Electric Field Cases | Class 12

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[@birmanikumar]

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[@lucifer8257]

Sir please finish this onion physics class 12 part before jee main 2023 1st attempt

[@MomoLuMo]

Yes sir pls

[@raunakrajput8387]

Yess sir

[@Same_think..you_me]

Yes sir

[@SanjeevKumar_024]

Yes

[@pacepoetic]

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[@simapaul197]

this series of physics is just like gem...very much helpful

[@mb59621]

Jaise jaise onion ki layers hum kholte hai , students ke aankhon se ansu behta hai .

[@rajkadam6618]

AT 21:00 as we come closer to hemisphere the valve of e decreses because if we consider a elemental ring on the hemisphere small de will formula will be of ring we can apply that

[@satyamsangle9316]

It can also be analyse vectorially

[@theelectricbulb4928]

This is a unbelievable series😎😎😎

[@Gazishahchak]

Most practical guy in jee field

[@tanujabudhori]

15:30. Sir, Why point will perform SHM. Net force on point due to rod is actualy not directly proportional to linear variable of displacement

[@Shine.for.creator]

Again watch this

[@shubhamsrivastava48]

Thank you ❤️ so much sir for this Series 😊

[@AdityaSingh-ze6oo]

At 21:00 electric field will decrease as we go down and the field is given by :- E = (s/4p)(R^2/R^2+x^2) where s-surface charge density p-permittivity of free space and x-distance from the centre of hemispherical cup in downward direction. Therefore the point charge will be in unstable equilibrium.

[@pratiksingh4867]

Thankyou sir for your hardwork 🙏🙏🙏🙏🙏🙏

[@umangsarraf7013]

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[@madhujyarajkhowa1529]

At 21:06 if we displace the charge by x downward then force will decrease and the new force will become qé/4E (R^2/R^2+x^2) . here é is surface charge density and E is permittivity of free space and R is radius of hemisphere...

[@madhujyarajkhowa1529]

@Kartik Tripathi kese Kiya that or sahi Kon hai

[@madhujyarajkhowa1529]

@Kartik Tripathi or ek Dekho If x=0 then should be qé/4(E..)

[@harshgour405]

​@@madhujyarajkhowa1529i guess you are right because i also came up with same answer

[@annapurnasarangi9999]

Hey, guys, I feel ki here we can use the solid angle concept, and find out result.. tan inverse se planar angle mil jaega, and using solid angle, we can find the field produced by that point charge, from Newton's 3rd law, the amt of field away from charge equals the field towards the charge.. hence as we go low, the magnitude of field decreases, to a point and becomes 0 and then again starts to increase and becomes equal to field acting on a particle on the surface of the hemisphere

[@mjrquadri6317]

Sir please complete the onion physics series for class 12 🙏

[@patelnandan_]

Koi hai mere jaisa jiska onion physics se besic hil gya ❤️ Sir please finish before jee 2023

[@engineerfauji8431]

Thankyou sir Jai shree Ram 🚩🙏

[@tanavposwal]

Best timing for revision

[@arpangoswami2124]

21:12 Field Remains same I feel. Please Disclose the Answer.

[@sureshwarrier1086]

21:12 Field will decrease

[@singhaniya_08]

Thank you sir🩵

[@dr.norespect9149]

AA sir is back !

[@AM-vy4kc]

Agr elemental ring consider krenge to ring k case m center pr electric field zero hota hai aur infinity pr bhi zero hota hai aur beech m kahi maximum hota hai... To usi trh is elemental ring k liye bhi koi aisa point hoga jaha field maximum hoga aur uske baad field decrease hoga... Mere khyal se field kahi beech m maximum hoga aur fir decrease hoga.. Saath m ye bhi lg rha hai ki electric field = sigma/4 €• hai jo ki constant hai to field hr jagh constant hi hoga jaise previous case m electric field due to sheet tha... Sir please discuss this i m very confused. Clarity nhi mil rhi ki exactly electric field kya hoga?? Please sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@hrushikeshjadhav2937]

Sir when will the next lecture of electrostatic (onion physics) is coming?

[@jeedrago]

SI 0:06 Sir please If you continue a onion physics lecture it helpful for 2024

[@rstkuldeepofficial4052]

Very good explanation sir

[@rajaryan904]

Sir meri physics bhut weak h or m neet ka aspirant hu sir only onion physics se neet k liye cover ho jayega ya nhi

[@vasu_navdeep]

one boon you can give to us by completing 12 major topics by the 1st attempt of jee mains

[@programmeraman]

More and advance content in less time that's Ashish sir

[@NEWtom_lite]

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[@Rishav_Kaushal5761]

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[@birmanikumar]

Absolutely ❤️

[@gamingandtechhub351]

there would be point of equilibrium when charge is inside the cup at some x , gravity diregarded

[@aarya8542]

thanks sir

[@ayushsahu6632]

Sir it will decrease as component of Fields will come in act opposite to it

[@MomoLuMo]

Thanku

[@MomoLuMo]

U r god sir

[@rohn1693]

Thxu so much sir

[@vamshivarsha7611]

sir pls make vedios on josaa counselling 2022

[@greeperk9s]

Am I supposed to makes notes. Or is there any PDF

[@omchauhan6145]

Pdf

[@yuvrajrawat8746]

Sir when we displace the q by certain distance x the small q will experience more repulsion by the existing charges and the mag of E will increase and hence FORCE WHEN DISPLACED BELOW THE SURFACE>F ON THE SURFACE I HOPE ITS CORRECT... AND SIR E = Q/4Aapsilonnot so as x decreses mag of E inc while on a vertical motion upwards x dec and E increases....

[@Yaara_1]

Bhai mathematical derivation kari hai toh eoh bhi btade 🙏

[@advarbindkumar5791]

E=k σ π[1-cos2(taninv(R/x))]/2 Where E is electric field

[@Yaara_1]

@@advarbindkumar5791 Thanks!

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[@pg_64_03]

@@meerasharma19 nahi nahi usko ulta latak kr lecture dekhna chaiye then he will surely able to catch the concepts

[@aalphadw]

Thanks Sir

[@integration_IIT_ISM]

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[@Naachu1111]

Aree ur classes are very understanding... But plz upload videos in english. It will help many students from different states

[@Naachu1111]

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[@jeeaccountkedharsaiganesh6532]

I am From AP and I also feel the same.... But We Have to Adapt to the situation Bro...

[@Pogi_saxual]

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Thanks

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[@Hopeless_i_am]

💯

[@sksingh20055]

1st like and view sir

[@tilottamaroul9674]

Doesn't matter

[@pranavjangan9822]

💓

[@akki3535]

21:12 field will remain same

[@prathammathura]

no it will decrease/ btw what rank you got in jee 2023pls tell.

[@JACK-ho6cj]

Decrease hoga

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500 likes ✅

[@AnkitKumar-uh2sl]

Neet aspirent

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Only hindi...speak English sir....

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The all concepts of jee main in only onoion physics