charge density of smaller drop to charge density of larger drop = 1:4 💯

[@Twilight_sakshi_queen]

1:39:12 The product of one of the two charges of equal and opposite magnitude and distance between them is called dipole moment . DIPOLE MOMENT IS A VECTORE QUANTITY . Direction is from -ve to +ve charge. It's SI unit is Cm 🔥

[@Twilight_sakshi_queen]

1:38:56 Pattern of ELECTRIC FIELD LINES WILL BE FROM +VE SIDE OF PLATE TOWARDS NEGATIVE CHARGE 🎀

[@Twilight_sakshi_queen]

1:38:43 (A) E = Kq/x^2 (B) E' = Q+q / 4πE0(x')^2

[@Twilight_sakshi_queen]

1:39:04 SOLUTION:- 🔥 Firstly , the two conducting balls are brought in contact so the total charge will be [ -Q + 3Q = 2Q ] and after separation, the charge will be equally distributed so , charge on each ball will be [ 2Q/2 = Q ]. After having same charge they both will repel each other so the force acting between them will be repulsive 💯

[@Storyyy_teller]

45:56 nhii sir ye dikkat ni h ... Dikat h tension hi ni hooo rhi mn hi ni kr rha padne ka... Pta h kuch nhi kiya pure saal lakin padha hi ni ja rha... Ki jo hogi deki jayegi💀... Or jb aap kaam ko be mn krte ho na tho 3× time lgta h me experience se bta rha

[@ArtiGupta-sv5cd]

Sir 2.5 hr pyqs sessions liya kro 100 que per chapter

[@anishraj884]

Par bhai kaha se padhe

[@Cheeku098]

@anishraj884 zaki saudagar is the best one shots, just do it, do PYQs and NCERT

[@Steve-sp4]

Sir bohot mast class tha numerical toh numerical ab toh derivation me bhi confidence aa rha h 😊😊😊😊😊

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@PranjalGaur-m2q]

crystal clear sir, you are the best physics teacher ♥♥

[@Cricketknowledge992]

Best lecture and quality numericals thank you sir 🩷💝

[@Nanshiivibes]

Very useful video sir.. Thank you sir ❤

[@Moonlight_X_30]

Done sir 👍

[@RambirDalalRambirDalal]

Thank you sir ❤❤✨️✨️ Questions kar ke maja aa gaya ❤❤ Enough for the boards ❤❤all types of question is here ❤❤ in this session 🎉🎉 Your At ❤❤🎉🎉

[@velvet.vogu3]

can i watch this if i’m not able to solve numericals? will this video be helpful for me? pls reply

[@Kyujiro_Rengoku155]

Bhai haan approach krna tob aayega!

[@Kyujiro_Rengoku155]

Merko bhi nhi hote and then phir khud se lgaio teh question kuch dino baad and revise krte rho

[@velvet.vogu3]

@@Kyujiro_Rengoku155 time hi nahi hai bro kuch din ka ab.. boards hain bs agle mahine.. saare subjects dekhne hain

[@Kyujiro_Rengoku155]

@@velvet.vogu3 are jaise tumne aaj dekha lec and fir 2 din baad dekho question ho jayega yaar and revise krte kro 2,4 din ke gaap me utna time hai and hojayega

[@velvet.vogu3]

@@Kyujiro_Rengoku155 okk

[@Kumkum_Baghel_46]

Sir really in questions sa concept bhi clear ho rha hn... Thanku so much sir 🩷... And I am your AT ❤❤❤❤

[@ChetanBhati-s2z]

AT bhaiya op ❤❤❤❤❤ 💗💗💗💗💗

[@kushagragarg766]

Completed 🏆🏆

[@Radheedeepak]

Thanks sir ❤

[@coregamerlusifer7632]

47:40 A ans

[@TheChosenOnes-j7i]

Kase ?

[@Subh9800]

wonderful lecture ❤

[@TasneemKhan-h7q]

UP board walo ke liye bi h ye q ki isme zyada que to cbse ke hi h.. Plzz tell me

[@YoutubefunYoutubechannel]

12:50 sir ye explanation samajh nhi aaya 🔴🔴❗️❗️

[@SunnyMourya-b3g]

Requirements - (1)time stamp -(2) continue series 😊😊😊

[@Omprakash-r2d4u]

Thank u sir for this amazing class ☺️☺️😄☺️❤❤❤❤❤🎉🎉🎉🎉🎉

[@RishavSrivastava-e4r]

Sir in question 19 why we haven't use the formula of axial Enet=2kp÷r^3??

[@ManojKumar-nd3go]

Vo formula r>>>>l ke liye use hota h

[@BhaiPadhle-yn5ey]

12:50 Sir Q3 ka solution aapne galat kiya h answer to 2/5 hi h par tarika shayad galat h Wo simple (4Q/E•)/(10Q/E•) = 2/5 ata

[@adityarawat_]

Mai bhi wahi soch raha 2nd step tak hi tha wo 6 se divide kyu kiya hame To pure ek cube se batana hai naki uski ek side se ?

[@BhaiPadhle-yn5ey]

@adityarawat_ exactly

[@Miswah123]

47:44 ( A )ans

[@TheChosenOnes-j7i]

Kase ?

[@Mantasha-k7q]

thanks sir numericals m confident aa rha h thanks sir your efforts love you sir ji 💞🥹

[@rajdabano199]

Sir state board ke liya padh sakte hai???

[@diyakanwal6138]

Thank you sooo much sir lecture waa soo helpful

[@zahidahusain1807]

THANKU SO MCH SIR❤💓

[@akankshasingh1010]

SSS army attendance here😅😅

[@anshikakushwaha1067]

Sss🎉

[@Trendy_x-h6w]

13:37 ans 2/3😢

[@classxstudymodeon2450]

Cuet ka foem kb ata hai kii bata skta hai pls ❤

[@सनातन-ण2ग]

Google kar Lo

[@zahidahusain1807]

SIR APKI WJH SE CONFIDENCE AAYA...❤💞

[@Tanu_Ojha_0001]

Iska time table channel pr h ??? Ki next ch kb ayega ??

[@dream.comes-true601]

Sir ,Please kindly bring pyg videos of all subjects like this

[@yadavbhai6845]

Jac board ke liye enough h ki nhi sir

[@SIMRANPREET-b9z]

Ivv u the most 💜✨

[@sumitdalal-w9h]

SSS AND AT OP♥♥

[@adnanahadshah]

Nice ❤❤❤❤

[@jaiswal-le8jh]

sss kyu nahi la raha ya pyqs series 😢😢😢😢😢

[@RaghavOjha-q6e]

🔥🔥🔥

[@lalityadav-kw5vd]

sir question no. 17 me 0.2 nahi hoga 1.8 hoga please tell me sir

[@mamtarajbhar4471]

Sir CLASS 6 ampe shuru hoti to jyada accha hota School jaana hota Hain

[@iblamerabeek]

6pm par vijeta ke saath clash kar jayegi

[@Kartik-s5k9j]

All the best for boards 12 class 👍

[@akgupta27]

sir please computer wala bacho ka liya bhi class schledule kar dijiya [computer science with python} 🙏🙏🙏 please sir

[@onestep_71]

KIS KIS NE CUET KI PREPARATION KAR RAHA HAI AUR KABSE ?

[@studyguru2939]

Dusro se kyu puch rhe ho khud pe focus kro

[@bharat-steyn18]

+1​@studyguru2939

[@harshitu_]

Ho sake to pehle wala msg like kar dena sir ❤❤

[@Bluebereyezz]

Any student from board booster batch?

[@AdityaRaj-yq6ws]

Sir chapter 2nd ka banao ab

[@user18652]

Notes kaha se milege fir ye bala

[@Jyotiraditya7s]

Jab patni ki baithak mein maja nahin aaya

[@FREESTYLEVIDEOOFFICIAL]

❤

[@ANSH_66]

D

[@HimanshuSahu-e6q]

Thank you sir mai imandari se aap jo kahogewo karuga merese hopayega utna karugga 😢😢😢

[@KrishnaThakur-jg1qo]

B

[@abdulmoiz1403]

why no ISC boards pyqs?

[@Vaibhav__mishra_18]

Numerical ke lecture dalo na sar

[@RAJRAM-j8i]

😎

[@HeBLo07]

sir your AT army"s commander is here😁

[@alishawahid1618]

Sir state board Wale kar skte hai ?

[@s143ff3]

Lakshay JEE 🙌🏻

[@pawanbawankar5772]

Bhai paper kab hai

[@PampiKumari-j6c]

Hii

[@shashikantsharma7965]

Please class ko 9 bje start kijiye vote for 9 o clock

[@kaur6091]

Kal kisski class hai??

[@nitinmourya3740]

Ray optics

[@kaur6091]

@nitinmourya3740 ok thnx😊

[@Abhishek-ri2sy]

Sahi saa nahi dhik raha haa bluur saa figure aa raha hai

[@shubhijaiswal875]

Sir serial wise karao na pyq series ab seedha optics kyu rkh diya

[@ShreyaKatiyar-x7w]

High weightage ke according revision kra rha h👍🏻😌

[@shubhijaiswal875]

@ShreyaKatiyar-x7w still bhyi flow toot jaega... Infact Vijeta me oneshot b nhi cover hoga 17 tk

[@ShreyaKatiyar-x7w]

@@shubhijaiswal875 last year ki joh vijeta series h ussa last ke chapters complete krlo last year bhi bilkul same syllabus tha issa jldi bhi hoga high Weitage bhi complete

[@amenov7734]

Jee wale attendance

[@Bhavana_pandey-f4t]

Mast lecture tha sir. Thanks sir 😊😊😊

[@kaelishmaurya]

Thankyou sir.♥️

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@Manvi-Singhzpqm]

Thankyou sir 😢❤😊

[@Prash08.]

❤❤

[@VishalTripathi-ue1bj]

D

[@AshuSharma-xo4nj]

hii

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@UshaDevi-j5w9q]

Thanku so much sir ☺️

[@sunilpandey3101]

❤❤❤❤

[@AshuSharma-xo4nj]

hii

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@Subh9800]

thankyou sir ji ❤❤❤

[@adityadubey2174]

Thank you sir ❤

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤

[@UneekBoy000b]

Sir please ye series continue rakhna ❤❤❤❤